Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
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Showing 641-650 of 650 questions.
If (a=10) and (b=15) in \(6x^a+8x^b+1\), what is the degree?
B. (15)
(a=10) और (b=15) रखने पर घातें (10), (15), और (0) हैं। सबसे बड़ी घात (15) है। / Putting (a=10) and (b=15), the powers are (10), (15), and (0). The highest power is (15).
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Which option does not have degree (9)?
D. \(x^9-x^9+12x^6\)
अंतिम विकल्प सरल होकर \(12x^6\) बनता है। इसलिए उसकी डिग्री (6) है, (9) नहीं। / The last option simplifies to \(12x^6\). Therefore its degree is (6), not (9).
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If (p(x)=x-7\(x^3+x\)-x^{10}-x-8+59), what is the degree of (p(x))?
C. (0)
(x-7\(x^3+x\)=x^{10}+x-8) है और दोनों चर पद कट जाते हैं। बचा (59) है जिसकी डिग्री (0) है। / (x-7\(x^3+x\)=x^{10}+x-8), and both variable terms cancel. The remaining (59) has degree (0).
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What is the degree of (x-7(x-6)2)?
C. (9)
((x-6)2) की डिग्री (2) है और बाहर \(x^7\) है। कुल उच्चतम घात (7+2=9) होगी। / ((x-6)2) has degree (2), and there is \(x^7\) outside. The total highest power is (7+2=9).
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If the degree of ((r+12)x^{12}+(r+12)x-5+26) is (0), what is the value of (r)?
B. (r=-12)
डिग्री (0) के लिए दोनों चर पद हटने चाहिए। (r+12=0) से (r=-12) मिलता है। / For degree (0), both variable terms must vanish. From (r+12=0), we get (r=-12).
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C. (17)
अशून्य बहुपदों के गुणन में डिग्री सामान्यतः जुड़ती है। इसलिए (9+8=17) होगा। / For the product of non-zero polynomials, degrees generally add. Therefore (9+8=17).
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What is the total degree of \(x^8y^2+x^6y^9+xy\)?
B. (15)
\(x^6y^9\) की कुल घात (6+9=15) है। यह सबसे बड़ी कुल घात है। / The total power of \(x^6y^9\) is (6+9=15). This is the highest total power.
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For which value will (\(u^2-196\)x^{15}+(u-14)x-8+13) have degree (0)?
A. (u=14)
डिग्री (0) के लिए \(x^{15}\) और \(x^8\) दोनों पद हटने चाहिए। (u=14) पर दोनों गुणांक (0) हैं। / For degree (0), both \(x^{15}\) and \(x^8\) terms must vanish. At (u=14), both coefficients are (0).
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If (F(x)=7x^{13}-7x^{13}+8x-9-8x-9+10x-6-5), what is the degree of (F(x))?
C. (6)
\(x^{13}\) और \(x^9\) के पद कट जाते हैं। बचा \(10x^6-5\) है जिसकी डिग्री (6) है। / The \(x^{13}\) and \(x^9\) terms cancel. The remaining \(10x^6-5\) has degree (6).
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If (V(x)=\(x^8+5x^4\)2-x^{16}-10x^{12}+3x-7), what is the degree of (V(x))?
C. (8)
(\(x^8+5x^4\)2=x^{16}+10x^{12}+25x-8) होता है। बड़े पद कटने के बाद \(25x^8+3x^7\) बचता है जिसकी डिग्री (8) है। / (\(x^8+5x^4\)2=x^{16}+10x^{12}+25x-8). After higher terms cancel, \(25x^8+3x^7\) remains, whose degree is (8).
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