Question 31/143
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस विकल्प में \(2^4\times3^3\times7^2\) का सही मान है?
Which option gives the correct value of \(2^4\times3^3\times7^2\)?
#evaluate-factorisation
#number-21168
#hard
A 21168
B 10584
C 28224
D 14112
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\), \(3^3=27\), and \(7^2=49\).
Step 2
Why this answer is correct
\(16\times27\times49=21168\).
Step 3
Exam Tip
Solve all three powers separately first. चरण 1: \(2^4=16\), \(3^3=27\) और \(7^2=49\) निकालें। चरण 2: \(16\times27\times49=21168\)। चरण 3: तीनों घातों को पहले अलग-अलग हल करें।
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Question 32/143
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^7\times3^5\) है?
Which number has prime factorisation \(2^7\times3^5\)?
#evaluate-factorisation
#number-31104
#hard
A 31104
B 15552
C 62208
D 20736
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^7=128\) and \(3^5=243\).
Step 2
Why this answer is correct
\(128\times243=31104\).
Step 3
Exam Tip
Simplifying both powers first is the correct method. चरण 1: \(2^7=128\) और \(3^5=243\) निकालें। चरण 2: \(128\times243=31104\)। चरण 3: दोनों घातों को पहले सरल करना सही तरीका है।
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Question 33/143
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3\times5\times7^2\) है?
Which number has prime factorisation \(2^4\times3\times5\times7^2\)?
#evaluate-factorisation
#number-11760
#hard
A 11760
B 5880
C 23520
D 17640
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(7^2=49\).
Step 2
Why this answer is correct
\(16\times3\times5\times49=11760\).
Step 3
Exam Tip
Calculating powers first makes the work easier. चरण 1: \(2^4=16\) और \(7^2=49\) निकालें। चरण 2: \(16\times3\times5\times49=11760\)। चरण 3: घातों का मान पहले निकालने से गणना आसान होती है।
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Question 34/143
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(3^2\times5^2\times7^2\) है?
Which number has prime factorisation \(3^2\times5^2\times7^2\)?
#evaluate-factorisation
#square-number
#hard
A 11025
B 3675
C 22050
D 1225
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^2=9\), \(5^2=25\), and \(7^2=49\).
Step 2
Why this answer is correct
\(9\times25\times49=11025\).
Step 3
Exam Tip
In this square form, all exponents are 2, so multiply carefully. चरण 1: \(3^2=9\), \(5^2=25\) और \(7^2=49\) निकालें। चरण 2: \(9\times25\times49=11025\)। चरण 3: वर्ग रूप में सभी घातें 2 हैं, इसलिए गुणा ध्यान से करें।
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Question 35/143
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^5\times3^3\times7\) है?
Which number has prime factorisation \(2^5\times3^3\times7\)?
#evaluate-factorisation
#number-6048
#hard
A 6048
B 3024
C 12096
D 8064
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^5=32\) and \(3^3=27\).
Step 2
Why this answer is correct
\(32\times27\times7=6048\).
Step 3
Exam Tip
Find the values of higher powers separately. चरण 1: \(2^5=32\) और \(3^3=27\) निकालें। चरण 2: \(32\times27\times7=6048\)। चरण 3: बड़ी घातों का मान अलग से निकालें।
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Question 36/143
Hard Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times7\times11\) है?
Which number has prime factorisation \(2^3\times3^2\times7\times11\)?
#evaluate-factorisation
#number-5544
#hard
A 5544
B 2772
C 11088
D 8316
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times7\times11=5544\).
Step 3
Exam Tip
Simplify powers first and then multiply. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times7\times11=5544\)। चरण 3: घातों को पहले सरल करके गुणा करें।
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Question 37/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2\times3^2\times5^2\times13\) है?
Which number has prime factorisation \(2\times3^2\times5^2\times13\)?
#evaluate-factorisation
#number-5850
#medium
A 5850
B 2925
C 11700
D 3900
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^2=9\) and \(5^2=25\).
Step 2
Why this answer is correct
\(2\times9\times25\times13=5850\).
Step 3
Exam Tip
First do \(9\times25=225\), then multiply the rest. चरण 1: \(3^2=9\) और \(5^2=25\) निकालें। चरण 2: \(2\times9\times25\times13=5850\)। चरण 3: पहले \(9\times25=225\) करें, फिर बाकी गुणा करें।
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Question 38/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(2^4\times3\times5\times11\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^4\times3\times5\times11\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#number-2640
#medium
A 2640
B 1320
C 5280
D 3960
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5\times11=2640\).
