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Class 10MathematicsReal NumbersFundamental Theorem of ArithmeticHardLevel 6
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Which option gives the number formed by (2^5\times3^3\times5\times7)?

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Answer and explanation

Correct answer: 30240

Step 1: First calculate (2^5=32) and (3^3=27). Step 2: (32\times27\times5\times7=30240). Step 3: To get the number from prime factorisation, multiply all factors.

Related tags

Evaluate-FactorisationPrime-FactorsHard

Frequently asked questions

What is the correct answer to this question?

30240

Why is this the correct answer?

Step 1: First calculate (2^5=32) and (3^3=27). Step 2: (32\times27\times5\times7=30240). Step 3: To get the number from prime factorisation, multiply all factors.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Fundamental Theorem of Arithmetic.

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10 more MCQs
  1. 1According to the Fundamental Theorem of Arithmetic, every composite number can be written in which form?
  2. 2What is the prime factorisation of 36?
  3. 3What is the correct prime factorisation of 60?
  4. 4What does uniqueness mean in the Fundamental Theorem of Arithmetic?
  5. 5In the prime factorisation of 84, what is the power of 2?
  6. 6The number (2^3\times3^2) is equal to which number?
  7. 7Which is the prime factorisation of 45?
  8. 8Which of the following numbers is prime?
  9. 9Which of the following numbers is composite?
  10. 10What is the prime factorisation of 90?
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