The distance is (1.25-\left\(-2.75\right\)=4) units. In exams, do not miss signs while subtracting negative decimals.
Step 2
Why this answer is correct
The correct answer is B. (4) इकाई / (4) units. The distance is (1.25-\left\(-2.75\right\)=4) units. In exams, do not miss signs while subtracting negative decimals.
Step 3
Exam Tip
दूरी (1.25-\left\(-2.75\right\)=4) इकाई है। परीक्षा में ऋणात्मक दशमलव घटाते समय चिह्न न भूलें।
The distance is (\frac{5}{2}-\left\(-\frac{3}{2}\right\)=4) units. In exams, always take distance as positive.
Step 2
Why this answer is correct
The correct answer is C. (4) इकाई / (4) units. The distance is (\frac{5}{2}-\left\(-\frac{3}{2}\right\)=4) units. In exams, always take distance as positive.
Step 3
Exam Tip
दूरी (\frac{5}{2}-\left\(-\frac{3}{2}\right\)=4) इकाई है। परीक्षा में दूरी हमेशा धनात्मक लें।
A. (1) के बाद तीसरा निशान जब (8) बराबर भाग हों/Third mark after (1) when there are (8) equal parts
Step 1
Concept
\(1+\frac{3}{8}\) is the third of (8) equal parts after (1). In exams, count the fractional parts after the integer.
Step 2
Why this answer is correct
The correct answer is A. (1) के बाद तीसरा निशान जब (8) बराबर भाग हों / Third mark after (1) when there are (8) equal parts. \(1+\frac{3}{8}\) is the third of (8) equal parts after (1). In exams, count the fractional parts after the integer.
Step 3
Exam Tip
\(1+\frac{3}{8}\), (1) के बाद (8) बराबर भागों में तीसरे भाग पर है। परीक्षा में पूर्णांक के बाद भिन्न भाग गिनें।
The denominator of \(\frac{5}{6}\) is (6), so the segment from (0) to (1) has (6) equal parts. In exams, the denominator tells the number of parts.
Step 2
Why this answer is correct
The correct answer is B. (6) भाग / (6) parts. The denominator of \(\frac{5}{6}\) is (6), so the segment from (0) to (1) has (6) equal parts. In exams, the denominator tells the number of parts.
Step 3
Exam Tip
\(\frac{5}{6}\) में हर (6) है, इसलिए (0) से (1) तक (6) बराबर भाग होंगे। परीक्षा में हर भागों की संख्या बताता है।
\(-\frac{17}{5}=-3-\frac{2}{5}\), so it lies between (-4) and (-3). In exams, keep the sign of a negative mixed number correct.
Step 2
Why this answer is correct
The correct answer is B. \(-3-\frac{2}{5}\). \(-\frac{17}{5}=-3-\frac{2}{5}\), so it lies between (-4) and (-3). In exams, keep the sign of a negative mixed number correct.
Step 3
Exam Tip
\(-\frac{17}{5}=-3-\frac{2}{5}\), इसलिए यह (-4) और (-3) के बीच है। परीक्षा में ऋणात्मक मिश्र संख्या का चिह्न ठीक रखें।
\(\frac{13}{4}=3+\frac{1}{4}\), so it lies one-fourth after (3). In exams, convert an improper fraction into a mixed number.
Step 2
Why this answer is correct
The correct answer is A. \(3+\frac{1}{4}\). \(\frac{13}{4}=3+\frac{1}{4}\), so it lies one-fourth after (3). In exams, convert an improper fraction into a mixed number.
Step 3
Exam Tip
\(\frac{13}{4}=3+\frac{1}{4}\), इसलिए यह (3) के बाद एक चौथाई पर होगा। परीक्षा में विषम भिन्न को मिश्र संख्या में बदलें।
\(\sqrt{2}\) lies between (1) and (2), so \(5-\sqrt{2}\) lies between (3) and (4). In exams, change limits carefully while subtracting.
Step 2
Why this answer is correct
The correct answer is B. (3) और (4) / (3) and (4). \(\sqrt{2}\) lies between (1) and (2), so \(5-\sqrt{2}\) lies between (3) and (4). In exams, change limits carefully while subtracting.
Step 3
Exam Tip
\(\sqrt{2}\) (1) और (2) के बीच है, इसलिए \(5-\sqrt{2}\) (3) और (4) के बीच होगा। परीक्षा में घटाने पर सीमा सावधानी से बदलें।
\(\sqrt{3}\) lies between (1) and (2), so \(2+\sqrt{3}\) lies between (3) and (4). In exams, adding a number shifts the whole interval forward.
