यदि (5,g) विलेय के मोल (0.050) हैं, तो मोलर द्रव्यमान कितना होगा?
If (5,g) solute has (0.050) moles, what is the molar mass?
#molar mass
#molality calculation
#easy
A \(50,g,mol^{-1}\)
B \(75,g,mol^{-1}\)
C \(100,g,mol^{-1}\)
D \(125,g,mol^{-1}\)
Explanation opens after your attempt
Correct Answer
C. \(100,g,mol^{-1}\)
Step 1
Concept
मोलर द्रव्यमान \(=\frac{5}{0.050}\)। / Molar mass \(=\frac{5}{0.050}\).
Step 2
Why this answer is correct
इसका मान \(100,g,mol^{-1}\) है। / Its value is \(100,g,mol^{-1}\).
Step 3
Exam Tip
अंतिम उत्तर में सही इकाई लिखें। / Write the correct unit in the final answer.
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एक विलयन का क्वथनांक उन्नयन (0.52,K) है और \(K_b=0.52,K,kg,mol^{-1}\) है। यदि विलेय अवियोजित है, तो मोललता कितनी होगी?
A solution has boiling point elevation (0.52,K) and \(K_b=0.52,K,kg,mol^{-1}\). If the solute is non-dissociating, what is the molality?
#boiling point elevation
#Kb
#molality calculation
A \(0.25,mol,kg^{-1}\)
B \(0.50,mol,kg^{-1}\)
C \(1.00,mol,kg^{-1}\)
D \(2.00,mol,kg^{-1}\)
Explanation opens after your attempt
Correct Answer
C. \(1.00,mol,kg^{-1}\)
Step 1
Concept
अवियोजित विलेय के लिए \(\Delta T_b=K_bm\) है। / For a non-dissociating solute, \(\Delta T_b=K_bm\).
Step 2
Why this answer is correct
\(m=\frac{0.52}{0.52}=1.00,mol,kg^{-1}\) मिलेगा। / \(m=\frac{0.52}{0.52}=1.00,mol,kg^{-1}\).
Step 3
Exam Tip
यदि (i) नहीं दिया है और विलेय अवियोजित है, तो (i=1) लें। / If (i) is not needed and solute is non-dissociating, take (i=1).
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यदि (0.5) मोल विलेय (250) ग्राम विलायक में घुलता है, तो मोललता कितनी होगी?
If (0.5) mole solute dissolves in (250) gram solvent, what will be the molality?
#molality calculation
#solvent mass
#numerical
A \(0.5\)
B \(1.0\)
C \(2.0\)
D \(4.0\)
Explanation opens after your attempt
Correct Answer
C. \(2.0\)
Step 1
Concept
(250) ग्राम (0.25) किलोग्राम के बराबर है। / (250) gram equals (0.25) kilogram.
Step 2
Why this answer is correct
मोललता \(=\frac{0.5}{0.25}=2.0\) होगी। / Molality \(=\frac{0.5}{0.25}=2.0\).
Step 3
Exam Tip
विलायक का द्रव्यमान किलोग्राम में लेकर ही मोललता निकालें। / Use mass of solvent in kilogram while finding molality.
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यदि \(K_f = 1.86\) और \(\Delta T_f = 0.93\) हो, तो मोललता क्या होगी?
If \(K_f = 1.86\) and \(\Delta T_f = 0.93\), what is the molality?
#freezing point depression
#molality calculation
#Kf
A \(0.25\)
B \(0.5\)
C \(1.0\)
D \(2.0\)
Explanation opens after your attempt
Correct Answer
B. \(0.5\)
Step 1
Concept
\(\Delta T_f = K_fm\) से \(m = \frac{\Delta T_f}{K_f}\)। / From \(\Delta T_f = K_fm\), \(m = \frac{\Delta T_f}{K_f}\).
Step 2
Why this answer is correct
\(\frac{0.93}{1.86} = 0.5\)। / \(\frac{0.93}{1.86} = 0.5\).
Step 3
Exam Tip
संख्या छोटी हो तो भी अनुपात को ध्यान से निकालें। / Calculate the ratio carefully even when numbers are small.
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यदि \(K_b = 0.52\) और \(\Delta T_b = 1.04\) हो, तो अविद्युत अपघट्य विलयन की मोललता क्या होगी?
