समीकरण \(x^2-8x+16=0\) का दोहराया हुआ मूल क्या है?
What is the repeated root of \(x^2-8x+16=0\)?
Explanation opens after your attempt
A. (4)
Concept
(x-2-8x+16=(x-4)2). Therefore the repeated root is (4).
Why this answer is correct
The correct answer is A. (4). (x-2-8x+16=(x-4)2). Therefore the repeated root is (4).
Exam Tip
(x-2-8x+16=(x-4)2) है। इसलिए दोहराया हुआ मूल (4) है।
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