Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 521-530 of 584 questions.
What is the solution of ( 5x-2(3x-4)\geq 11 )?
A. \(x\leq -3\)
सरलीकरण से \(5x-6x+8\geq 11\) और \(-x\geq 3\) मिलता है। इसलिए \(x\leq -3\) है। / Simplification gives \(5x-6x+8\geq 11\) and \(-x\geq 3\). Therefore \(x\leq -3\).
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If \( \frac{x}{2}+3>\frac{2x-1}{5} \), what is the solution set?
A. (x>-32)
(10) से गुणा करने पर (5x+30>4x-2) मिलता है। इसलिए (x>-32) है। / Multiplying by (10) gives (5x+30>4x-2). Hence (x>-32).
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If \( \frac{3x+2}{8}<\frac{x-1}{2}+1 \), choose the correct solution.
A. (x>-2)
(8) से गुणा करने पर (3x+2<4x-4+8) मिलता है। इससे (x>-2) है। / Multiplying by (8) gives (3x+2<4x-4+8). Hence (x>-2).
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Which is the solution of ( 12-3(2x+1)\leq x-5 )?
A. \(x\geq 2\)
सरलीकरण से \(9-6x\leq x-5\) मिलता है। इसलिए \(14\leq 7x\) और \(x\geq 2\) है। / Simplification gives \(9-6x\leq x-5\). Therefore \(14\leq 7x\) and \(x\geq 2\).
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If \( \frac{x-6}{-3}>2 \), the correct solution for (x) is:
A. (x<0)
ऋणात्मक (-3) से गुणा करने पर चिह्न बदलता है। इसलिए (x-6<-6) और (x<0) है। / Multiplying by negative (-3) reverses the sign. Hence (x-6<-6) and (x<0).
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What is the solution set of \( \frac{2x+5}{3}\leq 7-\frac{x}{6} \)?
A. \(x\leq \frac{37}{5}\)
(6) से गुणा करने पर \(4x+10\leq 42-x\) मिलता है। इससे \(5x\leq 32\) और \(x\leq \frac{32}{5}\) है। / Multiplying by (6) gives \(4x+10\leq 42-x\). Thus \(5x\leq 32\) and \(x\leq \frac{32}{5}\).
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If ( 2x-3<5 ) and \( x+4\geq 1 \), what is the combined solution?
A. \(-3\leq x<4\)
पहली असमानता से (x<4) और दूसरी से \(x\geq -3\) मिलता है। संयुक्त हल ([-3,4)) है। / The first inequality gives (x<4), and the second gives \(x\geq -3\). The combined solution is ([-3,4)).
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The solution of ( 3(2x-1)-4(x+2)>x-9 ) is:
A. (x>2)
सरलीकरण से (6x-3-4x-8>x-9) मिलता है। इससे (x>2) है। / Simplification gives (6x-3-4x-8>x-9). Hence (x>2).
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If \( \frac{5x-4}{6}\geq \frac{x+2}{3}+1 \), what is the solution for (x)?
A. \(x\geq 4\)
(6) से गुणा करने पर \(5x-4\geq 2x+4+6\) मिलता है। अतः \(3x\geq 14\) और \(x\geq \frac{14}{3}\) है। / Multiplying by (6) gives \(5x-4\geq 2x+4+6\). Thus \(3x\geq 14\) and \(x\geq \frac{14}{3}\).
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If the solution of ( mx+2>8 ) is (x< -3), what is the value of (m)?
A. ( -2 )
हल (mx>6) है और (x<-3) तभी मिलेगा जब (m) ऋणात्मक हो। \(\frac{6}{m}=-3\) से (m=-2) है। / The solution is (mx>6), and (x<-3) requires (m) to be negative. From \(\frac{6}{m}=-3\), (m=-2).
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