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In the arithmetic progression (16,21,26,31,\ldots), which term is (56)?

Answer and explanation

Correct answer: 9th

Here, the first term is \(a=16\) and the common difference is \(d=5\). The \(n\)th term is \(a_n=a+(n-1)d\). So, \(16+(n-1)\times5=56\) gives \(n-1=8\), hence \(n=9\). Therefore, 56 is the 9th term. The close distractor, the 8th term, is incorrect because the 8th term is \(16+7\times5=51\). Exam tip: To find the position of a given term in an AP, start with \(a_n=a+(n-1)d\).

Related tags

Arithmetic ProgressionSequences And ProgressionsNth TermTerm PositionLinear EquationMathematicsClass 9 Mcq

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