Concept-wise Practice

evaluate-factorisation MCQ Questions for Class 10

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Practice Questions

143 questions tagged with evaluate-factorisation.

Question 121/143 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

किस संख्या का अभाज्य गुणनखंडन \(2^4\times3^2\times5\) है?

Which number has prime factorisation \(2^4\times3^2\times5\)?

Explanation opens after your attempt
Correct Answer

C. 720

Step 1

Concept

Calculate \(2^4=16\) and \(3^2=9\).

Step 2

Why this answer is correct

\(16\times9\times5=720\).

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: \(2^4=16\) और \(3^2=9\) निकालें। चरण 2: \(16\times9\times5=720\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 122/143 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

यदि \(x=2^4\times3^2\times7\), तो (x) का मान क्या है?

If \(x=2^4\times3^2\times7\), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

C. 1008

Step 1

Concept

First calculate \(2^4=16\) and \(3^2=9\).

Step 2

Why this answer is correct

\(16\times9\times7=1008\).

Step 3

Exam Tip

Simplify powers first while finding the number. चरण 1: पहले \(2^4=16\) और \(3^2=9\) निकालें। चरण 2: \(16\times9\times7=1008\)। चरण 3: संख्या निकालते समय पहले घातों को सरल करें।

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Question 123/143 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

किस संख्या का अभाज्य गुणनखंडन \(2^4\times3\times7\) है?

Which number has prime factorisation \(2^4\times3\times7\)?

Explanation opens after your attempt
Correct Answer

C. 336

Step 1

Concept

Calculate \(2^4=16\).

Step 2

Why this answer is correct

\(16\times3\times7=336\).

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: \(2^4=16\) निकालें। चरण 2: \(16\times3\times7=336\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 124/143 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

यदि \(r=2^6\times3\times5^2\), तो (r) का मान क्या है?

If \(r=2^6\times3\times5^2\), what is the value of (r)?

Explanation opens after your attempt
Correct Answer

B. 4800

Step 1

Concept

Calculate \(2^6=64\) and \(5^2=25\).

Step 2

Why this answer is correct

\(64\times3\times25=4800\).

Step 3

Exam Tip

Simplifying powers first makes multiplication easier. चरण 1: \(2^6=64\) और \(5^2=25\) निकालें। चरण 2: \(64\times3\times25=4800\)। चरण 3: पहले घातों को सरल करने से गुणा आसान हो जाता है।

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Question 125/143 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

यदि \(n=3^4\times5^2\), तो (n) का मान क्या है?

If \(n=3^4\times5^2\), what is the value of (n)?

Explanation opens after your attempt
Correct Answer

B. 2025

Step 1

Concept

Calculate \(3^4=81\) and \(5^2=25\).

Step 2

Why this answer is correct

\(81\times25=2025\).

Step 3

Exam Tip

In questions with powers, simplify the powers first. चरण 1: \(3^4=81\) और \(5^2=25\) निकालें। चरण 2: \(81\times25=2025\)। चरण 3: घातों वाले प्रश्न में पहले घातों को सरल करना चाहिए।

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Question 126/143 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times5\) है?

Which number has prime factorisation \(2^3\times3^2\times5\)?

Explanation opens after your attempt
Correct Answer

C. 360

Step 1

Concept

Calculate \(2^3=8\) and \(3^2=9\).

Step 2

Why this answer is correct

\(8\times9\times5=360\).

Step 3

Exam Tip

When converting prime factorisation into a number, multiply all factors. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times5=360\)। चरण 3: दिए गए अभाज्य गुणनखंडन को संख्या में बदलते समय सभी गुणनखंडों का गुणा करें।

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Question 127/143 Medium Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

यदि \(x=2^3\times3^2\times7\), तो (x) का मान क्या है?

If \(x=2^3\times3^2\times7\), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. 504

Step 1

Concept

First calculate \(2^3=8\) and \(3^2=9\).

Step 2

Why this answer is correct

\(8\times9\times7=504\).

Step 3

Exam Tip

To get the number from prime factorisation, simplify powers first. चरण 1: पहले \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times7=504\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए घातों को पहले सरल करें।

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Question 128/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

यदि किसी संख्या का अभाज्य गुणनखंडन \(3\times7\times11\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(3\times7\times11\), what is the number?

Explanation opens after your attempt
Correct Answer

C. 231

Step 1

Concept

Multiply the given prime factors.

Step 2

Why this answer is correct

\(3\times7\times11=231\), so the number is 231.

Step 3

Exam Tip

To get the original number, multiply all prime factors. चरण 1: दिए गए अभाज्य गुणनखंडों को गुणा करें। चरण 2: \(3\times7\times11=231\), इसलिए संख्या 231 है। चरण 3: मूल संख्या पाने के लिए सभी अभाज्य गुणनखंडों का गुणा करें।

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Question 129/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

संख्या \(2^4\times3\times5^2\) का मान क्या है?

