Question 61/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^3\times5\times7\times11\) है?
Which number has prime factorisation \(2^3\times5\times7\times11\)?
#evaluate-factorisation
#number-3080
#medium
A 3080
B 1540
C 6160
D 3850
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\).
Step 2
Why this answer is correct
\(8\times5\times7\times11=3080\).
Step 3
Exam Tip
Whatever the order, the product remains the same. चरण 1: \(2^3=8\) निकालें। चरण 2: \(8\times5\times7\times11=3080\)। चरण 3: क्रम कोई भी हो, गुणनफल वही रहेगा।
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Question 62/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि \(2^2\times5^4\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^2\times5^4\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#number-2500
#medium
A 2500
B 1250
C 5000
D 625
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(5^4=625\).
Step 2
Why this answer is correct
\(4\times625=2500\).
Step 3
Exam Tip
Finding the higher power first makes the answer easier. चरण 1: \(2^2=4\) और \(5^4=625\) निकालें। चरण 2: \(4\times625=2500\)। चरण 3: बड़ी घात को पहले निकालने से उत्तर आसान बनता है।
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Question 63/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^4\times3^4\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^4\times3^4\), which number is it?
#evaluate-factorisation
#number-1296
#medium
A 1296
B 648
C 2592
D 1728
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\) and \(3^4=81\).
Step 2
Why this answer is correct
\(16\times81=1296\).
Step 3
Exam Tip
In such calculations, simplifying powers first is safer. चरण 1: \(2^4=16\) और \(3^4=81\) हैं। चरण 2: \(16\times81=1296\)। चरण 3: ऐसी गणना में घातों को पहले सरल करना सुरक्षित रहता है।
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Question 64/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times5^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^3\times3^2\times5^2\), which number is it?
#evaluate-factorisation
#number-1800
#medium
A 1800
B 900
C 3600
D 1200
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\), \(3^2=9\), and \(5^2=25\).
Step 2
Why this answer is correct
\(8\times9\times25=1800\).
Step 3
Exam Tip
Find each power separately and then multiply. चरण 1: \(2^3=8\), \(3^2=9\) और \(5^2=25\) निकालें। चरण 2: \(8\times9\times25=1800\)। चरण 3: तीनों घातों का मान अलग-अलग निकालकर गुणा करें।
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Question 65/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि \(2^4\times3^2\times5\) से संख्या बनाई जाए, तो वह कौन सी होगी?
If a number is formed from \(2^4\times3^2\times5\), which number will it be?
#evaluate-factorisation
#mcq-pattern
#medium
A 720
B 360
C 1440
D 1080
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^2=9\).
Step 2
Why this answer is correct
\(16\times9\times5=720\).
Step 3
Exam Tip
Solving powers first helps find the option quickly. चरण 1: \(2^4=16\) और \(3^2=9\) निकालें। चरण 2: \(16\times9\times5=720\)। चरण 3: घातों को पहले हल करने से विकल्प जल्दी मिल जाता है।
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Question 66/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि \(m=3^3\times5\times7\), तो (m) का मान क्या है?
If \(m=3^3\times5\times7\), what is the value of (m)?
#evaluate-factorisation
#powers
#medium
A 945
B 315
C 1890
D 735
Explanation opens after your attempt
Step 1
Concept
\(3^3=27\).
Step 2
Why this answer is correct
\(27\times5\times7=945\).
Step 3
Exam Tip
It is better to simplify the power part first. चरण 1: \(3^3=27\) है। चरण 2: \(27\times5\times7=945\)। चरण 3: घात वाले भाग को पहले सरल करना ठीक रहता है।
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Question 67/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
यदि \(n=2^5\times3\times7\), तो (n) का मान क्या है?
If \(n=2^5\times3\times7\), what is the value of (n)?
#evaluate-factorisation
#powers
#medium
A 672
B 336
C 1008
D 504
Explanation opens after your attempt
Step 1
Concept
\(2^5=32\).
Step 2
Why this answer is correct
\(32\times3\times7=672\).
Step 3
Exam Tip
Multiply all factors to convert prime factorisation into the number. चरण 1: \(2^5=32\) है। चरण 2: \(32\times3\times7=672\)। चरण 3: अभाज्य गुणनखंडन को संख्या में बदलने के लिए सभी गुणनखंडों का गुणा करें।
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Question 68/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3^2\times5\times11\) है?
