(\(\sqrt{31}+\sqrt{12}\)\(\sqrt{31}-\sqrt{12}\)) का मान क्या है?

What is the value of (\(\sqrt{31}+\sqrt{12}\)\(\sqrt{31}-\sqrt{12}\))?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. (19)

Step 1

Concept

This is conjugate multiplication, so the value is (31-12=19). Identify the \(a^2-b^2\) form.

Step 2

Why this answer is correct

The correct answer is B. (19). This is conjugate multiplication, so the value is (31-12=19). Identify the \(a^2-b^2\) form.

Step 3

Exam Tip

यह संयुग्मी गुणन है इसलिए मान (31-12=19) है। \(a^2-b^2\) रूप पहचानें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

(\(\sqrt{31}+\sqrt{12}\)\(\sqrt{31}-\sqrt{12}\)) का मान क्या है? / What is the value of (\(\sqrt{31}+\sqrt{12}\)\(\sqrt{31}-\sqrt{12}\))?

Correct Answer: B. (19). Explanation: यह संयुग्मी गुणन है इसलिए मान (31-12=19) है। \(a^2-b^2\) रूप पहचानें। / This is conjugate multiplication, so the value is (31-12=19). Identify the \(a^2-b^2\) form.

Which concept should I revise for this Mathematics MCQ?

This is conjugate multiplication, so the value is (31-12=19). Identify the \(a^2-b^2\) form.

What exam hint can help solve this Mathematics question?

यह संयुग्मी गुणन है इसलिए मान (31-12=19) है। \(a^2-b^2\) रूप पहचानें।