Concept-wise Practice

evaluate-factorisation MCQ Questions for Class 10

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143 questions tagged with evaluate-factorisation.

Question 91/143 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^4\times3\) है, तो वह संख्या कौन सी है?

If the prime factorisation of a number is \(2^4\times3\), which number is it?

Explanation opens after your attempt
Correct Answer

A. 48

Step 1

Concept

Calculate \(2^4=16\).

Step 2

Why this answer is correct

\(16\times3=48\).

Step 3

Exam Tip

It is easier to find the value of prime powers first. चरण 1: \(2^4=16\) निकालें। चरण 2: \(16\times3=48\)। चरण 3: अभाज्य घात का मान पहले निकालना आसान रहता है।

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Question 92/143 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

किस संख्या का अभाज्य गुणनखंडन \(3\times5^2\) है?

Which number has prime factorisation \(3\times5^2\)?

Explanation opens after your attempt
Correct Answer

A. 75

Step 1

Concept

Calculate \(5^2=25\).

Step 2

Why this answer is correct

\(3\times25=75\).

Step 3

Exam Tip

Simplify the power first and then multiply. चरण 1: \(5^2=25\) निकालें। चरण 2: \(3\times25=75\)। चरण 3: घात को पहले सरल करें, फिर गुणा करें।

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Question 93/143 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

किस संख्या का अभाज्य गुणनखंडन \(2\times3\times7\) है?

Which number has prime factorisation \(2\times3\times7\)?

Explanation opens after your attempt
Correct Answer

A. 42

Step 1

Concept

The prime factors are given.

Step 2

Why this answer is correct

\(2\times3\times7=42\).

Step 3

Exam Tip

When no power is written, each prime is taken once. चरण 1: अभाज्य गुणनखंड दिए गए हैं। चरण 2: \(2\times3\times7=42\)। चरण 3: जब घात न हो तो प्रत्येक अभाज्य एक बार लिया जाता है।

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Question 94/143 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

यदि किसी संख्या का अभाज्य गुणनखंडन \(2\times5^2\) है, तो वह संख्या कौन सी है?

If the prime factorisation of a number is \(2\times5^2\), which number is it?

Explanation opens after your attempt
Correct Answer

A. 50

Step 1

Concept

\(5^2=25\).

Step 2

Why this answer is correct

\(2\times25=50\).

Step 3

Exam Tip

Find the value of the power and then multiply. चरण 1: \(5^2=25\) है। चरण 2: \(2\times25=50\)। चरण 3: घात का मान निकालकर फिर गुणा करें।

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Question 95/143 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^2\times3^2\) है, तो वह संख्या कौन सी है?

If the prime factorisation of a number is \(2^2\times3^2\), which number is it?

Explanation opens after your attempt
Correct Answer

A. 36

Step 1

Concept

Calculate \(2^2=4\) and \(3^2=9\).

Step 2

Why this answer is correct

\(4\times9=36\).

Step 3

Exam Tip

Multiply to get the number from prime factorisation. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9=36\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए गुणा करें।

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Question 96/143 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

यदि \(m=3^2\times7\), तो (m) का मान क्या है?

If \(m=3^2\times7\), what is the value of (m)?

Explanation opens after your attempt
Correct Answer

A. 63

Step 1

Concept

\(3^2=9\).

Step 2

Why this answer is correct

\(9\times7=63\).

Step 3

Exam Tip

In an expression with powers, evaluate the power first. चरण 1: \(3^2=9\) है। चरण 2: \(9\times7=63\)। चरण 3: घात वाले रूप में पहले घात का मान निकालें।

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Question 97/143 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

यदि \(n=2^3\times5\), तो (n) का मान क्या है?

If \(n=2^3\times5\), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

A. 40

Step 1

Concept

\(2^3=8\).

Step 2

Why this answer is correct

\(8\times5=40\).

Step 3

Exam Tip

Multiply the factors to convert prime factorisation into the number. चरण 1: \(2^3=8\) है। चरण 2: \(8\times5=40\)। चरण 3: अभाज्य गुणनखंडन को संख्या में बदलने के लिए गुणा करें।

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Question 98/143 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\) है?

Which number has prime factorisation \(2^3\times3^2\)?

Explanation opens after your attempt
Correct Answer

A. 72

Step 1

Concept

Calculate \(2^3=8\) and \(3^2=9\).

Step 2

Why this answer is correct

\(8\times9=72\).

Step 3

Exam Tip

Evaluating powers first gives the answer quickly. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9=72\)। चरण 3: घातों का मान पहले निकालने से उत्तर जल्दी मिलता है।

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Question 99/143 Easy Mathematics Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7

किस संख्या का अभाज्य गुणनखंडन \(2^2\times3\times5\) है?

