\(2\sqrt{6}-\sqrt{6}\) का सरल रूप क्या है?

What is the simplified form of \(2\sqrt{6}-\sqrt{6}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(\sqrt{6}\)

Step 1

Concept

Subtracting like radicals gives \(2\sqrt{6}-\sqrt{6}=\sqrt{6}\). \(\sqrt{6}\) is an irrational number.

Step 2

Why this answer is correct

The correct answer is A. \(\sqrt{6}\). Subtracting like radicals gives \(2\sqrt{6}-\sqrt{6}=\sqrt{6}\). \(\sqrt{6}\) is an irrational number.

Step 3

Exam Tip

समान मूलों को घटाने पर \(2\sqrt{6}-\sqrt{6}=\sqrt{6}\) मिलता है। \(\sqrt{6}\) अपरिमेय संख्या है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(2\sqrt{6}-\sqrt{6}\) का सरल रूप क्या है? / What is the simplified form of \(2\sqrt{6}-\sqrt{6}\)?

Correct Answer: A. \(\sqrt{6}\). Explanation: समान मूलों को घटाने पर \(2\sqrt{6}-\sqrt{6}=\sqrt{6}\) मिलता है। \(\sqrt{6}\) अपरिमेय संख्या है। / Subtracting like radicals gives \(2\sqrt{6}-\sqrt{6}=\sqrt{6}\). \(\sqrt{6}\) is an irrational number.

Which concept should I revise for this Mathematics MCQ?

Subtracting like radicals gives \(2\sqrt{6}-\sqrt{6}=\sqrt{6}\). \(\sqrt{6}\) is an irrational number.

What exam hint can help solve this Mathematics question?

समान मूलों को घटाने पर \(2\sqrt{6}-\sqrt{6}=\sqrt{6}\) मिलता है। \(\sqrt{6}\) अपरिमेय संख्या है।