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In Class 9 Mathematics, the topic Exponents builds on Number Systems by showing how repeated multiplication is represented compactly using powers. Students learn to identify the base and exponent, apply the laws of exponents while multiplying and dividing powers, and work with zero and negative integral exponents. They practise simplifying numerical and algebraic expressions, compare powers, and use exponent notation accurately to express very large or very small numbers.
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Medium · Level 5 · exponents,integer operations,order of operations,number systems,mental arithmeticView options
590
600
610
1089
Medium · Level 5 · number systems,exponents,squares,square roots,positive rootView options
18
16
14
12
Medium · Level 5 · exponents, squares, arithmetic operations, number systems, mental calculationView options
1225
1245
1250
1260
Medium · Level 5 · exponents,number systems,squares,arithmetic operations,subtractionView options
500
550
650
600
Medium · Level 5 · exponents,number systems,powers,order of operations,class 9 mathematicsView options
81
91
101
71
Medium · Level 5 · number systems,exponents,cubes,cube roots,perfect cubesView options
6
7
8
9
Medium · Level 5 · exponents,integer operations,squares,order of operationsView options
900
950
1100
1000
Medium · Level 5 · exponents, laws of exponents, number systems, division of powers, class 9 mathematicsView options
49
14
343
7
Medium · Level 5 · exponents,order of operations,squares,integer arithmetic,number systemsView options
900
1100
1200
1000
Medium · Level 5 · number systems,exponents,square roots,perfect squares,quadratic equationsView options
21
19
23
25
Medium · Level 5 · exponents,powers,number-systems,arithmetic,mental-calculationView options
1008
1024
16
1000
Medium · Level 5 · exponents,integer operations,squares,subtraction,number systemsView options
900
1100
1200
1000
Medium · Level 5 · exponents,laws of exponents,division of powers,number systems,grade 9 mathematicsView options
Medium · Level 6 · exponents, laws of exponents, number systems, powers, class 9 mathematicsView options
8
4
16
64
Medium · Level 6 · number systems,exponents,square roots,quadratic equations,positive rootView options
14
12
16
18
Question 1MediumLevel 5
What is the value of (33^2-489)?
Correct answer: B
First evaluate the exponent: \(33^2 = 33 \times 33 = 1089\). Then \(1089 - 489 = 600\). Therefore, the correct answer is 600. The value 1089 is only \(33^2\); the subtraction of 489 must still be performed. Exam tip: In a mixed expression, evaluate exponents before addition or subtraction.
If (d^2=324) then what is the positive value of (d)?
Correct answer: A
Since the square root of 324 is 18, the possible values of d are 18 and -18. As the question asks for the positive value, d = 18 is correct. Option 16 is not correct because 16² = 256, not 324. Exam tip: When the positive value is asked in d² = n, take the positive square root of n.
First find the square of 35: 35² = 1225. Adding 25 gives 1225 + 25 = 1250. Therefore, 1250 is the correct answer. Option 1225 is only the value of 35²; it does not include the added 25. Exam tip: evaluate the exponent first, then perform addition or subtraction.
First find the square of 36: \(36^2=36\times36=1296\). Then \(1296-696=600\), so the correct answer is 600. The option 650 can result from an error in subtraction. Exam tip: after finding a square, verify the subtraction using column subtraction or a quick mental check.
Evaluate the powers first: \(2^6=64\) and \(3^3=27\). Therefore, \(2^6+3^3=64+27=91\). Hence, 91 is the correct answer. An option such as 81 does not result from correctly evaluating and adding both powers. Exam tip: In such expressions, calculate exponents before performing addition or subtraction.
Given x^3=512. Since 8^3=8×8×8=512, x=8. Option 7 is not correct because 7^3=343. Exam tip: Memorising cubes of numbers from 1 to 10 helps solve such questions quickly.
First find the square of 38: \(38^2=38\times38=1444\). Then, \(1444-444=1000\), so the correct answer is 1000. An answer such as 900 can result from an error in finding the square or in subtraction. Exam tip: In an expression with brackets, evaluate the exponent (square) before performing subtraction.