What is the value of \(2^4\times3\times5^2\)?

Explanation opens after your attempt
Correct Answer

C. 1200

Step 1

Concept

Find \(2^4=16\) and \(5^2=25\).

Step 2

Why this answer is correct

\(16\times3\times25=1200\).

Step 3

Exam Tip

In questions with powers, simplify the powers first. चरण 1: \(2^4=16\) और \(5^2=25\) निकालें। चरण 2: \(16\times3\times25=1200\)। चरण 3: कई घातों वाले प्रश्नों में पहले घातों को सरल करें।

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Question 130/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

किस संख्या का अभाज्य गुणनखंडन \(2\times3^2\times7\) है?

Which number has prime factorisation \(2\times3^2\times7\)?

Explanation opens after your attempt
Correct Answer

C. 126

Step 1

Concept

Find \(3^2=9\).

Step 2

Why this answer is correct

\(2\times9\times7=126\), so the number is 126.

Step 3

Exam Tip

To get the number from prime factorisation, simplify powers first. चरण 1: \(3^2=9\) निकालें। चरण 2: \(2\times9\times7=126\), इसलिए संख्या 126 है। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए घातों को पहले सरल करें।

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Question 131/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

किस संख्या का अभाज्य गुणनखंडन \(2^2\times3\times5\) है?

Which number has prime factorisation \(2^2\times3\times5\)?

Explanation opens after your attempt
Correct Answer

C. 60

Step 1

Concept

Find \(2^2=4\).

Step 2

Why this answer is correct

\(4\times3\times5=60\), so the number is 60.

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: \(2^2=4\) निकालें। चरण 2: \(4\times3\times5=60\), इसलिए संख्या 60 है। चरण 3: दिए गए अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों को गुणा करें।

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Question 132/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

संख्या \(3^3\times5\) का मान क्या है?

What is the value of \(3^3\times5\)?

Explanation opens after your attempt
Correct Answer

C. 135

Step 1

Concept

First find \(3^3=27\).

Step 2

Why this answer is correct

\(27\times5=135\), so the number is 135.

Step 3

Exam Tip

In a form with powers, evaluate the power first. चरण 1: पहले \(3^3=27\) निकालें। चरण 2: \(27\times5=135\), इसलिए संख्या 135 है। चरण 3: घात वाले रूप में पहले घात का मान निकालें।

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Question 133/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 6

संख्या \(2^3\times3\times7\) किसके बराबर है?

The number \(2^3\times3\times7\) is equal to what?

Explanation opens after your attempt
Correct Answer

C. 168

Step 1

Concept

First find \(2^3=8\).

Step 2

Why this answer is correct

\(8\times3\times7=168\), so the number is 168.

Step 3

Exam Tip

In expressions with powers, evaluate the power first. चरण 1: पहले \(2^3=8\) निकालें। चरण 2: \(8\times3\times7=168\), इसलिए संख्या 168 है। चरण 3: घातों वाले रूप में पहले घात का मान निकालना आसान रहता है।

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Question 134/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

यदि किसी संख्या का अभाज्य गुणनखंडन \(2\times5\times11\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(2\times5\times11\), what is the number?

Explanation opens after your attempt
Correct Answer

C. 110

Step 1

Concept

Multiply the given prime factors.

Step 2

Why this answer is correct

\(2\times5\times11=110\), so the number is 110.

Step 3

Exam Tip

To get the original number, multiply all prime factors. चरण 1: दिए गए अभाज्य गुणनखंडों को गुणा करें। चरण 2: \(2\times5\times11=110\), इसलिए संख्या 110 है। चरण 3: मूल संख्या पाने के लिए सभी अभाज्य गुणनखंडों का गुणा करें।

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Question 135/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

संख्या \(2^3\times3\times5^2\) का मान क्या है?

What is the value of \(2^3\times3\times5^2\)?

Explanation opens after your attempt
Correct Answer

C. 600

Step 1

Concept

Find \(2^3=8\) and \(5^2=25\).

Step 2

Why this answer is correct

\(8\times3\times25=600\).

Step 3

Exam Tip

In questions with powers, simplify the powers first. चरण 1: \(2^3=8\) और \(5^2=25\) निकालें। चरण 2: \(8\times3\times25=600\)। चरण 3: कई घातों वाले प्रश्नों में पहले घात सरल करें।

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Question 136/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

किस संख्या का अभाज्य गुणनखंडन \(2^3\times7\) है?

Which number has prime factorisation \(2^3\times7\)?

Explanation opens after your attempt
Correct Answer

C. 56

Step 1

Concept

Find \(2^3=8\).

Step 2

Why this answer is correct

\(8\times7=56\), so the number is 56.