Step 3
Exam Tip
Do multiplication in small steps to avoid mistakes. चरण 1: \(2^4=16\) निकालें। चरण 2: \(16\times3\times5\times11=2640\)। चरण 3: गुणन को छोटे चरणों में करें ताकि गलती न हो।
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Question 39/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^2\times3^4\times7\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^2\times3^4\times7\), which number is it?
#evaluate-factorisation
#number-2268
#medium
A 2268
B 1134
C 4536
D 3402
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(3^4=81\).
Step 2
Why this answer is correct
\(4\times81\times7=2268\).
Step 3
Exam Tip
Simplifying the higher power first is the right method. चरण 1: \(2^2=4\) और \(3^4=81\) निकालें। चरण 2: \(4\times81\times7=2268\)। चरण 3: बड़ी घात को पहले सरल करना सही तरीका है।
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Question 40/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि किसी संख्या का अभाज्य गुणनखंडन \(3^2\times5\times7^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(3^2\times5\times7^2\), which number is it?
#evaluate-factorisation
#number-2205
#medium
A 2205
B 735
C 4410
D 1470
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^2=9\) and \(7^2=49\).
Step 2
Why this answer is correct
\(9\times5\times49=2205\).
Step 3
Exam Tip
Simplify the two powers first and multiply. चरण 1: \(3^2=9\) और \(7^2=49\) निकालें। चरण 2: \(9\times5\times49=2205\)। चरण 3: दो घातों को पहले सरल करके गुणा करें।
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Question 41/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(2^5\times3^2\times7\) से संख्या बनाई जाए, तो वह कौन सी होगी?
If a number is formed from \(2^5\times3^2\times7\), which number will it be?
#evaluate-factorisation
#mcq-pattern
#medium
A 2016
B 1008
C 4032
D 1344
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^5=32\) and \(3^2=9\).
Step 2
Why this answer is correct
\(32\times9\times7=2016\).
Step 3
Exam Tip
Solving powers first gives the answer quickly. चरण 1: \(2^5=32\) और \(3^2=9\) निकालें। चरण 2: \(32\times9\times7=2016\)। चरण 3: घातों को पहले हल करने से उत्तर जल्दी मिलता है।
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Question 42/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(m=3^4\times5\times7\), तो (m) का मान क्या है?
If \(m=3^4\times5\times7\), what is the value of (m)?
#evaluate-factorisation
#powers
#medium
A 2835
B 945
C 5670
D 2025
Explanation opens after your attempt
Step 1
Concept
\(3^4=81\).
Step 2
Why this answer is correct
\(81\times5\times7=2835\).
Step 3
Exam Tip
Simplifying the power first keeps the calculation clear. चरण 1: \(3^4=81\) है। चरण 2: \(81\times5\times7=2835\)। चरण 3: घात को पहले सरल करने से गणना साफ रहती है।
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Question 43/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
यदि \(n=2^4\times3\times5\times11\), तो (n) का मान क्या है?
If \(n=2^4\times3\times5\times11\), what is the value of (n)?
#evaluate-factorisation
#powers
#medium
A 2640
B 1320
C 5280
D 1980
Explanation opens after your attempt
Step 1
Concept
\(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5\times11=2640\).
Step 3
Exam Tip
Multiply all factors to get the number from prime form. चरण 1: \(2^4=16\) है। चरण 2: \(16\times3\times5\times11=2640\)। चरण 3: अभाज्य रूप से संख्या पाने के लिए सभी गुणनखंडों को गुणा करें।
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Question 44/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3\times5\times13\) है?
Which number has prime factorisation \(2^4\times3\times5\times13\)?
#evaluate-factorisation
#number-3120
#medium
A 3120
B 1560
C 6240
D 2340
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5\times13=3120\).
Step 3
Exam Tip
It is easy to first treat \(3\times5\times13\) as 195 and multiply. चरण 1: \(2^4=16\) निकालें। चरण 2: \(16\times3\times5\times13=3120\)। चरण 3: पहले \(3\times5\times13\) को 195 समझकर गुणा करना आसान है।
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Question 45/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3\times7\times11\) है?
Which number has prime factorisation \(2^2\times3\times7\times11\)?
#evaluate-factorisation
#number-924
#medium
A 924
B 462
C 1848
D 1386
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\).
Step 2
Why this answer is correct
\(4\times3\times7\times11=924\).
Step 3
Exam Tip
With many factors, multiply in pairs. चरण 1: \(2^2=4\) निकालें। चरण 2: \(4\times3\times7\times11=924\)। चरण 3: कई गुणनखंडों में जोड़े बनाकर गुणा करें।
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Question 46/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^5\times3^3\) है?
Which number has prime factorisation \(2^5\times3^3\)?
#evaluate-factorisation
#number-864
#medium
A 864
B 432
C 1728
D 1296
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^5=32\) and \(3^3=27\).
