Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
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Showing 161-170 of 650 questions.
What is considered the degree of the zero polynomial (0)?
C. परिभाषित नहींNot defined
शून्य बहुपद की डिग्री परिभाषित नहीं होती। इसे अशून्य नियतांक बहुपद से अलग रखें। / The degree of the zero polynomial is not defined. Keep it separate from a non-zero constant polynomial.
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After simplifying \(3x^5+2x^5-4x^2+8\), what is the degree?
C. (5)
सरल रूप \(5x^5-4x^2+8\) है। इसमें सबसे बड़ी घात (5) है। / The simplified form is \(5x^5-4x^2+8\). Its highest power is (5).
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If \(r\neq0\), what will be the degree of \(rx^7+3x^2-10\)?
C. (7)
\(r\neq0\) होने से \(x^7\) पद मौजूद रहेगा। इसलिए सबसे बड़ी घात (7) है। / Since \(r\neq0\), the \(x^7\) term remains present. Therefore the highest power is (7).
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If (r=0), what will be the degree of \(rx^7+3x^2-10\)?
C. (2)
(r=0) होने पर \(x^7\) पद हट जाता है। बची हुई सबसे बड़ी घात (2) है। / When (r=0), the \(x^7\) term disappears. The remaining highest power is (2).
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What is the degree of the polynomial \(4y^5-3y^2+8\)?
C. (5)
चर (y) की सबसे बड़ी घात (5) है। इसलिए बहुपद की डिग्री (5) है। / The highest power of the variable (y) is (5). Therefore the degree of the polynomial is (5).
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With respect to (x), what is the degree of \(5y^2-3y+1\)?
C. (0)
(x) के संदर्भ में यह अशून्य नियतांक जैसा है। इसलिए इसकी डिग्री (0) है। / With respect to (x), it behaves like a non-zero constant. Therefore its degree is (0).
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If the degree of (p(x)=\(m^2-4\)x-5+6x-3+1) is (3), which can be a possible value of (m)?
B. (m=2)
डिग्री (3) के लिए \(x^5\) का गुणांक (0) होना चाहिए। \(m^2-4=0\) से \(m=\pm2\) मिलता है। / For degree (3), the coefficient of \(x^5\) must be (0). From \(m^2-4=0\), \(m=\pm2\).
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What will be the degree after expanding (2x-4\(3x^2-1\))?
C. (6)
फैलाने पर \(6x^6-2x^4\) मिलता है। सबसे बड़ी घात (6) है। / On expanding, we get \(6x^6-2x^4\). The highest power is (6).
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After simplifying (x-2\(x^3+1\)-x-5+4x), what is the degree?
C. (2)
(x-2\(x^3+1\)=x-5+x-2) और \(x^5\) कट जाता है। बचा \(x^2+4x\) है जिसकी डिग्री (2) है। / (x-2\(x^3+1\)=x-5+x-2), and \(x^5\) cancels. The remaining \(x^2+4x\) has degree (2).
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What is the degree of the polynomial (\(x^2+1\)\(x^3-2\))?
C. (5)
गुणन में सबसे बड़ी घात \(x^2\cdot x^3=x^5\) से आती है। इसलिए डिग्री (5) है। / In multiplication, the highest power comes from \(x^2\cdot x^3=x^5\). Therefore the degree is (5).
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