Which number has prime factorisation \(2^2\times3\times5\)?

Explanation opens after your attempt
Correct Answer

A. 60

Step 1

Concept

Calculate \(2^2=4\).

Step 2

Why this answer is correct

\(4\times3\times5=60\).

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: \(2^2=4\) निकालें। चरण 2: \(4\times3\times5=60\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 100/143 Expert Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

किस विकल्प में \(2^8\times3^4\times5\times7\) से बनी संख्या सही है?

Which option gives the number formed by \(2^8\times3^4\times5\times7\)?

Explanation opens after your attempt
Correct Answer

A. 725760

Step 1

Concept

Calculate \(2^8=256\) and \(3^4=81\).

Step 2

Why this answer is correct

\(256\times81\times5\times7=725760\).

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: \(2^8=256\) और \(3^4=81\) निकालें। चरण 2: \(256\times81\times5\times7=725760\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 101/143 Expert Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^7\times3^6\times5^3\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(2^7\times3^6\times5^3\), what is the number?

Explanation opens after your attempt
Correct Answer

A. 11664000

Step 1

Concept

Calculate \(2^7=128\), \(3^6=729\), and \(5^3=125\).

Step 2

Why this answer is correct

\(128\times729\times125=11664000\).

Step 3

Exam Tip

Simplifying powers first keeps the calculation clear. चरण 1: \(2^7=128\), \(3^6=729\), और \(5^3=125\) निकालें। चरण 2: \(128\times729\times125=11664000\)। चरण 3: घातों को पहले सरल करने से गणना साफ रहती है।

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Question 102/143 Expert Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

किस विकल्प में \(2^{11}\times3^5\times5\) का सही मान है?

Which option gives the correct value of \(2^{11}\times3^5\times5\)?

Explanation opens after your attempt
Correct Answer

A. 2488320

Step 1

Concept

Calculate \(2^{11}=2048\) and \(3^5=243\).

Step 2

Why this answer is correct

\(2048\times243\times5=2488320\).

Step 3

Exam Tip

In larger multiplication, simplify powers first. चरण 1: \(2^{11}=2048\) और \(3^5=243\) निकालें। चरण 2: \(2048\times243\times5=2488320\)। चरण 3: बड़े गुणन में पहले घातों को सरल करें।

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Question 103/143 Expert Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

किस विकल्प में \(2^7\times3^4\times5\times7\) से बनी संख्या सही है?

Which option gives the number formed by \(2^7\times3^4\times5\times7\)?

Explanation opens after your attempt
Correct Answer

A. 362880

Step 1

Concept

Calculate \(2^7=128\) and \(3^4=81\).

Step 2

Why this answer is correct

\(128\times81\times5\times7=362880\).

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: \(2^7=128\) और \(3^4=81\) निकालें। चरण 2: \(128\times81\times5\times7=362880\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 104/143 Expert Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^6\times3^6\times5^3\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(2^6\times3^6\times5^3\), what is the number?

Explanation opens after your attempt
Correct Answer

A. 5832000

Step 1

Concept

Calculate \(2^6=64\), \(3^6=729\), and \(5^3=125\).

Step 2

Why this answer is correct

\(64\times729\times125=5832000\).

Step 3

Exam Tip

Simplifying powers first keeps the calculation clean. चरण 1: \(2^6=64\), \(3^6=729\), और \(5^3=125\) निकालें। चरण 2: \(64\times729\times125=5832000\)। चरण 3: घातों को पहले सरल करने से गणना साफ रहती है।

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Question 105/143 Expert Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

किस विकल्प में \(2^{10}\times3^4\times5\) का सही मान है?

Which option gives the correct value of \(2^{10}\times3^4\times5\)?

Explanation opens after your attempt
Correct Answer

A. 414720

Step 1

Concept

Calculate \(2^{10}=1024\) and \(3^4=81\).

Step 2

Why this answer is correct

\(1024\times81\times5=414720\).

Step 3

Exam Tip

In larger multiplication, simplify powers first. चरण 1: \(2^{10}=1024\) और \(3^4=81\) निकालें। चरण 2: \(1024\times81\times5=414720\)। चरण 3: बड़े गुणन में पहले घातों को सरल करें।

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Question 106/143 Expert Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4

किस विकल्प में \(2^6\times3^4\times5\times7\) से बनी संख्या सही है?

Which option gives the number formed by \(2^6\times3^4\times5\times7\)?

Explanation opens after your attempt
Correct Answer

A. 181440

Step 1

Concept

First calculate \(2^6=64\) and \(3^4=81\).

