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In Class 9 Mathematics, under the chapter Exploring Algebraic Identities, students use geometric diagrams and area-based representations to understand algebraic identities visually. They relate squares and rectangles formed from algebraic expressions to expansions such as binomial products, helping them see why both sides of an identity are equal rather than merely memorising formulas.
TOPIC PRACTICE
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Hard · Level 67 · visual-proof,same-area,identityView options
Both areas are equal
The first area is always greater
The second area is always zero
They are areas of different figures
Hard · Level 67 · minus-square,perfect-square,visual-recognitionView options
Square with side (x+3)
Square with side (x-3)
Square with side (x-6)
Square with side (x+9)
Hard · Level 67 · complete-square,small-corner,area-modelView options
Model of a square with side (x+6)
Model of a square with side (x+12)
Rectangle with dimensions (x+3) and (x+9)
Rectangle with dimensions (x-6) and (x+6)
Hard · Level 67 · numeric-visual,difference-of-squares,rectangle-areaView options
(119)
(144)
(169)
(100)
Hard · Level 67 · missing-middle,complete-square,error-analysisView options
Because the two middle (6x) rectangles are missing
Because (36) is not a square
Because (x^2) is not an area
Because (x) is always (6)
Hard · Level 67 · signed-factors,constant-corner,rectangle-modelView options
Positive (21)
Negative (21)
Positive (10x)
Negative (10x)
Hard · Level 67 · perfect-square,area-model,minus-binomialView options
(5a+3b)
(25a-9b)
(5a-3b)
(10a-6b)
Hard · Level 67 · three-term-square,cross-rectangles,visual-countingView options
(3)
(4)
(5)
(6)
Hard · Level 67 · factor-model,signed-rectangle,visual-factorizationView options
((x+4)(x-3))
((x-4)(x-3))
((x+6)(x-2))
((x+12)(x-1))
Hard · Level 67 · cross-rectangles,dimension-check,visual-modelView options
(2x+5) and (3x+3)
(2x+3) and (3x+5)
(6x+10) and (x+15)
(x+6) and (x+10)
Hard · Level 67 · factorization,area-rectangle,number-partsView options
(4) and (10)
(5) and (9)
(2) and (20)
(6) and (8)
Hard · Level 67 · signed-expansion,cross-terms,rectangle-modelView options
(14x)
(4x)
(-4x)
(-45x)
Hard · Level 67 · perfect-square,visual-square,two-variableView options
(8x+5y)
(64x-25y)
(8x-5y)
(16x-10y)
Hard · Level 67 · area-difference,two-squares,visual-identityView options
Two squares with sides (x+4) and (x-4)
One rectangle with only side (x+4)
Two equal squares with side (x)
One circle and one square
Hard · Level 67 · difference-of-squares,visual-transformation,areaView options
(8x)
(16x)
(x^2-16)
(x^2+16)
Hard · Level 67 · general-model,binomial-square,rectanglesView options
(ax)
(2ax)
(x^2+a^2)
(2a^2x)
Hard · Level 67 · sign-change,plus-minus-square,visual-comparisonView options
(4x^2)
(9y^2)
Middle term (12xy)
Both square terms
Hard · Level 67 · difference-of-squares,area-rectangle,visual-factorizationView options
((6x+1)(6x-1))
((36x+1)(36x-1))
((6x+1)(x-1))
((18x+1)(18x-1))
Hard · Level 67 · student-error,binomial-square,visual-modelView options
The student counted (x^2) twice
The student omitted two (2x) rectangles
The student made (4) negative
The student took side (x-2)
Hard · Level 67 · area-comparison,remaining-rectangles,visual-identityView options
Only the area of two (5x) rectangles remains from the complete square
(x^2) also remains from the complete square
The square (25) remains from the complete square
No area remains
Question 1HardLevel 67
In a visual proof, the same large square area is written as ((a+b)^2) and (a^2+2ab+b^2). What is the conclusion?
Correct answer: A
The area of the same figure is written in two ways, so the expressions are equal. Exam tip: remember the same-area principle in visual proofs.
If (6x) and (10x) are two cross rectangles and the corner is (15), what can be the outer dimensions of the rectangle?
Correct answer: B
In ((2x+3)(3x+5)), (2x\times5=10x) and (3\times3x=9x), so it does not match; ((2x+5)(3x+3)) also gives corner (15) but cross terms (6x) and (15x). Thus no option fully matches.
If the outer dimensions in a rectangle model are (x-5) and (x+9), what will be the total area of the (x)-rectangles?
Correct answer: B
The outer dimensions are \\(x-5\\) and \\(x+9\\). In the visual expansion, multiplying these dimensions produces four parts: \\(x\cdot x=x^2\\), \\(x\cdot9=9x\\), \\((-5)\cdot x=-5x\\), and \\((-5)\cdot9=-45\\). The question asks only for the total area of the rectangles containing an \\(x\\) factor, so the two cross terms must be combined.
Their total is \\(9x+(-5x)=4x\\), making option B correct. The signs matter: the negative width contributes \\(-5x\\), not \\(5x\\). Option A incorrectly adds the magnitudes and gives \\(14x\\), while option C reverses the sign. The constant corner \\(-45\\) is not part of the requested total because it has no \\(x\\) factor.
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