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In Class 9 Mathematics, the topic Exponents builds on Number Systems by showing how repeated multiplication is represented compactly using powers. Students learn to identify the base and exponent, apply the laws of exponents while multiplying and dividing powers, and work with zero and negative integral exponents. They practise simplifying numerical and algebraic expressions, compare powers, and use exponent notation accurately to express very large or very small numbers.
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Hard · Level 6 · exponents,number systems,laws of exponents, powersView options
100
1000
125
40
Hard · Level 6 · exponents,number systems,order of operations,powersView options
71
81
91
101
Hard · Level 6 · exponents,number systems,squares,arithmetic operationsView options
144
169
194
124
Hard · Level 6 · number systems, exponents, negative exponents, exponent laws, class 9 mathematicsView options
\(a^{-n}=\frac{1}{a^n}\)
\(a^{-n}=-a^n\)
\(a^{-n}=\frac{1}{a^{-n}}\)
\(a^{-n}=a^n-1\)
Hard · Level 6 · exponents,number systems,exponent laws,simplificationView options
15
3
9
45
Hard · Level 6 · exponents,number systems,laws of exponents,powers,grade 9 mathematicsView options
256
1024
512
2048
Hard · Level 6 · exponents,number systems,powers,arithmetic operationsView options
211
243
264
275
Hard · Level 6 · number systems,exponents,laws of exponents,simplification,class 9 mathematicsView options
5
25
125
625
Hard · Level 6 · number systems,exponents,powers,arithmetic operations,class 9 mathematicsView options
64
72
80
96
Hard · Level 6 · exponents,difference of squares,number systems,algebraic identitiesView options
96
196
100
296
Hard · Level 6 · exponents,number systems,quotient rule,powersView options
Hard · Level 6 · exponents,powers,power of a power,number systems,class 9 mathematicsView options
3125
15625
625
78125
Hard · Level 6 · exponents,number systems,laws of exponents,division of powers,simplificationView options
4
8
16
64
Hard · Level 6 · exponents,number systems,order of operations,powersView options
175
165
185
195
Hard · Level 6 · exponents,number systems,squares,arithmetic operationsView options
169
179
159
189
Hard · Level 6 · exponents,number systems,integer operations,order of operationsView options
909
919
929
939
Hard · Level 6 · exponents,number systems,evaluation of powers,arithmetic operationsView options
369
389
379
399
Hard · Level 6 · exponents,number systems,powers,arithmeticView options
240
250
260
169
Hard · Level 6 · number systems,exponents,laws of exponents,division of powersView options
4
8
16
32
Question 1HardLevel 6
What is the value of (2^3 \times 5^3)?
Correct answer: B
Using the product rule for equal exponents, \(a^n \times b^n=(ab)^n\). Thus, \(2^3 \times 5^3=(2\times5)^3=10^3=1000\), so option B is correct. Exam tip: When the exponents are equal, multiply the bases first and then apply the common exponent.
First evaluate the powers: 7^2 = 49 and 2^5 = 32. Adding them gives 49 + 32 = 81, so option B is correct. Exam tip: evaluate exponents before performing the addition.
Evaluate the powers first: \(13^2=169\) and \(5^2=25\). Therefore, \(13^2-5^2=169-25=144\), so option A is correct. Exam tip: calculate both squares before subtracting; option B is only the value of \(13^2\), not of the complete expression.
For a non-zero number \(a\) and a positive integer \(n\), which is the correct rule for a negative exponent?
Correct answer: A
Since \(a^n\times a^{-n}=a^{n-n}=a^0=1\), \(a^{-n}\) is the reciprocal of \(a^n\). Hence it equals \(\frac{1}{a^n}\), not \(-a^n\). Exam tip: convert a negative exponent into a reciprocal first.
Using the law \(\frac{a^n}{b^n}=\left(\frac{a}{b}\right)^n\) for equal exponents, \(\frac{15^2}{5^2}=\left(\frac{15}{5}\right)^2=3^2=9\). Therefore, 9 is correct. Exam tip: When the exponents are the same, divide the bases first and then apply the exponent.
