Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 411-420 of 584 questions.
What is the interval-form solution of (11-3x>2x+1)?
A. (x<2)
(10>5x) से (x<2) मिलता है। अंतराल में यह (\(-\infty,2\)) होगा। / From (10>5x), (x<2) is obtained. In interval form, it is (\(-\infty,2\)).
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If (-7x+4<18-2x), then (x) will be greater than what?
A. \(x>-\frac{14}{5}\)
(-5x<14) प्राप्त होता है। ऋणात्मक से भाग देने पर \(x>-\frac{14}{5}\) होगा। / We get (-5x<14). Dividing by a negative gives \(x>-\frac{14}{5}\).
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What is the solution of (2.5(2x-1)\ge 1.5(x+3))?
A. \(x\ge 2\)
सरलीकरण से \(5x-2.5\ge 1.5x+4.5\) मिलता है। इससे \(3.5x\ge 7\), अतः \(x\ge 2\)। / Simplification gives \(5x-2.5\ge 1.5x+4.5\). Thus \(3.5x\ge 7\), so \(x\ge 2\).
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Choose the solution of \(\frac{2x-5}{3}+\frac{x+1}{6}\le 4\).
A. \(x\le \frac{17}{5}\)
हर हटाने पर \(4x-10+x+1\le 24\) मिलता है। अतः \(5x\le 33\), इसलिए \(x\le \frac{33}{5}\)। / Clearing denominators gives \(4x-10+x+1\le 24\). Hence \(5x\le 33\), so \(x\le \frac{33}{5}\).
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What is the solution of (5(x-1)-2(3x+4)<9)?
B. (x<-22)
सरलीकरण से (-x-13<9) मिलता है। इससे (-x<22), इसलिए (x>-22) होना चाहिए। / Simplification gives (-x-13<9). Thus (-x<22), so (x>-22) should result.
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If \(\frac{3-4x}{2}\ge 5-\frac{x}{3}\), what is the solution for (x)?
A. \(x\le -\frac{21}{10}\)
(6) से गुणा करने पर \(9-12x\ge 30-2x\) मिलता है। इससे \(-21\ge 10x\), अतः \(x\le -\frac{21}{10}\)। / Multiplying by (6) gives \(9-12x\ge 30-2x\). Thus \(-21\ge 10x\), so \(x\le -\frac{21}{10}\).
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What is the solution set of \(2-\frac{5x-1}{4}<\frac{x+7}{2}\)?
A. \(x>-\frac{5}{7}\)
(4) से गुणा करने पर (8-(5x-1)<2x+14) मिलता है। इससे (9-5x<2x+14), इसलिए \(x>-\frac{5}{7}\)। / Multiplying by (4) gives (8-(5x-1)<2x+14). Thus (9-5x<2x+14), so \(x>-\frac{5}{7}\).
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Solve the inequality (13+4x\le 2(3x-5)+1).
A. \(x\ge 11\)
दाएँ पक्ष (6x-9) है। \(13+4x\le 6x-9\) से \(22\le 2x\), अतः \(x\ge 11\)। / The right side is (6x-9). From \(13+4x\le 6x-9\), \(22\le 2x\), so \(x\ge 11\).
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Which is the correct solution of (-2(5-x)+3(x-4)>6x+1)?
A. (x<-23)
बायाँ पक्ष (5x-22) बनता है। (5x-22>6x+1) से (x<-23) मिलता है। / The left side becomes (5x-22). From (5x-22>6x+1), we get (x<-23).
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If \(0.75x+\frac{1}{2}<2-\frac{x}{4}\), what is the solution for (x)?
A. \(x<\frac{3}{2}\)
\(0.75x=\frac{3x}{4}\) मानकर हल करें। \(x+\frac{1}{2}<2\) से \(x<\frac{3}{2}\) मिलता है। / Treat (0.75x) as \(\frac{3x}{4}\). From \(x+\frac{1}{2}<2\), \(x<\frac{3}{2}\).
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