यदि \(u=3\sqrt{2}+\sqrt{98}-\sqrt{50}\) है, तो \(\frac{u}{\sqrt{2}}\) का मान क्या है?
If \(u=3\sqrt{2}+\sqrt{98}-\sqrt{50}\), what is the value of \(\frac{u}{\sqrt{2}}\)?
Explanation opens after your attempt
Correct Answer
C. (5)
Concept
\(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so \(u=5\sqrt{2}\). Dividing gives (5).
Why this answer is correct
The correct answer is C. (5). \(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{50}=5\sqrt{2}\), so \(u=5\sqrt{2}\). Dividing gives (5).
Exam Tip
\(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{50}=5\sqrt{2}\), इसलिए \(u=5\sqrt{2}\) है। भाग देने पर (5) मिलता है।
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