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If (x^2=196) then what is the positive value of (x)?

Answer and explanation

Correct answer: 14

Given \(x^2=196\), we get \(x=\pm\sqrt{196}=\pm14\). Since the question asks for the positive value of \(x\), the answer is \(14\). The close distractor \(12\) is incorrect because \(12^2=144\), not 196. Exam tip: For \(x^2=a\), there are usually two values, \(\pm\sqrt a\); select only the positive one when asked.

Related tags

Number SystemsExponentsSquare RootsQuadratic EquationsPositive RootMathematicsClass 9 Mcq

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