Which number has prime factorisation \(2^2\times3^2\times5\times11\)?
#evaluate-factorisation
#number-1980
#medium
A 1980
B 990
C 3960
D 1080
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(3^2=9\).
Step 2
Why this answer is correct
\(4\times9\times5\times11=1980\).
Step 3
Exam Tip
Simplifying powers first gives the answer quickly. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9\times5\times11=1980\)। चरण 3: घातों को पहले सरल करने से उत्तर जल्दी मिलता है।
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Question 69/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^6\times3^3\) है?
Which number has prime factorisation \(2^6\times3^3\)?
#evaluate-factorisation
#number-1728
#medium
A 1728
B 864
C 3456
D 1296
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^6=64\) and \(3^3=27\).
Step 2
Why this answer is correct
\(64\times27=1728\).
Step 3
Exam Tip
Simplify higher powers separately first. चरण 1: \(2^6=64\) और \(3^3=27\) निकालें। चरण 2: \(64\times27=1728\)। चरण 3: बड़ी घातों को पहले अलग से सरल करें।
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Question 70/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^2\times5\times7^2\) है?
Which number has prime factorisation \(2^2\times5\times7^2\)?
#evaluate-factorisation
#number-980
#medium
A 980
B 490
C 1960
D 700
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(7^2=49\).
Step 2
Why this answer is correct
\(4\times5\times49=980\).
Step 3
Exam Tip
Finding powers first reduces mistakes. चरण 1: \(2^2=4\) और \(7^2=49\) निकालें। चरण 2: \(4\times5\times49=980\)। चरण 3: घातों का मान पहले निकालने से गलती कम होती है।
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Question 71/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3\times11\) है?
Which number has prime factorisation \(2^4\times3\times11\)?
#evaluate-factorisation
#number-528
#medium
A 528
B 264
C 1056
D 396
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times11=528\).
Step 3
Exam Tip
While multiplying, complete smaller products first. चरण 1: \(2^4=16\) निकालें। चरण 2: \(16\times3\times11=528\)। चरण 3: गुणन करते समय पहले छोटे गुणन को पूरा करें।
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Question 72/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 7
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times7\) है?
Which number has prime factorisation \(2^3\times3^2\times7\)?
#evaluate-factorisation
#number-504
#medium
A 504
B 252
C 1008
D 756
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times7=504\).
Step 3
Exam Tip
Evaluate prime powers first, then multiply. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times7=504\)। चरण 3: अभाज्य घातों का मान पहले निकालें, फिर गुणा करें।
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Question 73/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^4\times3^4\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^4\times3^4\), which number is it?
#evaluate-factorisation
#number-1296
#easy
A 1296
B 648
C 2592
D 1728
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^4=81\).
Step 2
Why this answer is correct
\(16\times81=1296\).
Step 3
Exam Tip
Evaluate prime powers and then multiply. चरण 1: \(2^4=16\) और \(3^4=81\) निकालें। चरण 2: \(16\times81=1296\)। चरण 3: अभाज्य घातों का मान निकालकर गुणा करें।
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Question 74/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times5^2\) है?
Which number has prime factorisation \(2^3\times3^2\times5^2\)?
#evaluate-factorisation
#number-1800
#easy
A 1800
B 900
C 3600
D 1200
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\), \(3^2=9\), and \(5^2=25\).
Step 2
Why this answer is correct
\(8\times9\times25=1800\).
Step 3
Exam Tip
Simplify powers first, then multiply. चरण 1: \(2^3=8\), \(3^2=9\) और \(5^2=25\) निकालें। चरण 2: \(8\times9\times25=1800\)। चरण 3: घातों को पहले सरल करें, फिर गुणा करें।
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Question 75/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2\times3\times5\times7\times11\) है?
Which number has prime factorisation \(2\times3\times5\times7\times11\)?
#evaluate-factorisation
#number-2310
#easy
A 2310
B 1155
C 4620
D 3300
Explanation opens after your attempt
Step 1
Concept
Multiply all given prime factors.
Step 2
Why this answer is correct
\(2\times3\times5\times7\times11=2310\).