Step 2
Why this answer is correct
\(32\times27=864\).
Step 3
Exam Tip
Simplify both powers separately. चरण 1: \(2^5=32\) और \(3^3=27\) निकालें। चरण 2: \(32\times27=864\)। चरण 3: दोनों घातों को अलग-अलग सरल करें।
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Question 47/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(3\times5^2\times11\) है?
Which number has prime factorisation \(3\times5^2\times11\)?
#evaluate-factorisation
#number-825
#medium
A 825
B 550
C 1650
D 275
Explanation opens after your attempt
Step 1
Concept
Calculate \(5^2=25\).
Step 2
Why this answer is correct
\(3\times25\times11=825\).
Step 3
Exam Tip
It is useful to simplify the power part first. चरण 1: \(5^2=25\) निकालें। चरण 2: \(3\times25\times11=825\)। चरण 3: घात वाले भाग को पहले सरल करना उपयोगी है।
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Question 48/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 9
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times11\) है?
Which number has prime factorisation \(2^3\times3^2\times11\)?
#evaluate-factorisation
#number-792
#medium
A 792
B 396
C 1188
D 1584
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times11=792\).
Step 3
Exam Tip
First solve the powers, then multiply by 11. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times11=792\)। चरण 3: पहले घातों को हल करें, फिर 11 से गुणा करें।
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Question 49/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3\times5\times7\times11\) है?
Which number has prime factorisation \(2^2\times3\times5\times7\times11\)?
#evaluate-factorisation
#number-4620
#medium
A 4620
B 2310
C 9240
D 3850
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\).
Step 2
Why this answer is correct
\(4\times3\times5\times7\times11=4620\).
Step 3
Exam Tip
When there are many factors, multiply in pairs. चरण 1: \(2^2=4\) निकालें। चरण 2: \(4\times3\times5\times7\times11=4620\)। चरण 3: कई गुणनखंड हों तो जोड़े बनाकर गुणा करें।
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Question 50/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(2^2\times3^2\times7\times11\) किसी संख्या का अभाज्य गुणनखंडन है, तो संख्या क्या है?
If \(2^2\times3^2\times7\times11\) is the prime factorisation of a number, what is the number?
#evaluate-factorisation
#number-2772
#medium
A 2772
B 1386
C 5544
D 1980
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(3^2=9\).
Step 2
Why this answer is correct
\(4\times9\times7\times11=2772\).
Step 3
Exam Tip
Move step by step while multiplying. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9\times7\times11=2772\)। चरण 3: गुणा करते समय चरणों में आगे बढ़ें।
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Question 51/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि किसी संख्या का अभाज्य गुणनखंडन \(2\times3^3\times5^2\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2\times3^3\times5^2\), which number is it?
#evaluate-factorisation
#number-1350
#medium
A 1350
B 675
C 2700
D 1500
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^3=27\) and \(5^2=25\).
Step 2
Why this answer is correct
\(2\times27\times25=1350\).
Step 3
Exam Tip
Simplifying the two powers first makes multiplication easy. चरण 1: \(3^3=27\) और \(5^2=25\) निकालें। चरण 2: \(2\times27\times25=1350\)। चरण 3: दो घातों को पहले सरल करने से गुणा आसान होता है।
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Question 52/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि किसी संख्या का अभाज्य गुणनखंडन \(2^2\times3^3\times11\) है, तो वह संख्या कौन सी है?
If the prime factorisation of a number is \(2^2\times3^3\times11\), which number is it?
#evaluate-factorisation
#number-1188
#medium
A 1188
B 594
C 2376
D 1320
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(3^3=27\).
Step 2
Why this answer is correct
\(4\times27\times11=1188\).
Step 3
Exam Tip
Finding the value of powers first is the right method. चरण 1: \(2^2=4\) और \(3^3=27\) निकालें। चरण 2: \(4\times27\times11=1188\)। चरण 3: पहले घातों का मान निकालना ठीक तरीका है।
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Question 53/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(2^4\times3^2\times11\) से संख्या बनाई जाए, तो वह कौन सी होगी?
If a number is formed from \(2^4\times3^2\times11\), which number will it be?
#evaluate-factorisation
#mcq-pattern
#medium
A 1584
B 792
C 3168
D 1188
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^2=9\).
Step 2
Why this answer is correct
\(16\times9\times11=1584\).
Step 3
Exam Tip
Solve powers first and then multiply. चरण 1: \(2^4=16\) और \(3^2=9\) निकालें। चरण 2: \(16\times9\times11=1584\)। चरण 3: घातों को पहले हल करके गुणा करें।
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Question 54/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(m=2^3\times3^2\times5\times7\), तो (m) का मान क्या है?
