Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 301-310 of 600 questions.
What is the simplified surd form of \( \sqrt{675} \)?
A. \(15\sqrt{3}\)
\(675=225\times3\) इसलिए \( \sqrt{675}=15\sqrt{3} \)। सबसे बड़ा पूर्ण वर्ग गुणनखंड पहले खोजें। / Since \(675=225\times3\), \( \sqrt{675}=15\sqrt{3} \). First find the largest perfect-square factor.
Login to save your score, XP, coins and progress.
What is obtained by simplifying \( \sqrt{980} \)?
A. \(14\sqrt{5}\)
\(980=196\times5\) इसलिए \( \sqrt{980}=14\sqrt{5} \)। करणी में पूर्ण वर्ग को बाहर निकालें। / Since \(980=196\times5\), \( \sqrt{980}=14\sqrt{5} \). Take the perfect square outside the radical.
Login to save your score, XP, coins and progress.
What is the simplified form of \(2\sqrt{147}-3\sqrt{75}+\sqrt{300}\)?
B. \(8\sqrt{3}\)
\(2\sqrt{147}=14\sqrt{3}\), \(3\sqrt{75}=15\sqrt{3}\), और \( \sqrt{300}=10\sqrt{3} \)। कुल \(9\sqrt{3}\) नहीं बल्कि (14-15+10=9) से \(9\sqrt{3}\) होना चाहिए। / \(2\sqrt{147}=14\sqrt{3}\), \(3\sqrt{75}=15\sqrt{3}\), and \( \sqrt{300}=10\sqrt{3} \). The coefficient is (14-15+10=9), so the value is \(9\sqrt{3}\).
Login to save your score, XP, coins and progress.
Choose the correct simplified form of \(4\sqrt{72}+2\sqrt{200}-5\sqrt{50}\).
A. \(14\sqrt{2}\)
\(4\sqrt{72}=24\sqrt{2}\), \(2\sqrt{200}=20\sqrt{2}\), और \(5\sqrt{50}=25\sqrt{2}\)। इसलिए परिणाम \(19\sqrt{2}\) होना चाहिए। / \(4\sqrt{72}=24\sqrt{2}\), \(2\sqrt{200}=20\sqrt{2}\), and \(5\sqrt{50}=25\sqrt{2}\). Therefore the result should be \(19\sqrt{2}\).
Login to save your score, XP, coins and progress.
What is the value of ( \sqrt{18}\(2\sqrt{8}-\sqrt{50}\) )?
B. ( -6 )
\(2\sqrt{8}=4\sqrt{2}\) और \( \sqrt{50}=5\sqrt{2} \), इसलिए कोष्ठक \( -\sqrt{2} \) है। ( \sqrt{18}\times\(-\sqrt{2}\)=-\sqrt{36}=-6 )। / \(2\sqrt{8}=4\sqrt{2}\) and \( \sqrt{50}=5\sqrt{2} \), so the bracket is \( -\sqrt{2} \). ( \sqrt{18}\times\(-\sqrt{2}\)=-\sqrt{36}=-6 ).
Login to save your score, XP, coins and progress.
What is the expansion of ( \(3\sqrt{2}+2\sqrt{3}\)2 )?
A. \(30+12\sqrt{6}\)
\(a^2+2ab+b^2\) लगाने पर \(18+12\sqrt{6}+12=30+12\sqrt{6}\) मिलता है। मध्य पद को न भूलें। / Using \(a^2+2ab+b^2\), we get \(18+12\sqrt{6}+12=30+12\sqrt{6}\). Do not forget the middle term.
Login to save your score, XP, coins and progress.
What is the simplified form of ( \(5\sqrt{3}-2\sqrt{5}\)2 )?
A. \(95-20\sqrt{15}\)
( \(5\sqrt{3}\)2=75 ) और ( \(2\sqrt{5}\)2=20 ) हैं। मध्य पद \(2\times5\sqrt{3}\times2\sqrt{5}=20\sqrt{15}\) घटेगा। / ( \(5\sqrt{3}\)2=75 ) and ( \(2\sqrt{5}\)2=20 ). The middle term \(2\times5\sqrt{3}\times2\sqrt{5}=20\sqrt{15}\) is subtracted.
Login to save your score, XP, coins and progress.
What is the value of ( \(2\sqrt{7}+\sqrt{5}\)\(2\sqrt{7}-\sqrt{5}\) )?
A. (23)
यह अंतर के वर्ग का रूप है। ( \(2\sqrt{7}\)2-\(\sqrt{5}\)2=28-5=23 )। / This is a difference of squares. ( \(2\sqrt{7}\)2-\(\sqrt{5}\)2=28-5=23 ).
Login to save your score, XP, coins and progress.
What is the rationalised form of \( \frac{1}{3\sqrt{2}+2\sqrt{5}} \)?
B. \( \frac{2\sqrt{5}-3\sqrt{2}}{2} \)
संयुग्मी से गुणा करने पर हर (18-20=-2) मिलता है। इसलिए रूप \( \frac{2\sqrt{5}-3\sqrt{2}}{2} \) लिखा जा सकता है। / Multiplying by the conjugate gives denominator (18-20=-2). So the form can be written as \( \frac{2\sqrt{5}-3\sqrt{2}}{2} \).
Login to save your score, XP, coins and progress.
What is the rationalised form of \( \frac{2}{\sqrt{7}-\sqrt{5}} \)?
A. \( \sqrt{7}+\sqrt{5} \)
संयुग्मी \( \sqrt{7}+\sqrt{5} \) से गुणा करने पर हर (7-5=2) आता है। अंश में भी (2) है इसलिए उत्तर \( \sqrt{7}+\sqrt{5} \) है। / Multiplying by the conjugate \( \sqrt{7}+\sqrt{5} \) gives denominator (7-5=2). The numerator also has (2), so the answer is \( \sqrt{7}+\sqrt{5} \).
Login to save your score, XP, coins and progress.
Use Google login or mobile OTP. Admin can block users and control login providers.