Step 3
Exam Tip
When no power is written, each prime is taken once. चरण 1: दिए गए सभी अभाज्य गुणनखंडों को गुणा करें। चरण 2: \(2\times3\times5\times7\times11=2310\)। चरण 3: जब घात न हो तो प्रत्येक अभाज्य एक बार लिया जाता है।
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Question 76/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि किसी संख्या का अभाज्य गुणनखंडन \(5^2\times7^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(5^2\times7^2\), which number is it?
#evaluate-factorisation
#number-1225
#easy
A 1225
B 875
C 2450
D 6125
Explanation opens after your attempt
Step 1
Concept
\(5^2=25\) and \(7^2=49\).
Step 2
Why this answer is correct
\(25\times49=1225\).
Step 3
Exam Tip
Both powers are 2 in this square form, so multiply carefully. चरण 1: \(5^2=25\) और \(7^2=49\) हैं। चरण 2: \(25\times49=1225\)। चरण 3: वर्ग रूप में दोनों घातें 2 हैं, इसलिए गुणा साफ करें।
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Question 77/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^3\times3\times7^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^3\times3\times7^2\), which number is it?
#evaluate-factorisation
#number-1176
#easy
A 1176
B 588
C 1470
D 2352
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(7^2=49\).
Step 2
Why this answer is correct
\(8\times3\times49=1176\).
Step 3
Exam Tip
Evaluating powers first makes calculation easier. चरण 1: \(2^3=8\) और \(7^2=49\) निकालें। चरण 2: \(8\times3\times49=1176\)। चरण 3: घातों का मान पहले निकालना गणना को आसान बनाता है।
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Question 78/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(m=3^2\times5^2\), तो (m) का मान क्या है?
If \(m=3^2\times5^2\), what is the value of (m)?
#evaluate-factorisation
#powers
#easy
A 225
B 150
C 300
D 450
Explanation opens after your attempt
Step 1
Concept
\(3^2=9\) and \(5^2=25\).
Step 2
Why this answer is correct
\(9\times25=225\).
Step 3
Exam Tip
Simplify both powers first. चरण 1: \(3^2=9\) और \(5^2=25\) हैं। चरण 2: \(9\times25=225\)। चरण 3: दोनों घातों को पहले सरल करें।
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Question 79/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(n=2^3\times3\times7\), तो (n) का मान क्या है?
If \(n=2^3\times3\times7\), what is the value of (n)?
#evaluate-factorisation
#powers
#easy
A 168
B 84
C 126
D 336
Explanation opens after your attempt
Step 1
Concept
\(2^3=8\).
Step 2
Why this answer is correct
\(8\times3\times7=168\).
Step 3
Exam Tip
Multiply to get the number from prime factorisation. चरण 1: \(2^3=8\) है। चरण 2: \(8\times3\times7=168\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए गुणा करें।
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Question 80/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2\times3^4\) है?
Which number has prime factorisation \(2\times3^4\)?
#evaluate-factorisation
#number-162
#easy
A 162
B 81
C 324
D 486
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^4=81\).
Step 2
Why this answer is correct
\(2\times81=162\).
Step 3
Exam Tip
Simplify the factor with a power first. चरण 1: \(3^4=81\) निकालें। चरण 2: \(2\times81=162\)। चरण 3: घात वाले गुणनखंड को पहले सरल करें।
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Question 81/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3^2\times5\) है?
Which number has prime factorisation \(2^4\times3^2\times5\)?
#evaluate-factorisation
#number-720
#easy
A 720
B 360
C 1440
D 1080
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^2=9\).
Step 2
Why this answer is correct
\(16\times9\times5=720\).
Step 3
Exam Tip
Evaluating powers first makes calculation easier. चरण 1: \(2^4=16\) और \(3^2=9\) निकालें। चरण 2: \(16\times9\times5=720\)। चरण 3: पहले घातों का मान निकालने से गणना आसान होती है।
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Question 82/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^4\times5^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^4\times5^2\), which number is it?
#evaluate-factorisation
#number-400
#easy
A 400
B 200
C 800
D 100
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(5^2=25\).
Step 2
Why this answer is correct
\(16\times25=400\).
Step 3
Exam Tip
Finding powers first makes the calculation easier. चरण 1: \(2^4=16\) और \(5^2=25\) निकालें। चरण 2: \(16\times25=400\)। चरण 3: घातों का मान पहले निकालना आसान रहता है।
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Question 83/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3^2\times7\) है?