If \(K_b = 0.52\) and \(\Delta T_b = 1.04\), what is the molality of the non-electrolyte solution?
#boiling point elevation
#molality calculation
#Kb
A \(0.5\)
B \(1.0\)
C \(2.0\)
D \(4.0\)
Explanation opens after your attempt
Correct Answer
C. \(2.0\)
Step 1
Concept
\(\Delta T_b = K_bm\) से \(m = \frac{\Delta T_b}{K_b}\)। / From \(\Delta T_b = K_bm\), \(m = \frac{\Delta T_b}{K_b}\).
Step 2
Why this answer is correct
\(\frac{1.04}{0.52} = 2.0\)। / \(\frac{1.04}{0.52} = 2.0\).
Step 3
Exam Tip
अज्ञात मोललता हो तो सूत्र को पहले व्यवस्थित करें। / Rearrange the formula first when molality is unknown.
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यदि (100) ग्राम जल में (0.1) मोल अविद्युत अपघट्य विलेय घोला जाए, तो मोललता कितनी होगी?
If (0.1) mole non-electrolyte solute is dissolved in (100) gram water, what is the molality?
#molality calculation
#water
#non electrolyte
A \(0.1\)
B \(1.0\)
C \(10\)
D \(100\)
Explanation opens after your attempt
Correct Answer
B. \(1.0\)
Step 1
Concept
(100) ग्राम जल = (0.1) किलोग्राम। / (100) gram water equals (0.1) kilogram.
Step 2
Why this answer is correct
मोललता \(= \frac{0.1}{0.1} = 1.0\)। / Molality \(= \frac{0.1}{0.1} = 1.0\).
Step 3
Exam Tip
ग्राम को किलोग्राम में बदलना सबसे जरूरी कदम है। / Converting gram to kilogram is the key step.
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यदि मोललता (0.4) और \(K_f = 2.0\) हो, तो \(\Delta T_f\) कितना होगा?
If molality is (0.4) and \(K_f = 2.0\), what is \(\Delta T_f\)?
#freezing point depression
#Kf
#molality calculation
A \(0.2\)
B \(0.8\)
C \(2.4\)
D \(5.0\)
Explanation opens after your attempt
Correct Answer
B. \(0.8\)
Step 1
Concept
\(\Delta T_f = K_f m\) प्रयोग करें। / Use \(\Delta T_f = K_f m\).
Step 2
Why this answer is correct
\(2.0 \times 0.4 = 0.8\)। / \(2.0 \times 0.4 = 0.8\).
Step 3
Exam Tip
पहले मोललता सही निकालें, फिर ताप में कमी निकालें। / First find molality correctly, then calculate depression.
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यदि किसी अविद्युत अपघट्य विलेय के (0.1) मोल को (1) किलोग्राम विलायक में घोला जाए, तो मोललता क्या होगी?
If (0.1) mole of a non-electrolyte solute is dissolved in (1) kilogram solvent, what is the molality?
#molality calculation
#colligative properties
#solutions
A \(0.01\)
B \(0.1\)
C \(1.0\)
D \(10\)
Explanation opens after your attempt
Correct Answer
B. \(0.1\)
Step 1
Concept
मोललता = विलेय के मोल / विलायक का किलोग्राम द्रव्यमान। / Molality equals moles of solute divided by kilograms of solvent.
Step 2
Why this answer is correct
\(\frac{0.1}{1} = 0.1\)। / \(\frac{0.1}{1} = 0.1\).
Step 3
Exam Tip
मोललता में विलयन का आयतन नहीं, विलायक का द्रव्यमान लिया जाता है। / Molality uses mass of solvent, not volume of solution.
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यदि \(\Delta T_f = 0.9\) और \(K_f = 1.8\) हो, तो मोललता कितनी होगी?
If \(\Delta T_f = 0.9\) and \(K_f = 1.8\), what is the molality?
#molality calculation
#freezing point
#Kf
A \(0.5\)
B \(2\)
C \(1.62\)
D \(2.7\)
Explanation opens after your attempt
Correct Answer
A. \(0.5\)
Step 1
Concept
\(\Delta T_f = K_f m\) से \(m = \frac{\Delta T_f}{K_f}\)। / From \(\Delta T_f = K_f m\), \(m = \frac{\Delta T_f}{K_f}\).