Step 3

Exam Tip

To get the number from prime factorisation, simplify powers first. चरण 1: \(2^3=8\) निकालें। चरण 2: \(8\times7=56\), इसलिए संख्या 56 है। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए घातों को पहले सरल करें।

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Question 137/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

किस संख्या का अभाज्य गुणनखंडन \(3^2\times7\) है?

Which number has prime factorisation \(3^2\times7\)?

Explanation opens after your attempt
Correct Answer

C. 63

Step 1

Concept

Find \(3^2=9\).

Step 2

Why this answer is correct

\(9\times7=63\), so the number is 63.

Step 3

Exam Tip

To get the number from prime factorisation, multiply all factors. चरण 1: \(3^2=9\) निकालें। चरण 2: \(9\times7=63\), इसलिए संख्या 63 है। चरण 3: दिए गए अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 138/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

संख्या \(2^4\times5\) का मान क्या है?

What is the value of \(2^4\times5\)?

Explanation opens after your attempt
Correct Answer

C. 80

Step 1

Concept

First find \(2^4=16\).

Step 2

Why this answer is correct

\(16\times5=80\), so the number is 80.

Step 3

Exam Tip

In a form with powers, it is easier to evaluate the power first. चरण 1: पहले \(2^4=16\) निकालें। चरण 2: \(16\times5=80\), इसलिए संख्या 80 है। चरण 3: घात वाले रूप में पहले घात का मान निकालना आसान रहता है।

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Question 139/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 5

संख्या \(2^2\times3^2\times5\) किसके बराबर है?

The number \(2^2\times3^2\times5\) is equal to what?

Explanation opens after your attempt
Correct Answer

C. 180

Step 1

Concept

First evaluate the powers: \(2^2=4\) and \(3^2=9\).

Step 2

Why this answer is correct

\(4\times9\times5=180\), so the number is 180.

Step 3

Exam Tip

Simplify powers first, then multiply. चरण 1: पहले घातों का मान निकालें: \(2^2=4\) और \(3^2=9\)। चरण 2: \(4\times9\times5=180\), इसलिए संख्या 180 है। चरण 3: पहले घात सरल करें, फिर गुणा करें।

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Question 140/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4

यदि किसी संख्या का अभाज्य गुणनखंडन \(3\times5\times7\) है, तो वह संख्या क्या है?

If the prime factorisation of a number is \(3\times5\times7\), what is the number?

Explanation opens after your attempt
Correct Answer

C. 105

Step 1

Concept

Multiply the given prime factors.

Step 2

Why this answer is correct

\(3\times5\times7=105\), so the number is 105.

Step 3

Exam Tip

To get the original number from prime factorisation, multiply all factors. चरण 1: दिए गए अभाज्य गुणनखंडों को गुणा करें। चरण 2: \(3\times5\times7=105\), इसलिए संख्या 105 है। चरण 3: अभाज्य गुणनखंडन से मूल संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 141/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4

संख्या \(2^2\times3\times5^2\) का मान क्या है?

What is the value of \(2^2\times3\times5^2\)?

Explanation opens after your attempt
Correct Answer

C. 300

Step 1

Concept

Find \(2^2=4\) and \(5^2=25\).

Step 2

Why this answer is correct

\(4\times3\times25=300\).

Step 3

Exam Tip

In questions with powers, simplify the powers first. चरण 1: \(2^2=4\) और \(5^2=25\) निकालें। चरण 2: \(4\times3\times25=300\)। चरण 3: कई घातों वाले प्रश्नों में पहले घातों को सरल करें।

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Question 142/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4

किस संख्या का अभाज्य गुणनखंडन \(2\times3\times7\) है?

Which number has prime factorisation \(2\times3\times7\)?

Explanation opens after your attempt
Correct Answer

C. 42

Step 1

Concept

Multiply the given prime factors.

Step 2

Why this answer is correct

\(2\times3\times7=42\), so the number is 42.

Step 3

Exam Tip

To get the number from factorisation, multiply all factors. चरण 1: दिए गए अभाज्य गुणनखंडों को गुणा करें। चरण 2: \(2\times3\times7=42\), इसलिए संख्या 42 है। चरण 3: गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।

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Question 143/143 Easy Mathematics Chapter 1: Real Numbers 2: Fundamental Theorem of Arithmetic Class 10 Level 4

किस संख्या का अभाज्य गुणनखंडन \(2^2\times7\) है?

Which number has prime factorisation \(2^2\times7\)?

Explanation opens after your attempt
Correct Answer

C. 28

Step 1

Concept

Find \(2^2=4\).

Step 2

Why this answer is correct

\(4\times7=28\), so the number is 28.

Step 3

Exam Tip

To get the number from prime factorisation, simplify powers first. चरण 1: \(2^2=4\) निकालें। चरण 2: \(4\times7=28\), इसलिए संख्या 28 है। चरण 3: दिए गए अभाज्य गुणनखंडन से संख्या पाने के लिए घातों को पहले सरल करें।

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