Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 481-490 of 600 questions.
What is the value of (\(\sqrt{31}+\sqrt{12}\)\(\sqrt{31}-\sqrt{12}\))?
B. (19)
यह संयुग्मी गुणन है इसलिए मान (31-12=19) है। \(a^2-b^2\) रूप पहचानें। / This is conjugate multiplication, so the value is (31-12=19). Identify the \(a^2-b^2\) form.
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What is the value of \(\frac{\sqrt{18}+\sqrt{50}}{\sqrt{8}}\)?
B. (4)
\(\sqrt{18}=3\sqrt{2}\), \(\sqrt{50}=5\sqrt{2}\) और \(\sqrt{8}=2\sqrt{2}\) है। इसलिए मान (4) है। / \(\sqrt{18}=3\sqrt{2}\), \(\sqrt{50}=5\sqrt{2}\), and \(\sqrt{8}=2\sqrt{2}\). So the value is (4).
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If \(x=\sqrt{5}+\sqrt{20}+\sqrt{45}\), what is the value of \(x^2\)?
B. (180)
\(\sqrt{20}=2\sqrt{5}\) और \(\sqrt{45}=3\sqrt{5}\), इसलिए \(x=6\sqrt{5}\) है। इसका वर्ग (180) है। / \(\sqrt{20}=2\sqrt{5}\) and \(\sqrt{45}=3\sqrt{5}\), so \(x=6\sqrt{5}\). Its square is (180).
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What is the rationalised form of \(\frac{5}{\sqrt{17}+\sqrt{8}}\)?
A. (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9})
संयुग्मी से गुणा करने पर हर (17-8=9) बनता है। इसलिए रूप (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9}) है। / Multiplying by the conjugate makes the denominator (17-8=9). So the form is (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9}).
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If \(y=\sqrt{14}-\sqrt{7}\), which is the simplified value of \(y^2\)?
A. \(21-14\sqrt{2}\)
(\(\sqrt{14}-\sqrt{7}\)2=14+7-2\sqrt{98}) है। \(\sqrt{98}=7\sqrt{2}\), इसलिए उत्तर \(21-14\sqrt{2}\) है। / (\(\sqrt{14}-\sqrt{7}\)2=14+7-2\sqrt{98}). Since \(\sqrt{98}=7\sqrt{2}\), the answer is \(21-14\sqrt{2}\).
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B. (16)
क्षेत्रफल (\(\sqrt{18}\)2-\(\sqrt{2}\)2=18-2=16) है। संयुग्मी आयाम परिमेय क्षेत्रफल दे सकते हैं। / Area is (\(\sqrt{18}\)2-\(\sqrt{2}\)2=18-2=16). Conjugate dimensions can give rational area.
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If \(u=3\sqrt{2}+\sqrt{98}-\sqrt{50}\), what is the value of \(\frac{u}{\sqrt{2}}\)?
C. (5)
\(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\), इसलिए \(u=5\sqrt{2}\) है। भाग देने पर (5) मिलता है। / \(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so \(u=5\sqrt{2}\). Dividing gives (5).
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What is the value of \(\frac{\sqrt{45}+\sqrt{80}}{\sqrt{5}}\)?
C. (7)
\(\sqrt{45}=3\sqrt{5}\) और \(\sqrt{80}=4\sqrt{5}\), इसलिए अंश \(7\sqrt{5}\) है। \(\sqrt{5}\) से भाग देने पर (7) मिलता है। / \(\sqrt{45}=3\sqrt{5}\) and \(\sqrt{80}=4\sqrt{5}\), so the numerator is \(7\sqrt{5}\). Dividing by \(\sqrt{5}\) gives (7).
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What is the value of (\(\sqrt{11}+\sqrt{3}\)2-\(\sqrt{11}-\sqrt{3}\)2)?
A. \(4\sqrt{33}\)
पहचान ((a+b)2-(a-b)2=4ab) लगाएं। यहाँ मान \(4\sqrt{33}\) है। / Use ((a+b)2-(a-b)2=4ab). Here the value is \(4\sqrt{33}\).
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If \(r=\sqrt{21}+\sqrt{5}\) and \(s=\sqrt{21}-\sqrt{5}\), what is the value of (rs)?
A. (16)
यह संयुग्मी गुणन है। इसलिए (rs=21-5=16) होगा। / This is conjugate multiplication. Therefore (rs=21-5=16).
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