यदि \(y=\sqrt{14}-\sqrt{7}\) है, तो \(y^2\) का सरल मान कौन-सा है?
If \(y=\sqrt{14}-\sqrt{7}\), which is the simplified value of \(y^2\)?
Explanation opens after your attempt
A. \(21-14\sqrt{2}\)
Concept
(\(\sqrt{14}-\sqrt{7}\)2=14+7-2\sqrt{98}). Since \(\sqrt{98}=7\sqrt{2}\), the answer is \(21-14\sqrt{2}\).
Why this answer is correct
The correct answer is A. \(21-14\sqrt{2}\). (\(\sqrt{14}-\sqrt{7}\)2=14+7-2\sqrt{98}). Since \(\sqrt{98}=7\sqrt{2}\), the answer is \(21-14\sqrt{2}\).
Exam Tip
(\(\sqrt{14}-\sqrt{7}\)2=14+7-2\sqrt{98}) है। \(\sqrt{98}=7\sqrt{2}\), इसलिए उत्तर \(21-14\sqrt{2}\) है।
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