Which number has prime factorisation \(2^2\times3^2\times7\)?
#evaluate-factorisation
#number-252
#easy
A 252
B 126
C 504
D 378
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(3^2=9\).
Step 2
Why this answer is correct
\(4\times9\times7=252\).
Step 3
Exam Tip
Evaluate prime powers and then multiply. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9\times7=252\)। चरण 3: अभाज्य घातों का मान निकालकर गुणा करें।
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Question 84/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2\times3\times5\times7\) है?
Which number has prime factorisation \(2\times3\times5\times7\)?
#evaluate-factorisation
#number-210
#easy
A 210
B 105
C 420
D 315
Explanation opens after your attempt
Step 1
Concept
All prime factors are given.
Step 2
Why this answer is correct
\(2\times3\times5\times7=210\).
Step 3
Exam Tip
When no power is written, each prime is taken once. चरण 1: सभी अभाज्य गुणनखंड दिए हैं। चरण 2: \(2\times3\times5\times7=210\)। चरण 3: जब घात न हो तो हर अभाज्य एक बार लिया जाता है।
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Question 85/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि किसी संख्या का अभाज्य गुणनखंडन \(3^2\times5^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(3^2\times5^2\), which number is it?
#evaluate-factorisation
#number-225
#easy
A 225
B 150
C 300
D 450
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^2=9\) and \(5^2=25\).
Step 2
Why this answer is correct
\(9\times25=225\).
Step 3
Exam Tip
Simplify powers first and then multiply. चरण 1: \(3^2=9\) और \(5^2=25\) निकालें। चरण 2: \(9\times25=225\)। चरण 3: घातों को पहले सरल करें, फिर गुणा करें।
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Question 86/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^2\times3\times11\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^2\times3\times11\), which number is it?
#evaluate-factorisation
#number-132
#easy
A 132
B 66
C 264
D 99
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\).
Step 2
Why this answer is correct
\(4\times3\times11=132\).
Step 3
Exam Tip
Multiply all factors to get the number from prime factorisation. चरण 1: \(2^2=4\) निकालें। चरण 2: \(4\times3\times11=132\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों का गुणा करें।
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Question 87/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(m=3^2\times5\times7\), तो (m) का मान क्या है?
If \(m=3^2\times5\times7\), what is the value of (m)?
#evaluate-factorisation
#powers
#easy
A 315
B 210
C 175
D 420
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^2=9\).
Step 2
Why this answer is correct
\(9\times5\times7=315\).
Step 3
Exam Tip
Simplify the factor with a power first. चरण 1: \(3^2=9\) निकालें। चरण 2: \(9\times5\times7=315\)। चरण 3: घात वाले गुणनखंड को पहले सरल करें।
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Question 88/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(n=2^4\times3\times5\), तो (n) का मान क्या है?
If \(n=2^4\times3\times5\), what is the value of (n)?
#evaluate-factorisation
#powers
#easy
A 240
B 120
C 180
D 300
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5=240\).
Step 3
Exam Tip
Multiply to get the number from prime form. चरण 1: \(2^4=16\) है। चरण 2: \(16\times3\times5=240\)। चरण 3: अभाज्य रूप से संख्या पाने के लिए गुणा करें।
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Question 89/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2\times3^3\times5\) है?
Which number has prime factorisation \(2\times3^3\times5\)?
#evaluate-factorisation
#number-270
#easy
A 270
B 180
C 135
D 540
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^3=27\).
Step 2
Why this answer is correct
\(2\times27\times5=270\).
Step 3
Exam Tip
Evaluating the power first makes calculation easy. चरण 1: \(3^3=27\) निकालें। चरण 2: \(2\times27\times5=270\)। चरण 3: घात का मान पहले निकालने से गणना आसान होती है।
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Question 90/143
Easy Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3\times7\) है?
Which number has prime factorisation \(2^3\times3\times7\)?
#evaluate-factorisation
#number-168
#easy
A 168
B 84
C 126
D 336
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\).
Step 2
Why this answer is correct
\(8\times3\times7=168\).
Step 3
Exam Tip
To get the number from prime factorisation, multiply all factors. चरण 1: \(2^3=8\) निकालें। चरण 2: \(8\times3\times7=168\)। चरण 3: अभाज्य गुणनखंडन से संख्या पाने के लिए सभी गुणनखंडों को गुणा करें।
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