When powers with the same base are divided, subtract the exponents: \(7^4 \div 7^2 = 7^{4-2} = 7^2 = 49\). Therefore, 49 is correct. 343 is \(7^3\), so it does not result here. Exam tip: use \(a^m \div a^n = a^{m-n}\) only when the non-zero bases are the same.
First evaluate the exponent: \(40^2 = 40 \times 40 = 1600\). Then \(1600 - 600 = 1000\). Therefore, the correct answer is 1000. An option such as 1100 may result from an error in subtraction. Exam tip: In an expression with brackets, calculate the exponent before performing subtraction.
If (y^2=441) then what is the positive value of (y)?
Correct answer: A
Since 21 × 21 = 441, the positive square root of 441 is 21. Although the equation y² = 441 has two solutions, 21 and −21, the question asks for the positive value, so 21 is correct. The close distractor 19 is incorrect because 19² = 361. Exam tip: when the positive value is asked in y² = a, take √a.
Compute powers: \(4^5=1024\) and \(4^2=16\), so \(1024-16=1008\). Why other options are wrong: 1024 corresponds to forgetting the subtraction step; 16 is just \(4^2\) alone; 1000 is a rounded estimate. Exam tip: factor out \(4^2\): \(4^5-4^2=4^2(4^3-1)=16(64-1)=16\times63=1008\), which helps avoid large subtraction errors.
First find the square of 42: 42² = 1764. Subtracting 764 from 1764 gives 1000. Therefore, the correct answer is 1000. An option such as 1100 may result from an error in subtraction at the hundreds place. Exam tip: In an expression with exponents, evaluate the exponent first and then perform addition or subtraction.
When powers with the same base are divided, subtract their exponents: \(9^4 \div 9^2 = 9^{4-2}=9^2=81\). Therefore, 81 is correct. The option 9 is only \(9^1\), so it is not correct. Exam tip: use \(a^m \div a^n=a^{m-n}\), where \(a\ne0\).
Since 9 × 9 × 9 = 729, we get z = 9. The cube of 8 is 512, so 8 is not correct. Exam tip: verify a perfect cube by multiplying the number by itself three times.
First find the square of 44: \(44^2=1936\). Then \(1936-936=1000\). Therefore, the correct answer is 1000. Option 900 may result from an error in subtraction. Exam tip: evaluate exponents before performing addition or subtraction.
Here, \(2^3=2\times2\times2=8\) and \(3^2=3\times3=9\). Therefore, \(2^3\times3^2=8\times9=72\). Option 64 is the value of \(2^6\), so it is not correct. Exam tip: Evaluate each exponential term separately before multiplying.
Evaluate the powers first: 2^6 = 64 and 2^3 = 8. Therefore, 64 + 8 = 72, so 72 is correct. The option 64 is only the value of 2^6; it does not include the addition of 2^3. Exam tip: In an expression with exponents, evaluate each power before performing addition or subtraction.
Here, 3^5 = 243 and 3^2 = 9. Therefore, 3^5 - 3^2 = 243 - 9 = 234. Hence, option B is correct. The value 244 may result from an incorrect subtraction by 10. Exam tip: Evaluate each power separately before performing subtraction.
When powers with the same base are divided, subtract the exponents: \(4^4 \div 4^2 = 4^{4-2} = 4^2 = 16\). Therefore, 16 is the correct answer. 64 equals \(4^3\), which may result from subtracting the exponents incorrectly. Exam tip: use \(a^m \div a^n = a^{m-n}\), where \(a \ne 0\).
If (x^2=196) then what is the positive value of (x)?
Correct answer: A
Given \(x^2=196\), we get \(x=\pm\sqrt{196}=\pm14\). Since the question asks for the positive value of \(x\), the answer is \(14\). The close distractor \(12\) is incorrect because \(12^2=144\), not 196. Exam tip: For \(x^2=a\), there are usually two values, \(\pm\sqrt a\); select only the positive one when asked.
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