For powers with the same base, the exponents are added: \(2^3\times2^2=2^{3+2}=2^5\). Then \((2^5)^2=2^{5\times2}=2^{10}=1024\). Therefore, option B is correct. Option C, 512, equals \(2^9\) and may result from applying the outer exponent incorrectly. Exam tip: remember \(a^m\times a^n=a^{m+n}\) and \((a^m)^n=a^{mn}\).
First evaluate the two powers: \(3^5=243\) and \(2^5=32\). Therefore, \(3^5+2^5=243+32=275\), so option D is correct. Option B is only the value of \(3^5\), not the complete expression. Exam tip: Evaluate each power separately before performing the addition.
Using the quotient rule for equal powers, \((25^2 \div 5^2)=(25\div 5)^2=5^2=25\). Therefore, option B is correct. Option A is only the quotient of the bases and misses the required squaring step. In an exam, remember the rule \(a^n\div b^n=(a\div b)^n\) when the exponents are equal.
Evaluate the powers first: 2^4=16 and 4^3=64. Therefore, 2^4+4^3=16+64=80, so option C is correct. In an exam, remember to calculate each power before performing the addition; 72 may result from an error in evaluating the powers.
First calculate the two squares: 14^2 = 196 and 10^2 = 100. Therefore, 14^2 - 10^2 = 196 - 100 = 96. This can also be verified using the difference-of-squares identity: a^2 - b^2 = (a-b)(a+b) = (14-10)(14+10) = 4 × 24 = 96. Exam tip: Use the difference-of-squares identity to simplify such expressions quickly.
Using the quotient rule for equal exponents, \(a^n \div b^n=(a\div b)^n\). Therefore, \(8^3\div2^3=(8\div2)^3=4^3=64\). Hence, 64 is correct. Exam tip: do not confuse \(8^3\div2^3\) with \(8\div2^3\); the placement of the exponent changes the expression.
First evaluate the powers: 2^7 = 128 and 2^4 = 16. Therefore, 2^7 - 2^4 = 128 - 16 = 112, so option D is correct. Remember that the exponent subtraction rule cannot be applied directly here because the terms are being subtracted; evaluate the two powers first.
Using the exponent rule \((a^m)^n=a^{mn}\), \((5^3)^2=5^{3\times2}=5^6=15625\). Therefore, 15625 is the correct answer. 3125 equals \(5^5\) and may result from handling the exponents incorrectly. Exam tip: when a power is raised to another power, multiply the exponents.
For division of numbers with the same exponent, use
\((a^n \div b^n)=(a\div b)^n\). Thus,
\((16^2 \div 4^2)=(16\div4)^2=4^2=16\). Therefore, option C is correct. Exam tip: when the exponents are equal, divide the bases first and then apply the common exponent.
First evaluate the powers: 11^2 = 121 and 2^6 = 64. Therefore, 11^2 + 2^6 = 121 + 64 = 185, so option C is correct. Exam tip: Evaluate each exponent separately before performing the addition to avoid calculation errors.
First evaluate the powers: 12^2=144 and 5^2=25. Therefore, 12^2+5^2=144+25=169, so option A is correct. In an exam, calculate each square separately before adding; 179 represents a likely arithmetic error in the addition.
Evaluate the powers first: \(10^3=1000\) and \(9^2=81\). Therefore, \(10^3-9^2=1000-81=919\), so option B is correct. Exam tip: calculate the powers before performing the subtraction.
First evaluate the powers: 7^3 = 7 × 7 × 7 = 343 and 6^2 = 6 × 6 = 36. Therefore, 7^3 + 6^2 = 343 + 36 = 379, so option C is correct. In an exam, calculate each power separately before adding to avoid errors.
13^2 = 13 × 13 = 169 and 3^4 = 3 × 3 × 3 × 3 = 81. Therefore (13^2 + 3^4) = 169 + 81 = 250. Option A (240) is incorrect — it likely arises from an arithmetic mistake (for example, computing 3^4 incorrectly). Exam tip: evaluate each power separately, then add and recheck the addition to avoid simple errors.
When powers with the same base are divided, their exponents are subtracted: \(2^9 \div 2^6=2^{9-6}=2^3=8\). Therefore, option B is correct. Exam tip: for division with the same base, subtract the exponents rather than adding them.
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