असमानता \(-\frac{x}{3}+4\le \frac{2x}{5}-1\) को हल कीजिए।
Solve the inequality \(-\frac{x}{3}+4\le \frac{2x}{5}-1\).
Explanation opens after your attempt
B. \(x\ge \frac{75}{11}\)
Concept
Clearing denominators gives \(-5x+60\le 6x-15\). Thus \(75\le 11x\), so \(x\ge \frac{75}{11}\).
Why this answer is correct
The correct answer is B. \(x\ge \frac{75}{11}\). Clearing denominators gives \(-5x+60\le 6x-15\). Thus \(75\le 11x\), so \(x\ge \frac{75}{11}\).
Exam Tip
हर हटाने पर \(-5x+60\le 6x-15\) मिलता है। इससे \(75\le 11x\), अतः \(x\ge \frac{75}{11}\)।
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