Level 3 • 10/50 questions • 35 seconds per question.
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What is the expansion of ( \(5+\sqrt{2}\)2 )?
C. \(27+10\sqrt{2}\)
( (a+b)2 ) का प्रयोग करें। यहाँ \(25+10\sqrt{2}+2=27+10\sqrt{2}\) मिलता है। / Use ( (a+b)2 ). Here \(25+10\sqrt{2}+2=27+10\sqrt{2}\).
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What is the value of ( \(6+\sqrt{23}\)\(6-\sqrt{23}\) )?
B. (13)
यह संयुग्मी गुणन है। (62-\(\sqrt{23}\)2=36-23=13) होगा। / This is conjugate multiplication. (62-\(\sqrt{23}\)2=36-23=13).
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What is the value of \( \sqrt{45}\times\sqrt{80} \)?
A. (60)
\( \sqrt{45}\times\sqrt{80}=\sqrt{3600}=60 \)। करणी गुणन में अंदर की संख्याएँ गुणा करें। / \( \sqrt{45}\times\sqrt{80}=\sqrt{3600}=60 \). In radical multiplication, multiply the radicands.
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What is the value of \( \sqrt{242}\div\sqrt{2} \)?
B. (11)
\( \frac{\sqrt{242}}{\sqrt{2}}=\sqrt{121}=11 \)। वर्गमूल के भाग में अंदर की संख्याओं का भाग लें। / \( \frac{\sqrt{242}}{\sqrt{2}}=\sqrt{121}=11 \). In division of square roots, divide the radicands.
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What is the value of \( \sqrt{3.24}+\sqrt{0.49} \)?
A. (2.5)
\( \sqrt{3.24}=1.8 \) और \( \sqrt{0.49}=0.7 \) है। योग (2.5) होगा। / \( \sqrt{3.24}=1.8 \) and \( \sqrt{0.49}=0.7 \). The sum is (2.5).
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What is the value of \( \sqrt{\frac{25}{49}}+\sqrt{\frac{16}{81}} \)?
A. \( \frac{73}{63} \)
पहला पद \( \frac{5}{7} \) और दूसरा \( \frac{4}{9} \) है। योग \( \frac{45}{63}+\frac{28}{63}=\frac{73}{63} \) है। / The first term is \( \frac{5}{7} \) and the second is \( \frac{4}{9} \). The sum is \( \frac{45}{63}+\frac{28}{63}=\frac{73}{63} \).
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What is the value of \( \sqrt{\frac{100}{169}}-\sqrt{\frac{9}{64}} \)?
A. \( \frac{41}{104} \)
\( \sqrt{\frac{100}{169}}=\frac{10}{13} \) और \( \sqrt{\frac{9}{64}}=\frac{3}{8} \) है। अंतर \( \frac{80}{104}-\frac{39}{104}=\frac{41}{104} \) है। / \( \sqrt{\frac{100}{169}}=\frac{10}{13} \) and \( \sqrt{\frac{9}{64}}=\frac{3}{8} \). The difference is \( \frac{80}{104}-\frac{39}{104}=\frac{41}{104} \).
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Between which two integers does \( \sqrt{101} \) lie?
C. (10) और (11)(10) and (11)
\(10^2=100\) और \(11^2=121\) है इसलिए \( \sqrt{101} \) (10) और (11) के बीच है। निकट पूर्ण वर्गों की तुलना करें। / \(10^2=100\) and \(11^2=121\), so \( \sqrt{101} \) lies between (10) and (11). Compare nearby perfect squares.
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Between which two integers will \( \sqrt{130} \) lie?
C. (11) और (12)(11) and (12)
\(11^2=121\) और \(12^2=144\) है इसलिए \( \sqrt{130} \) (11) और (12) के बीच है। सीमा वर्ग करके जाँचें। / \(11^2=121\) and \(12^2=144\), so \( \sqrt{130} \) lies between (11) and (12). Check the range by squaring.
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What is the value of \( |-\sqrt{100}+6| \)?
A. (4)
\( -\sqrt{100}+6=-10+6=-4 \) है और ( |-4|=4 )। निरपेक्ष मान दूरी देता है। / \( -\sqrt{100}+6=-10+6=-4 \) and ( |-4|=4 ). Absolute value gives distance.
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