Concept-wise Practice

class-10-math MCQ Questions for Class 10

class-10-math se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

2 questions tagged with class-10-math.

समांतर श्रेढ़ी \(6,10,14,18,\ldots\) का (31)वाँ पद क्या होगा?

What will be the (31)st term of the AP \(6,10,14,18,\ldots\)?

Explanation opens after your attempt
Correct Answer

A. (126)

Step 1

Concept

Here (a=6), (d=4), so \(a_{31}=6+30\times4=126\). For the (31)st term, add (30) differences.

Step 2

Why this answer is correct

The correct answer is A. (126). Here (a=6), (d=4), so \(a_{31}=6+30\times4=126\). For the (31)st term, add (30) differences.

Step 3

Exam Tip

यहाँ (a=6), (d=4) है, इसलिए \(a_{31}=6+30\times4=126\)। (31)वें पद के लिए (30) अंतर जोड़ें।

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यदि (a=47) और (b=9), तो (a=bq+r) में (q) और (r) के मान क्या होंगे?

If (a=47) and (b=9), what are the values of (q) and (r) in (a=bq+r)?

Explanation opens after your attempt
Correct Answer

A. (q=5,\ r=2)

Step 1

Concept

The greatest multiple of (9) not exceeding (47) is (45).

Step 2

Why this answer is correct

So \(47=9\times5+2\), giving (q=5) and (r=2).

Step 3

Exam Tip

First find the nearest smaller multiple of the divisor. चरण 1: (47) में (9) का सबसे बड़ा गुणज (45) है। चरण 2: इसलिए \(47=9\times5+2\), यहां (q=5) और (r=2) है। चरण 3: पहले भाजक का निकटतम छोटा गुणज खोजें।

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