Step 2
Why this answer is correct
\(\frac{0.9}{1.8} = 0.5\)। / \(\frac{0.9}{1.8} = 0.5\).
Step 3
Exam Tip
भाग करते समय दशमलव को ध्यान से रखें। / Handle decimal values carefully.
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यदि \(\Delta T_b = 1.5\) और \(K_b = 0.5\) हो, तो मोललता कितनी होगी?
If \(\Delta T_b = 1.5\) and \(K_b = 0.5\), what is the molality?
#molality calculation
#boiling point
#Kb
A \(3\)
B \(1\)
C \(0.75\)
D \(2\)
Explanation opens after your attempt
Step 1
Concept
\(\Delta T_b = K_b m\) से \(m = \frac{\Delta T_b}{K_b}\) मिलेगा। / From \(\Delta T_b = K_b m\), \(m = \frac{\Delta T_b}{K_b}\).
Step 2
Why this answer is correct
\(\frac{1.5}{0.5} = 3\)। / \(\frac{1.5}{0.5} = 3\).
Step 3
Exam Tip
अज्ञात मोललता हो तो पहले सूत्र को व्यवस्थित करें। / Rearrange the formula when molality is unknown.
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यदि \(\Delta T_f = 3.6\) और \(K_f = 1.8\) हो, तो मोललता कितनी होगी?
If \(\Delta T_f = 3.6\) and \(K_f = 1.8\), what is the molality?
#molality calculation
#freezing point depression
#Kf
A \(2\)
B \(1\)
C \(5.4\)
D \(0.5\)
Explanation opens after your attempt
Step 1
Concept
\(\Delta T_f = K_f m\) से \(m = \frac{\Delta T_f}{K_f}\)। / From \(\Delta T_f = K_f m\), \(m = \frac{\Delta T_f}{K_f}\).
Step 2
Why this answer is correct
\(\frac{3.6}{1.8} = 2\)। / \(\frac{3.6}{1.8} = 2\).
Step 3
Exam Tip
भाग करते समय ताप परिवर्तन और स्थिरांक के मात्रक संतुलित रखें। / Keep units consistent while dividing.
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यदि \(\Delta T_b = 2\) और \(K_b = 1\) हो, तो मोललता कितनी होगी?
If \(\Delta T_b = 2\) and \(K_b = 1\), what is the molality?
#molality calculation
#boiling point elevation
#solutions
A \(2\)
B \(1\)
C \(0.5\)
D \(3\)
Explanation opens after your attempt
Step 1
Concept
\(\Delta T_b = K_b m\) से \(m = \frac{\Delta T_b}{K_b}\)। / From \(\Delta T_b = K_b m\), \(m = \frac{\Delta T_b}{K_b}\).
Step 2
Why this answer is correct
\(m = \frac{2}{1} = 2\)। / \(m = \frac{2}{1} = 2\).
Step 3
Exam Tip
अज्ञात मोललता हो तो सूत्र को व्यवस्थित करें। / Rearrange the formula when molality is unknown.
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किसी विलयन में विलेय के मोल शून्य दशमलव पाँच और विलायक का द्रव्यमान दो सौ ग्राम है। मोललता कितनी होगी?
A solution contains 0.5 mol solute and 200 g solvent. What is the molality?
#solutions
#concentration metrics
#molality calculation
A 0.1 मोल प्रति किलोग्राम / 0.1 mol kg−1
B 1.0 मोल प्रति किलोग्राम / 1.0 mol kg−1
C 2.5 मोल प्रति किलोग्राम / 2.5 mol kg−1
D 5.0 मोल प्रति किलोग्राम / 5.0 mol kg−1
Explanation opens after your attempt
Correct Answer
C. 2.5 मोल प्रति किलोग्राम / 2.5 mol kg−1
Step 1
Concept
विलायक का द्रव्यमान दो सौ ग्राम यानी शून्य दशमलव दो किलोग्राम है। / Mass of solvent is 200 g or 0.200 kg.
Step 2
Why this answer is correct
मोललता विलेय के मोल बटे विलायक का किलोग्राम द्रव्यमान है। / Molality is moles of solute divided by kg of solvent.
Step 3
Exam Tip
शून्य दशमलव पाँच बटे शून्य दशमलव दो बराबर दो दशमलव पाँच मोल प्रति किलोग्राम है। / 0.5 divided by 0.200 equals 2.5 mol kg−1.
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