Step 2

Why this answer is correct

\(64\times81\times5\times7=181440\).

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: पहले \(2^6=64\) और \(3^4=81\) निकालें। चरण 2: \(64\times81\times5\times7=181440\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 107/143 Expert Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^5\times3^6\times5^3\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(2^5\times3^6\times5^3\), what is the number?

Explanation opens after your attempt
Correct Answer

A. 2916000

Step 1

Concept

Calculate \(2^5=32\), \(3^6=729\), and \(5^3=125\).

Step 2

Why this answer is correct

\(32\times729\times125=2916000\).

Step 3

Exam Tip

Simplifying powers first keeps the calculation manageable. चरण 1: \(2^5=32\), \(3^6=729\), और \(5^3=125\) निकालें। चरण 2: \(32\times729\times125=2916000\)। चरण 3: घातों को पहले सरल करने से गणना नियंत्रित रहती है।

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Question 108/143 Expert Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4

किस विकल्प में \(2^9\times3^4\times5\) का सही मान है?

Which option gives the correct value of \(2^9\times3^4\times5\)?

Explanation opens after your attempt
Correct Answer

A. 207360

Step 1

Concept

Calculate \(2^9=512\) and \(3^4=81\).

Step 2

Why this answer is correct

\(512\times81\times5=207360\).

Step 3

Exam Tip

In larger products, simplifying powers first is the right method. चरण 1: \(2^9=512\) और \(3^4=81\) निकालें। चरण 2: \(512\times81\times5=207360\)। चरण 3: बड़े गुणन में पहले घातों को सरल करना सही तरीका है।

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Question 109/143 Hard Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

किस विकल्प में \(2^5\times3^3\times5\times7\) से बनी संख्या सही है?

Which option gives the number formed by \(2^5\times3^3\times5\times7\)?

Explanation opens after your attempt
Correct Answer

A. 30240

Step 1

Concept

First calculate \(2^5=32\) and \(3^3=27\).

Step 2

Why this answer is correct

\(32\times27\times5\times7=30240\).

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: पहले \(2^5=32\) और \(3^3=27\) निकालें। चरण 2: \(32\times27\times5\times7=30240\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 110/143 Hard Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^4\times3^5\times5^3\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(2^4\times3^5\times5^3\), what is the number?

Explanation opens after your attempt
Correct Answer

A. 486000

Step 1

Concept

Calculate \(2^4=16\), \(3^5=243\), and \(5^3=125\).

Step 2

Why this answer is correct

\(16\times243\times125=486000\).

Step 3

Exam Tip

Simplifying powers first makes the calculation easier. चरण 1: \(2^4=16\), \(3^5=243\), और \(5^3=125\) निकालें। चरण 2: \(16\times243\times125=486000\)। चरण 3: घातों को पहले सरल करने से गणना कम कठिन होती है।

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Question 111/143 Hard Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

किस विकल्प में \(2^8\times3^3\times5\) का सही मान है?

Which option gives the correct value of \(2^8\times3^3\times5\)?

Explanation opens after your attempt
Correct Answer

A. 34560

Step 1

Concept

Calculate \(2^8=256\) and \(3^3=27\).

Step 2

Why this answer is correct

\(256\times27\times5=34560\).

Step 3

Exam Tip

In larger products, simplifying powers first is safer. चरण 1: \(2^8=256\) और \(3^3=27\) निकालें। चरण 2: \(256\times27\times5=34560\)। चरण 3: बड़े गुणन में पहले घातों को सरल करना सुरक्षित रहता है।

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Question 112/143 Hard Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

किस विकल्प में \(2^4\times3^3\times5\times7\) से बनी संख्या सही है?

Which option gives the number formed by \(2^4\times3^3\times5\times7\)?

Explanation opens after your attempt
Correct Answer

A. 15120

Step 1

Concept

First calculate \(2^4=16\) and \(3^3=27\).

Step 2

Why this answer is correct

\(16\times27\times5\times7=15120\).

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: पहले \(2^4=16\) और \(3^3=27\) निकालें। चरण 2: \(16\times27\times5\times7=15120\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 113/143 Hard Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^4\times3^5\times5^2\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(2^4\times3^5\times5^2\), what is the number?

Explanation opens after your attempt
Correct Answer

A. 97200

Step 1

Concept

Calculate \(2^4=16\), \(3^5=243\), and \(5^2=25\).

Step 2

Why this answer is correct

\(16\times243\times25=97200\).

