यदि (p(x)=x-7\(x^3+x\)-x^{10}-x-8+59), तो (p(x)) की डिग्री क्या है?
If (p(x)=x-7\(x^3+x\)-x^{10}-x-8+59), what is the degree of (p(x))?
Explanation opens after your attempt
C. (0)
Concept
(x-7\(x^3+x\)=x^{10}+x-8), and both variable terms cancel. The remaining (59) has degree (0).
Why this answer is correct
The correct answer is C. (0). (x-7\(x^3+x\)=x^{10}+x-8), and both variable terms cancel. The remaining (59) has degree (0).
Exam Tip
(x-7\(x^3+x\)=x^{10}+x-8) है और दोनों चर पद कट जाते हैं। बचा (59) है जिसकी डिग्री (0) है।
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