Step 2
Why this answer is correct
The correct answer is B. (3) और (4) / (3) and (4). \(\sqrt{3}\) lies between (1) and (2), so \(2+\sqrt{3}\) lies between (3) and (4). In exams, adding a number shifts the whole interval forward.
Step 3
Exam Tip
\(\sqrt{3}\) (1) और (2) के बीच है, इसलिए \(2+\sqrt{3}\) (3) और (4) के बीच होगा। परीक्षा में जोड़ने पर पूरा अंतराल आगे खिसकता है।
Since \(\sqrt{18}\) lies between (4) and (5), \(-\sqrt{18}\) lies between (-5) and (-4). In exams, the direction reverses for negative square roots.
Step 2
Why this answer is correct
The correct answer is C. (-5) और (-4) / (-5) and (-4). Since \(\sqrt{18}\) lies between (4) and (5), \(-\sqrt{18}\) lies between (-5) and (-4). In exams, the direction reverses for negative square roots.
Step 3
Exam Tip
क्योंकि \(\sqrt{18}\) (4) और (5) के बीच है, इसलिए \(-\sqrt{18}\) (-5) और (-4) के बीच होगा। परीक्षा में ऋणात्मक वर्गमूल में दिशा उलटी हो जाती है।
Since \(3^2=9\) and \(4^2=16\), \(\sqrt{10}\) lies between (3) and (4). In exams, bracket square roots between perfect squares.
Step 2
Why this answer is correct
The correct answer is B. (3) और (4) / (3) and (4). Since \(3^2=9\) and \(4^2=16\), \(\sqrt{10}\) lies between (3) and (4). In exams, bracket square roots between perfect squares.
Step 3
Exam Tip
क्योंकि \(3^2=9\) और \(4^2=16\), इसलिए \(\sqrt{10}\) (3) और (4) के बीच है। परीक्षा में वर्गमूल को पूर्ण वर्गों से घेरें।
The midpoint is \(\frac{\frac{2}{5}+\frac{4}{5}}{2}=\frac{3}{5}\). To find the exact middle point, take the average of the two points.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{3}{5}\). The midpoint is \(\frac{\frac{2}{5}+\frac{4}{5}}{2}=\frac{3}{5}\). To find the exact middle point, take the average of the two points.
Step 3
Exam Tip
मध्य संख्या \(\frac{\frac{2}{5}+\frac{4}{5}}{2}=\frac{3}{5}\) है। दो बिंदुओं के ठीक बीच के लिए उनका औसत लें।
(AC=|0.75-(-0.5)|=1.25), which is the greatest distance. The farthest points are often the endpoints.
Step 2
Why this answer is correct
The correct answer is C. (A) और (C) / (A) and (C). (AC=|0.75-(-0.5)|=1.25), which is the greatest distance. The farthest points are often the endpoints.
Step 3
Exam Tip
(AC=|0.75-(-0.5)|=1.25), जो सबसे बड़ी दूरी है। सबसे दूर बिंदु अक्सर दोनों सिरों पर होते हैं।
\(\frac{5}{6}\approx0.833\) and \(\frac{7}{8}=0.875\), so \(\frac{7}{8}\) is to the right. Use decimals or cross multiplication to compare.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{7}{8}\). \(\frac{5}{6}\approx0.833\) and \(\frac{7}{8}=0.875\), so \(\frac{7}{8}\) is to the right. Use decimals or cross multiplication to compare.
Step 3
Exam Tip
\(\frac{5}{6}\approx0.833\) और \(\frac{7}{8}=0.875\), इसलिए \(\frac{7}{8}\) दाईं ओर है। तुलना के लिए दशमलव या क्रॉस गुणन करें।
The total distance is (0.8-0.2=0.6) and \(\frac{0.6}{3}=0.2\). Divide total distance by the number of parts for equal sections.
Step 2
Why this answer is correct
The correct answer is B. (0.2). The total distance is (0.8-0.2=0.6) and \(\frac{0.6}{3}=0.2\). Divide total distance by the number of parts for equal sections.
Step 3
Exam Tip
कुल दूरी (0.8-0.2=0.6) है और \(\frac{0.6}{3}=0.2\) है। बराबर भाग के लिए कुल दूरी को भागों से विभाजित करें।
C. \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\) जैसे अनेक बिंदु/Many points like \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\)
Step 1
Concept
Between (0) and (1), there are infinitely many rational and irrational numbers. Between any two real numbers, more numbers can be found.
