Update
Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है • Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है • Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है
Subjects
Topic Wise MCQ

Mathematics Operations on real numbers and the laws of exponents MCQ Questions for Class 10

Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.

Back to Chapter Subject Page
Share

Start Operations on real numbers and the laws of exponents Topic Quiz

Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.

Easy Test 150 Questions Medium Test 150 Questions Hard Test 150 Questions Expert Test 150 Questions
Topic Navigation

Continue Chapter Revision

Leaderboard

Operations on real numbers and the laws of exponents Practice Questions

Showing 561-570 of 600 questions.

Search
Question 561/600 Expert Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

\(\sqrt{242}-\sqrt{128}+\sqrt{98}-\sqrt{72}\) का सरल रूप क्या है?

What is the simplified form of \(\sqrt{242}-\sqrt{128}+\sqrt{98}-\sqrt{72}\)?

Explanation opens after your attempt
Correct Answer

C. \(4\sqrt{2}\)

Explanation

Simple Explanation

\(\sqrt{242}=11\sqrt{2}\), \(\sqrt{128}=8\sqrt{2}\), \(\sqrt{98}=7\sqrt{2}\), और \(\sqrt{72}=6\sqrt{2}\)। कुल \(4\sqrt{2}\) मिलता है। / We have \(\sqrt{242}=11\sqrt{2}\), \(\sqrt{128}=8\sqrt{2}\), \(\sqrt{98}=7\sqrt{2}\), and \(\sqrt{72}=6\sqrt{2}\). The total is \(4\sqrt{2}\).

Open Question Page
Ask Friends
Question 562/600 Expert Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

यदि \(3^{x}\cdot27^{x-1}=243\), तो (x) का मान क्या है?

If \(3^{x}\cdot27^{x-1}=243\), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (2)

Explanation

Simple Explanation

\(27^{x-1}=3^{3x-3}\), इसलिए कुल घात (x+3x-3=4x-3) है। \(243=3^{5}\), इसलिए (4x-3=5) और (x=2)। / Since \(27^{x-1}=3^{3x-3}\), the total exponent is (x+3x-3=4x-3). Since \(243=3^{5}\), (4x-3=5), so (x=2).

Open Question Page
Ask Friends
Question 563/600 Expert Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

\(\frac{x^{-4}-y^{-4}}{x^{-2}-y^{-2}}\) का सरल रूप क्या है, जहाँ \(x\neq0\), \(y\neq0\), और \(x^{2}\neq y^{2}\)?

What is the simplified form of \(\frac{x^{-4}-y^{-4}}{x^{-2}-y^{-2}}\), where \(x\neq0\), \(y\neq0\), and \(x^{2}\neq y^{2}\)?

Explanation opens after your attempt
Correct Answer

A. \(\frac{x^{2}+y^{2}}{x^{2}y^{2}}\)

Explanation

Simple Explanation

मान लें \(A=x^{-2}\) और \(B=y^{-2}\), तो \(\frac{A^{2}-B^{2}}{A-B}=A+B\)। इसलिए उत्तर \(x^{-2}+y^{-2}=\frac{x^{2}+y^{2}}{x^{2}y^{2}}\) है। / Let \(A=x^{-2}\) and \(B=y^{-2}\). Then \(\frac{A^{2}-B^{2}}{A-B}=A+B\), so the answer is \(x^{-2}+y^{-2}=\frac{x^{2}+y^{2}}{x^{2}y^{2}}\).

Open Question Page
Ask Friends
Question 564/600 Expert Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

यदि \(A=19+6\sqrt{10}\), तो \(\sqrt{A}\) का सरल रूप क्या है?

If \(A=19+6\sqrt{10}\), what is the simplified form of \(\sqrt{A}\)?

Explanation opens after your attempt
Correct Answer

A. \(3+\sqrt{10}\)

Explanation

Simple Explanation

क्योंकि (\(3+\sqrt{10}\)^{2}=9+10+6\sqrt{10}=19+6\sqrt{10}), इसलिए \(\sqrt{A}=3+\sqrt{10}\)। परीक्षा में पूर्ण वर्ग करणी पहचानें। / Because (\(3+\sqrt{10}\)^{2}=9+10+6\sqrt{10}=19+6\sqrt{10}), \(\sqrt{A}=3+\sqrt{10}\). In exams, identify perfect-square surd forms.

Open Question Page
Ask Friends
Question 565/600 Expert Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

(\left\(\frac{8x^{-3}y^{2}}{2x^{5}y^{-4}}\right\)^{2}\cdot\frac{x^{16}}{16y^{12}}) का सरल रूप क्या है?

What is the simplified form of (\left\(\frac{8x^{-3}y^{2}}{2x^{5}y^{-4}}\right\)^{2}\cdot\frac{x^{16}}{16y^{12}})?

