Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 91-100 of 600 questions.
Which option is a correct example of an irrational number?
D. \(\sqrt{23}\)
(23) पूर्ण वर्ग नहीं है इसलिए \(\sqrt{23}\) अपरिमेय है। भिन्न और सांत दशमलव परिमेय होते हैं। / (23) is not a perfect square so \(\sqrt{23}\) is irrational. Fractions and terminating decimals are rational.
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Which part causes irrationality in \(4\sqrt{3}\)?
B. \(\sqrt{3}\)
\(\sqrt{3}\) अपरिमेय है इसलिए \(4\sqrt{3}\) अपरिमेय है। शून्येतर परिमेय गुणक प्रकार नहीं बदलता। / \(\sqrt{3}\) is irrational so \(4\sqrt{3}\) is irrational. A non-zero rational multiplier does not change the type.
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What type of number is \(\sqrt{81}+ \sqrt{2}\)?
B. अपरिमेयIrrational
\(\sqrt{81}=9\) है और \(9+\sqrt{2}\) अपरिमेय है। पहले सरल करें फिर संख्या का प्रकार तय करें। / \(\sqrt{81}=9\) and \(9+\sqrt{2}\) is irrational. Simplify first then decide the type.
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What is the simplified form of \(\sqrt{27}-\sqrt{12}\)?
B. \(\sqrt{3}\)
\(\sqrt{27}=3\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\) इसलिए अंतर \(\sqrt{3}\) है। परिणाम अपरिमेय है। / \(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\) so the difference is \(\sqrt{3}\). The result is irrational.
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Which statement is true for an irrational number?
D. उसे (pq) रूप में नहीं लिखा जा सकता / It cannot be written as (p / q)
अपरिमेय संख्या को (p/q) रूप में नहीं लिखा जा सकता। परीक्षा में यही मूल परिभाषा याद रखें। / An irrational number cannot be written in the form (p/q). Remember this basic definition for exams.
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What type of number is \(\sqrt[3]{8}\)?
B. परिमेयRational
\(\sqrt[3]{8}=2\) है इसलिए यह परिमेय है। पूर्ण घन का घनमूल परिमेय होता है। / \(\sqrt[3]{8}=2\) so it is rational. The cube root of a perfect cube is rational.
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Which is the simplified form of \(\sqrt{2}+3\sqrt{2}\)?
A. \(4\sqrt{2}\)
समान मूलों को जोड़ने पर \(\sqrt{2}+3\sqrt{2}=4\sqrt{2}\) मिलता है। यह अभी भी अपरिमेय है। / Adding like radicals gives \(\sqrt{2}+3\sqrt{2}=4\sqrt{2}\). It is still irrational.
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What is the sum of \(\sqrt{5}\) and \(\sqrt{20}\)?
B. \(3\sqrt{5}\)
\(\sqrt{20}=2\sqrt{5}\) इसलिए योग \(3\sqrt{5}\) है। पहले मूल को सरल करें। / \(\sqrt{20}=2\sqrt{5}\) so the sum is \(3\sqrt{5}\). Simplify radicals first.
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Which is the simplified form of \(\sqrt{98}\)?
A. \(7\sqrt{2}\)
\(\sqrt{98}=\sqrt{49\times2}=7\sqrt{2}\) होता है। \(\sqrt{2}\) बचने से यह अपरिमेय है। / \(\sqrt{98}=\sqrt{49\times2}=7\sqrt{2}\). Since \(\sqrt{2}\) remains, it is irrational.
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What is the simplified form of \(2\sqrt{6}-\sqrt{6}\)?
A. \(\sqrt{6}\)
समान मूलों को घटाने पर \(2\sqrt{6}-\sqrt{6}=\sqrt{6}\) मिलता है। \(\sqrt{6}\) अपरिमेय संख्या है। / Subtracting like radicals gives \(2\sqrt{6}-\sqrt{6}=\sqrt{6}\). \(\sqrt{6}\) is an irrational number.
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