Step 3

Exam Tip

Simplifying powers first makes the calculation easier. चरण 1: \(2^4=16\), \(3^5=243\), और \(5^2=25\) निकालें। चरण 2: \(16\times243\times25=97200\)। चरण 3: घातों को पहले सरल करने से गणना कम कठिन होती है।

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Question 114/143 Hard Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

किस विकल्प में \(2^7\times3^2\times5\) का सही मान है?

Which option gives the correct value of \(2^7\times3^2\times5\)?

Explanation opens after your attempt
Correct Answer

A. 5760

Step 1

Concept

Calculate \(2^7=128\) and \(3^2=9\).

Step 2

Why this answer is correct

\(128\times9\times5=5760\).

Step 3

Exam Tip

In larger products, simplifying powers first is safer. चरण 1: \(2^7=128\) और \(3^2=9\) निकालें। चरण 2: \(128\times9\times5=5760\)। चरण 3: बड़े गुणन में पहले घातों को सरल करना सुरक्षित रहता है।

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Question 115/143 Hard Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4

किस विकल्प में \(2^3\times3^2\times5\times7\) से बनी संख्या सही है?

Which option gives the number formed by \(2^3\times3^2\times5\times7\)?

Explanation opens after your attempt
Correct Answer

A. 2520

Step 1

Concept

First calculate \(2^3=8\) and \(3^2=9\).

Step 2

Why this answer is correct

\(8\times9\times5\times7=2520\).

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: पहले \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times5\times7=2520\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 116/143 Hard Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4

यदि किसी संख्या का अभाज्य गुणनखंडन \(2^3\times3^4\times5^2\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(2^3\times3^4\times5^2\), what is the number?

Explanation opens after your attempt
Correct Answer

A. 16200

Step 1

Concept

Calculate \(2^3=8\), \(3^4=81\), and \(5^2=25\).

Step 2

Why this answer is correct

\(8\times81\times25=16200\).

Step 3

Exam Tip

Simplifying powers first keeps the calculation safe. चरण 1: \(2^3=8\), \(3^4=81\), और \(5^2=25\) निकालें। चरण 2: \(8\times81\times25=16200\)। चरण 3: घातों को पहले सरल करने से गणना सुरक्षित रहती है।

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Question 117/143 Hard Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4

किस विकल्प में \(2^6\times3^2\times5\) का सही मान है?

Which option gives the correct value of \(2^6\times3^2\times5\)?

Explanation opens after your attempt
Correct Answer

A. 2880

Step 1

Concept

Calculate \(2^6=64\) and \(3^2=9\).

Step 2

Why this answer is correct

\(64\times9\times5=2880\).

Step 3

Exam Tip

In larger products, evaluate powers first and then multiply. चरण 1: \(2^6=64\) और \(3^2=9\) निकालें। चरण 2: \(64\times9\times5=2880\)। चरण 3: बड़े गुणन में पहले घातों का मान निकालें, फिर गुणा करें।

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Question 118/143 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

किस संख्या का अभाज्य गुणनखंडन \(2^5\times3\times7\) है?

Which number has prime factorisation \(2^5\times3\times7\)?

Explanation opens after your attempt
Correct Answer

B. 672

Step 1

Concept

Calculate \(2^5=32\).

Step 2

Why this answer is correct

\(32\times3\times7=672\).

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: \(2^5=32\) निकालें। चरण 2: \(32\times3\times7=672\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 119/143 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

यदि \(r=2^5\times3^2\times5^2\), तो (r) का मान क्या है?

If \(r=2^5\times3^2\times5^2\), what is the value of (r)?

Explanation opens after your attempt
Correct Answer

B. 7200

Step 1

Concept

Calculate \(2^5=32\), \(3^2=9\), and \(5^2=25\).

Step 2

Why this answer is correct

\(32\times9\times25=7200\).

Step 3

Exam Tip

In larger multiplication, simplify powers first. चरण 1: \(2^5=32\), \(3^2=9\) और \(5^2=25\) निकालें। चरण 2: \(32\times9\times25=7200\)। चरण 3: बड़े गुणन में पहले घातों को सरल करें।

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Question 120/143 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

यदि \(n=2^2\times3^4\times5\), तो (n) का मान क्या है?

If \(n=2^2\times3^4\times5\), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

C. 1620

Step 1

Concept

Calculate \(2^2=4\) and \(3^4=81\).

Step 2

Why this answer is correct

\(4\times81\times5=1620\).

Step 3

Exam Tip

Simplifying powers first makes multiplication easier. चरण 1: \(2^2=4\) और \(3^4=81\) निकालें। चरण 2: \(4\times81\times5=1620\)। चरण 3: पहले घातों को सरल करने से गुणा आसान होता है।

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