यदि \( \frac{5x-4}{6}\geq \frac{x+2}{3}+1 \), तो (x) का हल क्या है?
If \( \frac{5x-4}{6}\geq \frac{x+2}{3}+1 \), what is the solution for (x)?
Explanation opens after your attempt
A. \(x\geq 4\)
Concept
Multiplying by (6) gives \(5x-4\geq 2x+4+6\). Thus \(3x\geq 14\) and \(x\geq \frac{14}{3}\).
Why this answer is correct
The correct answer is A. \(x\geq 4\). Multiplying by (6) gives \(5x-4\geq 2x+4+6\). Thus \(3x\geq 14\) and \(x\geq \frac{14}{3}\).
Exam Tip
(6) से गुणा करने पर \(5x-4\geq 2x+4+6\) मिलता है। अतः \(3x\geq 14\) और \(x\geq \frac{14}{3}\) है।
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