Explanation opens after your attempt
Correct Answer

A. (1)

Explanation

Simple Explanation

अंदर \(\frac{8x^{-3}y^{2}}{2x^{5}y^{-4}}=4x^{-8}y^{6}\), इसका वर्ग \(16x^{-16}y^{12}\) है। फिर \(\frac{x^{16}}{16y^{12}}\) से गुणा करने पर (1) मिलता है। / Inside, \(\frac{8x^{-3}y^{2}}{2x^{5}y^{-4}}=4x^{-8}y^{6}\), and its square is \(16x^{-16}y^{12}\). Multiplying by \(\frac{x^{16}}{16y^{12}}\) gives (1).

Open Question Page
Ask Friends
Question 566/600 Expert Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

यदि \(4^{x}+4^{x+1}+4^{x+2}=336\), तो (x) का मान क्या है?

If \(4^{x}+4^{x+1}+4^{x+2}=336\), what is the value of (x)?

Explanation opens after your attempt
Correct Answer

B. (2)

Explanation

Simple Explanation

सामान्य पद \(4^{x}\) लेने पर (4^{x}(1+4+16)=336) मिलता है। इसलिए \(21\cdot4^{x}=336\), \(4^{x}=16\), और (x=2)। / Factoring \(4^{x}\), we get (4^{x}(1+4+16)=336). Thus \(21\cdot4^{x}=336\), \(4^{x}=16\), and (x=2).

Open Question Page
Ask Friends
Question 567/600 Expert Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

(\left\(25^{\frac{3}{2}}\right\)\cdot\left\(125^{-\frac{2}{3}}\right\)) का मान क्या है?

What is the value of (\left\(25^{\frac{3}{2}}\right\)\cdot\left\(125^{-\frac{2}{3}}\right\))?

Explanation opens after your attempt
Correct Answer

B. (5)

Explanation

Simple Explanation

(25^{\frac{3}{2}}=\(5^{2}\)^{\frac{3}{2}}=5^{3}) और (125^{-\frac{2}{3}}=\(5^{3}\)^{-\frac{2}{3}}=5^{-2})। गुणनफल (5) है। / Here (25^{\frac{3}{2}}=\(5^{2}\)^{\frac{3}{2}}=5^{3}) and (125^{-\frac{2}{3}}=\(5^{3}\)^{-\frac{2}{3}}=5^{-2}). The product is (5).

Open Question Page
Ask Friends
Question 568/600 Expert Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

यदि \(r=\sqrt{21}+\sqrt{14}\), तो \(r^{2}-14\sqrt{6}\) का मान क्या है?

If \(r=\sqrt{21}+\sqrt{14}\), what is the value of \(r^{2}-14\sqrt{6}\)?

Explanation opens after your attempt
Correct Answer

C. (35)

Explanation

Simple Explanation

\(r^{2}=21+14+2\sqrt{294}=35+14\sqrt{6}\)। इसलिए \(r^{2}-14\sqrt{6}=35\)। / Since \(r^{2}=21+14+2\sqrt{294}=35+14\sqrt{6}\), \(r^{2}-14\sqrt{6}=35\).

Open Question Page
Ask Friends
Question 569/600 Expert Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

\(\frac{x^{10}-1024}{x^{5}-32}\) का सरल रूप क्या है, जहाँ \(x^{5}\neq32\)?

What is the simplified form of \(\frac{x^{10}-1024}{x^{5}-32}\), where \(x^{5}\neq32\)?

Explanation opens after your attempt
Correct Answer

B. \(x^{5}+32\)

Explanation

Simple Explanation

(x^{10}-1024=\(x^{5}\)^{2}-32^{2}=\(x^{5}-32\)\(x^{5}+32\))। समान गुणनखंड कटने पर \(x^{5}+32\) बचता है। / We use (x^{10}-1024=\(x^{5}\)^{2}-32^{2}=\(x^{5}-32\)\(x^{5}+32\)). Cancelling the common factor leaves \(x^{5}+32\).

Open Question Page
Ask Friends
Question 570/600 Expert Mathematics Polynomials Operations on real numbers and the laws of exponents Class 10 Level 45

\(\frac{1}{\sqrt{26}-5}+\frac{1}{\sqrt{26}+5}\) का मान क्या है?

What is the value of \(\frac{1}{\sqrt{26}-5}+\frac{1}{\sqrt{26}+5}\)?

Explanation opens after your attempt
Correct Answer

A. \(2\sqrt{26}\)

Explanation

Simple Explanation

हरों का गुणनफल (26-25=1) है और अंश (\(\sqrt{26}+5\)+\(\sqrt{26}-5\)=2\sqrt{26}) है। परीक्षा में संयुग्म भिन्नों को साथ जोड़ें। / The product of denominators is (26-25=1), and the numerator is (\(\sqrt{26}+5\)+\(\sqrt{26}-5\)=2\sqrt{26}). In exams, add conjugate fractions together.

Open Question Page
Ask Friends

Operations on real numbers and the laws of exponents Learning Links

Polynomials Chapter

All chapter topics and quizzes

Easy Operations on real numbers and the laws of exponents Test

Topic-wise timed quiz

Mathematics Subject

All chapters and levels

Search Operations on real numbers and the laws of exponents

Find related MCQs