Which is the prime factorisation of 8820?
Step 1: Write (8820=180\times49). Step 2: (180=2^2\times3^2\times5) and (49=7^2), so (8820=2^2\times3^2\times5\times7^2). Step 3: Convert 180 and 49 into prime powers.
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SubjectsMathematics
अभाज्य गुणनखंडन
In Class 10 Mathematics, under the Real Numbers chapter, Prime Factorisation teaches students to express a composite number as a product of prime numbers. Students practise identifying prime factors and writing factorisations using multiplication and exponents. This foundational skill supports the Fundamental Theorem of Arithmetic and later work with HCF and LCM.
TOPIC PRACTICE
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Step 1: Write (8820=180\times49). Step 2: (180=2^2\times3^2\times5) and (49=7^2), so (8820=2^2\times3^2\times5\times7^2). Step 3: Convert 180 and 49 into prime powers.
View question detailsStep 1: Write (9800=8\times1225). Step 2: (8=2^3) and (1225=5^2\times7^2), so (9800=2^3\times5^2\times7^2). Step 3: Do not leave 1225 in the final form.
View question detailsStep 1: Write (10368=128\times81). Step 2: (128=2^7) and (81=3^4), so (10368=2^7\times3^4). Step 3: Write both 128 and 81 as prime powers.
View question detailsStep 1: Write (12320=32\times385). Step 2: (32=2^5) and (385=5\times7\times11), so (12320=2^5\times5\times7\times11). Step 3: Give 385 its complete prime form.
View question detailsStep 1: Write (13230=270\times49). Step 2: (270=2\times3^3\times5) and (49=7^2), so (13230=2\times3^3\times5\times7^2). Step 3: Do not keep 270 and 49 in the final form.
View question detailsStep 1: Write (14700=300\times49). Step 2: (300=2^2\times3\times5^2) and (49=7^2), so (14700=2^2\times3\times5^2\times7^2). Step 3: Convert 300 into prime powers.
View question detailsStep 1: Write (15840=32\times495). Step 2: (32=2^5) and (495=3^2\times5\times11), so (15840=2^5\times3^2\times5\times11). Step 3: Give 495 its complete prime form.
View question detailsStep 1: Write (17640=8\times2205). Step 2: (2205=3^2\times5\times7^2), so (17640=2^3\times3^2\times5\times7^2). Step 3: Give 2205 its complete prime form.
View question detailsStep 1: Write (20736=256\times81). Step 2: (256=2^8) and (81=3^4), so (20736=2^8\times3^4). Step 3: Convert 256 and 81 into prime powers.
View question detailsStep 1: Write (22050=450\times49). Step 2: (450=2\times3^2\times5^2) and (49=7^2), so (22050=2\times3^2\times5^2\times7^2). Step 3: Give 450 its complete prime form.
View question detailsStep 1: Write (27720=8\times3465). Step 2: (3465=3^2\times5\times7\times11), so (27720=2^3\times3^2\times5\times7\times11). Step 3: Give 3465 its complete prime form.
View question detailsStep 1: (15840=32\times495). Step 2: (32=2^5) and (495=3^2\times5\times11), so the power of 2 is 5. Step 3: Comparing gives (a=5).
View question detailsStep 1: Write (22050=450\times49). Step 2: (450=2\times3^2\times5^2) and (49=7^2), so the power of 3 is 2. Step 3: Comparing with the given form gives (b=2).
View question detailsStep 1: (20736) can be written as (256\times81). Step 2: (256=2^8) and (81=3^4), so (20736=2^8\times3^4). Step 3: Comparing gives (m=8).
View question detailsStep 1: For distinct prime factors, exponents are not added. Step 2: The bases are 2, 3, 5, 7, and 11. Step 3: Therefore, there are 5 distinct prime factors.
View question detailsStep 1: Calculate (2^3=8) and (3^3=27). Step 2: (8\times27\times11=2376). Step 3: Finding powers first is the correct method.
View question detailsStep 1: Calculate (3^2=9). Step 2: (9\times5\times7\times11=3465). Step 3: When there are many factors, multiply in pairs.
View question detailsStep 1: Calculate (2^4=16) and (3^2=9). Step 2: (16\times9\times5\times7=5040). Step 3: First do (16\times9=144), then multiply the rest.
View question detailsStep 1: Calculate (2^2=4), (3^3=27), and (7^2=49). Step 2: (4\times27\times49=5292). Step 3: Simplify all three powers separately.
View question detailsStep 1: Calculate (2^7=128) and (3^4=81). Step 2: (128\times81=10368). Step 3: Solving large powers first reduces mistakes.
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