Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 211-220 of 600 questions.
Which sequence is an arithmetic progression?
C. \(7,11,15,19,\ldots\)
\(7,11,15,19,\ldots\) में समान अंतर (4) है। समानांतर श्रेढ़ी में लगातार अंतर बराबर होते हैं। / In \(7,11,15,19,\ldots\), the common difference is (4). In an arithmetic progression consecutive differences are equal.
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C. (4)
\(a_4=18+3d=30\) से (3d=12) और (d=4)। चौथे पद तक तीन अंतर होते हैं। / From \(a_4=18+3d=30\), (3d=12) and (d=4). Up to the fourth term there are three gaps.
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What is the (12)th term of the arithmetic progression \(11,17,23,29,\ldots\)?
C. (77)
यहाँ (a=11) और (d=6), इसलिए (a_{12}=11+11(6)=77)। (12)वें पद तक (11) अंतर जुड़ते हैं। / Here (a=11) and (d=6), so (a_{12}=11+11(6)=77). Up to the (12)th term (11) gaps are added.
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If \(a_2=15\) and (d=5), what is \(a_1\)?
B. (10)
\(a_2=a_1+d\) इसलिए \(a_1=15-5=10\)। दूसरा पद दिया हो तो एक समान अंतर पीछे जाएं। / \(a_2=a_1+d\), so \(a_1=15-5=10\). If the second term is given move one common difference backward.
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What will be the (9)th term of the arithmetic progression \(28,24,20,16,\ldots\)?
A. (-4)
यहाँ (a=28) और (d=-4), इसलिए (a_9=28+8(-4)=-4)। घटती श्रेढ़ी में पद ऋणात्मक भी हो सकते हैं। / Here (a=28) and (d=-4), so (a_9=28+8(-4)=-4). In a decreasing progression terms can become negative.
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Which arithmetic progression has first term (6) and common difference (-3)?
C. \(6,3,0,-3,\ldots\)
पहला पद (6) है और हर बार (3) घट रहा है। इसलिए समान अंतर (-3) है। / The first term is (6), and (3) is subtracted each time. Therefore the common difference is (-3).
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If \(a_n=7n-2\), what is the first term?
A. (5)
पहले पद के लिए (n=1), इसलिए \(a_1=7-2=5\)। पहला पद निकालने में (n=1) रखें। / For the first term (n=1), so \(a_1=7-2=5\). Put (n=1) to find the first term.
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In the arithmetic progression \(16,21,26,31,\ldots\), which term is (56)?
C. (9)वाँ(9)th
(16+(n-1)5=56) से (n=9) मिलता है। पद की स्थिति के लिए सरल रैखिक समीकरण हल करें। / From (16+(n-1)5=56), (n=9). Solve the simple linear equation to find the position of a term.
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What is the sum of the first (4) terms of the arithmetic progression \(9,15,21,27,\ldots\)?
B. (72)
पहले (4) पदों का योग (9+15+21+27=72) है। कम पद हों तो सीधे जोड़ना आसान है। / The sum of the first (4) terms is (9+15+21+27=72). If there are few terms direct addition is easy.
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If (a=25) and (d=-5), what will \(a_7\) be?
B. (-5)
(a_7=25+6(-5)=-5)। ऋणात्मक समान अंतर को सही चिह्न के साथ रखें। / (a_7=25+6(-5)=-5). Keep the negative common difference with the correct sign.
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