Concept-wise Practice

repeated_root MCQ Questions for Class 10

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Practice Questions

34 questions tagged with repeated_root.

Question 31/34 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 32

समीकरण \(x^2-8x+16=0\) का दोहराया हुआ मूल क्या है?

What is the repeated root of \(x^2-8x+16=0\)?

Explanation opens after your attempt
Correct Answer

A. (4)

Step 1

Concept

(x-2-8x+16=(x-4)2). Therefore the repeated root is (4).

Step 2

Why this answer is correct

The correct answer is A. (4). (x-2-8x+16=(x-4)2). Therefore the repeated root is (4).

Step 3

Exam Tip

(x-2-8x+16=(x-4)2) है। इसलिए दोहराया हुआ मूल (4) है।

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Question 32/34 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(x^2-10x+25=0\) का मूल कौन सा है?

Which is the root of \(x^2-10x+25=0\)?

Explanation opens after your attempt
Correct Answer

B. (5) दो बार(5) twice

Step 1

Concept

(x-2-10x+25=(x-5)2) so the repeated root is (5). Recognising a perfect square saves time.

Step 2

Why this answer is correct

The correct answer is B. (5) दो बार / (5) twice. (x-2-10x+25=(x-5)2) so the repeated root is (5). Recognising a perfect square saves time.

Step 3

Exam Tip

(x-2-10x+25=(x-5)2) इसलिए दोहराया मूल (5) है। पूर्ण वर्ग पहचानना समय बचाता है।

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Question 33/34 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(x^2+6x+9=0\) के मूल कौन से हैं?

What are the roots of \(x^2+6x+9=0\)?

Explanation opens after your attempt
Correct Answer

B. (-3) और (-3)(-3) and (-3)

Step 1

Concept

(x-2+6x+9=(x+3)2) so both roots are (-3). In a perfect square the root sign is opposite.

Step 2

Why this answer is correct

The correct answer is B. (-3) और (-3) / (-3) and (-3). (x-2+6x+9=(x+3)2) so both roots are (-3). In a perfect square the root sign is opposite.

Step 3

Exam Tip

(x-2+6x+9=(x+3)2) इसलिए दोनों मूल (-3) हैं। पूर्ण वर्ग में मूल का चिन्ह उल्टा होता है।

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Question 34/34 Easy Mathematics Quadratic Equations Roots of a Quadratic Equation Class 10 Level 31

समीकरण \(x^2+2x+1=0\) का दोहराया हुआ मूल क्या है?

What is the repeated root of \(x^2+2x+1=0\)?

Explanation opens after your attempt
Correct Answer

B. (-1)

Step 1

Concept

(x-2+2x+1=(x+1)2) so the repeated root is (-1). Recognising a perfect square is useful.

Step 2

Why this answer is correct

The correct answer is B. (-1). (x-2+2x+1=(x+1)2) so the repeated root is (-1). Recognising a perfect square is useful.

Step 3

Exam Tip

(x-2+2x+1=(x+1)2) इसलिए दोहराया मूल (-1) है। पूर्ण वर्ग को पहचानना उपयोगी है।

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