Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 391-400 of 584 questions.
What is the solution of \(\frac{x-3}{4}+2>\frac{x}{2}\)?
C. (x<5)
हरों को हटाने पर (x+5>2x) मिलता है। अतः (x<5) सही है। / After clearing denominators, (x+5>2x) is obtained. Therefore (x<5) is correct.
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Choose the solution set of \(0.3x-1.2\le 0.6\).
D. \(x\le 6\)
\(0.3x\le 1.8\) से \(x\le 6\) मिलता है। दशमलव को भिन्न में बदलकर भी हल किया जा सकता है। / From \(0.3x\le 1.8\), we get \(x\le 6\). Decimals can also be converted into fractions.
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Solve the inequality (-4(2x-1)<3(1-x)+5).
A. \(x>-\frac{4}{5}\)
सरलीकरण से (-5x<4) मिलता है। ऋणात्मक से भाग देने पर उत्तर \(x>-\frac{4}{5}\) है। / Simplification gives (-5x<4). Dividing by a negative gives \(x>-\frac{4}{5}\).
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Which is the correct solution of (7-(3x+2)\ge 2x-10)?
B. \(x\le 3\)
सरलीकरण के बाद \(15\ge 5x\) आता है। इसलिए \(x\le 3\) सही है। / After simplification, \(15\ge 5x\) is obtained. Hence \(x\le 3\) is correct.
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What will be the solution set of \(\frac{2x+1}{3}\le \frac{x-4}{2}\)?
A. \(x\le -14\)
(6) से गुणा करने पर \(4x+2\le 3x-12\) मिलता है। इससे \(x\le -14\) आता है। / Multiplying by (6) gives \(4x+2\le 3x-12\). This gives \(x\le -14\).
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If (2(3x-5)-4(x+1)>8), what is the correct condition for (x)?
A. (x>11)
बायाँ पक्ष (2x-14) बनता है। (2x-14>8) से (x>11) मिलता है। / The left side becomes (2x-14). From (2x-14>8), we get (x>11).
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Choose the solution of \(\frac{5x-2}{7}<\frac{3x+8}{14}\).
A. \(x<\frac{12}{7}\)
(14) से गुणा करने पर (10x-4<3x+8) मिलता है। इसलिए (7x<12) और \(x<\frac{12}{7}\)। / Multiplying by (14) gives (10x-4<3x+8). So (7x<12) and \(x<\frac{12}{7}\).
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Solve the inequality \(-\frac{x}{3}+4\le \frac{2x}{5}-1\).
B. \(x\ge \frac{75}{11}\)
हर हटाने पर \(-5x+60\le 6x-15\) मिलता है। इससे \(75\le 11x\), अतः \(x\ge \frac{75}{11}\)। / Clearing denominators gives \(-5x+60\le 6x-15\). Thus \(75\le 11x\), so \(x\ge \frac{75}{11}\).
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What is the solution of (9-2(4x-3)<5(x+2))?
A. \(x>-\frac{5}{13}\)
सरलीकरण से (15-8x<5x+10) मिलता है। इससे (5<13x), इसलिए \(x>\frac{5}{13}\) नहीं बल्कि \(x>\frac{5}{13}\) होता है। / Simplification gives (15-8x<5x+10). This gives (5<13x), so \(x>\frac{5}{13}\).
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Find the solution set of (4x-9\ge 2(1-x)+15).
A. \(x\ge \frac{13}{3}\)
दाएँ पक्ष को सरल करने पर (17-2x) मिलता है। \(4x-9\ge 17-2x\) से \(x\ge \frac{13}{3}\)। / The right side simplifies to (17-2x). From \(4x-9\ge 17-2x\), \(x\ge \frac{13}{3}\).
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