If \(m=2^3\times3^2\times5\times7\), what is the value of (m)?
#evaluate-factorisation
#powers
#medium
A 2520
B 1260
C 5040
D 1680
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times5\times7=2520\).
Step 3
Exam Tip
First solve powers, then multiply by the remaining factors. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times5\times7=2520\)। चरण 3: पहले घातों को हल करें, फिर बाकी गुणनखंडों से गुणा करें।
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Question 55/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
यदि \(n=2^2\times3\times5^2\times7\), तो (n) का मान क्या है?
If \(n=2^2\times3\times5^2\times7\), what is the value of (n)?
#evaluate-factorisation
#powers
#medium
A 2100
B 1050
C 4200
D 700
Explanation opens after your attempt
Step 1
Concept
\(2^2=4\) and \(5^2=25\).
Step 2
Why this answer is correct
\(4\times3\times25\times7=2100\).
Step 3
Exam Tip
Solving the powers first makes multiplication easier. चरण 1: \(2^2=4\) और \(5^2=25\) हैं। चरण 2: \(4\times3\times25\times7=2100\)। चरण 3: दो घातों को पहले हल करने से गुणा आसान होता है।
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Question 56/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3^3\times7\) है?
Which number has prime factorisation \(2^4\times3^3\times7\)?
#evaluate-factorisation
#number-3024
#medium
A 3024
B 1512
C 6048
D 2016
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\) and \(3^3=27\).
Step 2
Why this answer is correct
\(16\times27\times7=3024\).
Step 3
Exam Tip
Simplify higher powers separately and multiply. चरण 1: \(2^4=16\) और \(3^3=27\) निकालें। चरण 2: \(16\times27\times7=3024\)। चरण 3: बड़ी घातों को अलग से सरल करके गुणा करें।
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Question 57/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^2\times3^2\times7\times11\) है?
Which number has prime factorisation \(2^2\times3^2\times7\times11\)?
#evaluate-factorisation
#number-2772
#medium
A 2772
B 1386
C 5544
D 1980
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^2=4\) and \(3^2=9\).
Step 2
Why this answer is correct
\(4\times9\times7\times11=2772\).
Step 3
Exam Tip
First multiply 4 and 9, then include the remaining factors. चरण 1: \(2^2=4\) और \(3^2=9\) निकालें। चरण 2: \(4\times9\times7\times11=2772\)। चरण 3: पहले 4 और 9 को गुणा करें, फिर बाकी गुणनखंड जोड़ें।
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Question 58/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2\times3^3\times5\times7\) है?
Which number has prime factorisation \(2\times3^3\times5\times7\)?
#evaluate-factorisation
#number-1890
#medium
A 1890
B 945
C 3780
D 1350
Explanation opens after your attempt
Step 1
Concept
Calculate \(3^3=27\).
Step 2
Why this answer is correct
\(2\times27\times5\times7=1890\).
Step 3
Exam Tip
Finding the value of the power first makes calculation simple. चरण 1: \(3^3=27\) निकालें। चरण 2: \(2\times27\times5\times7=1890\)। चरण 3: घात का मान पहले निकालना गणना को सरल बनाता है।
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Question 59/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^4\times3\times5\times7\) है?
Which number has prime factorisation \(2^4\times3\times5\times7\)?
#evaluate-factorisation
#number-1680
#medium
A 1680
B 840
C 3360
D 1260
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^4=16\).
Step 2
Why this answer is correct
\(16\times3\times5\times7=1680\).
Step 3
Exam Tip
When there are four factors, multiply smaller products in order. चरण 1: \(2^4=16\) निकालें। चरण 2: \(16\times3\times5\times7=1680\)। चरण 3: चार गुणनखंड हों तो क्रम से छोटे गुणन करें।
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Question 60/143
Medium Mathematics
Chapter 1: Real Numbers 3: Prime factorisation Class 10 Level 8
किस संख्या का अभाज्य गुणनखंडन \(2^3\times3^2\times11\) है?
Which number has prime factorisation \(2^3\times3^2\times11\)?
#evaluate-factorisation
#number-792
#medium
A 792
B 396
C 1584
D 1188
Explanation opens after your attempt
Step 1
Concept
Calculate \(2^3=8\) and \(3^2=9\).
Step 2
Why this answer is correct
\(8\times9\times11=792\).
Step 3
Exam Tip
Solve prime powers first, then multiply. चरण 1: \(2^3=8\) और \(3^2=9\) निकालें। चरण 2: \(8\times9\times11=792\)। चरण 3: अभाज्य घातों को पहले हल करें, फिर गुणा करें।
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