Step 2
Why this answer is correct
The correct answer is C. \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\) जैसे अनेक बिंदु / Many points like \(\frac{1}{2},\frac{1}{3},\sqrt{\frac{1}{4}}\). Between (0) and (1), there are infinitely many rational and irrational numbers. Between any two real numbers, more numbers can be found.
Step 3
Exam Tip
(0) और (1) के बीच परिमेय और अपरिमेय दोनों प्रकार की अनंत संख्याएं होती हैं। किसी भी दो वास्तविक संख्याओं के बीच और संख्याएं मिलती हैं।
C. यह (3) और (4) के बीच होगा/It will be between (3) and (4)
Step 1
Concept
Since \(3^2<12<4^2\), \(\sqrt{12}\) lies between (3) and (4). A square root can be much smaller than the number.
Step 2
Why this answer is correct
The correct answer is C. यह (3) और (4) के बीच होगा / It will be between (3) and (4). Since \(3^2<12<4^2\), \(\sqrt{12}\) lies between (3) and (4). A square root can be much smaller than the number.
Step 3
Exam Tip
क्योंकि \(3^2<12<4^2\), इसलिए \(\sqrt{12}\) (3) और (4) के बीच है। वर्गमूल संख्या को छोटा कर सकता है।
\(-\frac{3}{5}=-0.6\), so the order is (-0.7<-0.6<-0.2). Among negatives, the farther left number is smaller.
Step 2
Why this answer is correct
The correct answer is B. \(-0.7,-\frac{3}{5},-0.2\). \(-\frac{3}{5}=-0.6\), so the order is (-0.7<-0.6<-0.2). Among negatives, the farther left number is smaller.
Step 3
Exam Tip
\(-\frac{3}{5}=-0.6\), इसलिए क्रम (-0.7<-0.6<-0.2) है। ऋणात्मक संख्याओं में अधिक बाईं संख्या छोटी होती है।
\(\frac{9}{10}=0.9\), whose distance from (1) is (0.1), while (0.95) has distance (0.05). The smaller distance is closer.
Step 2
Why this answer is correct
The correct answer is B. (0.95). \(\frac{9}{10}=0.9\), whose distance from (1) is (0.1), while (0.95) has distance (0.05). The smaller distance is closer.
Step 3
Exam Tip
\(\frac{9}{10}=0.9\), जिसकी (1) से दूरी (0.1) है जबकि (0.95) की दूरी (0.05) है। कम दूरी वाला बिंदु पास होता है।
B. \(\sqrt{3}\) दाईं ओर है/\(\sqrt{3}\) is to the right
Step 1
Concept
Since (3>2), \(\sqrt{3}>\sqrt{2}\). For positive square roots, the root of the larger number is larger.
Step 2
Why this answer is correct
The correct answer is B. \(\sqrt{3}\) दाईं ओर है / \(\sqrt{3}\) is to the right. Since (3>2), \(\sqrt{3}>\sqrt{2}\). For positive square roots, the root of the larger number is larger.
Step 3
Exam Tip
क्योंकि (3>2), इसलिए \(\sqrt{3}>\sqrt{2}\) है। धनात्मक वर्गमूलों में बड़ी संख्या का वर्गमूल बड़ा होता है।
The total length is (2) and there are (8) parts, so each part is \(\frac{2}{8}=\frac{1}{4}\). Divide total length by the number of parts.
Step 2
Why this answer is correct
The correct answer is B. \(\frac{1}{4}\). The total length is (2) and there are (8) parts, so each part is \(\frac{2}{8}=\frac{1}{4}\). Divide total length by the number of parts.
Step 3
Exam Tip
कुल लंबाई (2) है और (8) भाग हैं इसलिए प्रत्येक भाग \(\frac{2}{8}=\frac{1}{4}\) है। बराबर भाग में कुल लंबाई को भागों से बांटें।
Both (2.5) and (-2.5) are (2.5) units from (0). Opposite numbers are equally distant from the origin.
Step 2
Why this answer is correct
The correct answer is A. (2.5) और (-2.5) / (2.5) and (-2.5). Both (2.5) and (-2.5) are (2.5) units from (0). Opposite numbers are equally distant from the origin.
Step 3
Exam Tip
(2.5) और (-2.5) दोनों की (0) से दूरी (2.5) है। विपरीत संख्याएं मूल बिंदु से बराबर दूरी पर होती हैं।