यदि \(x=2+\sqrt{3}\) है तो कौन सा समीकरण सत्य है?
If \(x=2+\sqrt{3}\), which equation is true?
Explanation opens after your attempt
Correct Answer
A. \(x^2-4x+1=0\)
Concept
The conjugate is \(2-\sqrt{3}\), with sum (4) and product (1). Hence the equation is \(x^2-4x+1=0\).
Why this answer is correct
The correct answer is A. \(x^2-4x+1=0\). The conjugate is \(2-\sqrt{3}\), with sum (4) and product (1). Hence the equation is \(x^2-4x+1=0\).
Exam Tip
(x) का संयुग्मी \(2-\sqrt{3}\) है और योग (4), गुणनफल (1) है। इसलिए समीकरण \(x^2-4x+1=0\) है।
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