\(\frac{5}{\sqrt{17}+\sqrt{8}}\) का परिमेयकृत रूप क्या है?

What is the rationalised form of \(\frac{5}{\sqrt{17}+\sqrt{8}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9})

Step 1

Concept

Multiplying by the conjugate makes the denominator (17-8=9). So the form is (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9}).

Step 2

Why this answer is correct

The correct answer is A. (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9}). Multiplying by the conjugate makes the denominator (17-8=9). So the form is (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9}).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर हर (17-8=9) बनता है। इसलिए रूप (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9}) है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{5}{\sqrt{17}+\sqrt{8}}\) का परिमेयकृत रूप क्या है? / What is the rationalised form of \(\frac{5}{\sqrt{17}+\sqrt{8}}\)?

Correct Answer: A. (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9}). Explanation: संयुग्मी से गुणा करने पर हर (17-8=9) बनता है। इसलिए रूप (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9}) है। / Multiplying by the conjugate makes the denominator (17-8=9). So the form is (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9}).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate makes the denominator (17-8=9). So the form is (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9}).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर हर (17-8=9) बनता है। इसलिए रूप (\frac{5\(\sqrt{17}-\sqrt{8}\)}{9}) है।