In a square of side \(x+7\), the small corner square is \(7^2\). What is its area?
The small square has side \(7\), so its area is \(7^2=49\). Exam tip: treat the square of the number as the constant term.
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SubjectsMathematics
सर्वसमिकाओं के दृश्य मॉडल
In Class 9 Mathematics, under the chapter Exploring Algebraic Identities, students use geometric diagrams and area-based representations to understand algebraic identities visually. They relate squares and rectangles formed from algebraic expressions to expansions such as binomial products, helping them see why both sides of an identity are equal rather than merely memorising formulas.
TOPIC PRACTICE
Up to 20 questions from this page. Select your focus, then start.
The small square has side \(7\), so its area is \(7^2=49\). Exam tip: treat the square of the number as the constant term.
View question detailsThe whole area is the sum of all four regions: \(x^2+5x+5x+25\). Combining like terms, \(5x+5x=10x\), gives \(x^2+10x+25\). This is also \((x+5)^2\). Option A misses one \(5x\) region. Exam tip: In an area model, add every small region and then combine like terms.
View question detailsA square of side \(x+2\) can be divided into one \(x\times x\) square, two \(x\times2\) rectangles, and one \(2\times2\) small square. Therefore, its total area is \(x^2+2x+2x+4=x^2+4x+4\). Option B includes the area of only one \(2x\) rectangle. Exam tip: use \((a+b)^2=a^2+2ab+b^2\).
View question details\((x-4)^2=x^2-2 \times x \times 4+16=x^2-8x+16\). Exam tip: take care of the negative middle term.
View question detailsThe big square has side \(50\), so its area is \(50^2=2500\). Exam tip: start with the large square.
View question detailsIn the visual model of \((50-1)^2\), each side of the small square is \(1\), so its area is \(1^2\). \(2 \times 50 \times 1\) represents the total area of two rectangular strips, not the small square. Exam tip: in the model of \((a-b)^2\), the small square always has area \(b^2\).
View question detailsThe area model has four parts with areas \(x^2\), \(3x\), \(3x\), and \(9\). Combining like terms gives \(3x+3x=6x\), so the expansion is \(x^2+6x+9\). Option A misses one \(3x\) part. Exam tip: verify using \((a+b)^2=a^2+2ab+b^2\).
View question detailsIn an area model, areas of smaller parts are added to get total area. Exam tip: add the parts in such questions.
View question details\((a+b)^2\) is an addition model while \((a-b)^2\) is a subtraction model. Exam tip: identify the model from the sign.
View question detailsThe given area is \(p^2+2pq+q^2=(p+q)^2\). Since the area of a square equals the square of its side, the side of the whole square is \(p+q\). Note that \((p-q)^2=p^2-2pq+q^2\), which has a negative middle term. Exam tip: recognise the identity \(a^2+2ab+b^2=(a+b)^2\) quickly.
View question detailsSplitting the square into two smaller squares and two rectangles gives \(a^2+2ab+b^2\). Exam tip: connect square area with the identity.
View question detailsThe area model has \(x^2\), two \(3x\) rectangles, and \(9\). Exam tip: the middle term comes from two equal rectangles.
View question detailsThe smaller area \(b^2\) is subtracted from the larger area \(a^2\). Exam tip: treat the removed part as subtraction.
View question detailsThe rectangle area is \((a+b)(a-b)\), which equals \(a^2-b^2\). Exam tip: multiply length and breadth.
View question detailsIn \((x-2)^2\), there is \(x^2\), two subtracted \(2x\) parts, and \(4\) added. Exam tip: watch the negative sign.
View question detailsThe total area of a divided square is found by adding the areas of all its non-overlapping parts. The four given parts are one region of area \\(p^2\\), two regions each of area \\(pq\\), and one region of area \\(q^2\\). Since the two \\(pq\\) regions have equal areas, together they contribute \\(pq+pq=2pq\\). Adding every part gives \\(p^2+pq+pq+q^2=p^2+2pq+q^2\\). Therefore, option B is correct. This is also the familiar identity \\( (p+q)^2=p^2+2pq+q^2\\), representing the area of a square whose side is \\(p+q\\).
The important point is that a diagram must be counted completely, including both middle rectangular parts. Option A leaves out the two \\(pq\\) regions, so it is incomplete. Option C has the signs used in the identity for \\( (p-q)^2\\), which does not match the stated positive parts. Option D, \\(2p+2q\\), represents a length such as a perimeter expression in a suitable setting, not an area made from square units. Thus the sum of the four areas leads unambiguously to option B.
The square parts are \(m^2\) and \(n^2\), and if \(m>n\), then \(m^2\) is larger. Exam tip: distinguish square and rectangular parts.
View question detailsThe \(x\) by \(x\) square has area \(x^2\). The two \(x\) by \(5\) rectangles together have area \(5x+5x=10x\), and the \(5\) by \(5\) square has area \(25\). Thus, the total area is \(x^2+10x+25=(x+5)^2\). In contrast, \((x-5)^2\) has the middle term \(-10x\), so it does not match. Exam tip: add the areas of the two equal rectangles first to identify the middle term.
View question detailsUsing \((a-b)^2=a^2-2ab+b^2\), put \(a=y\) and \(b=4\): \((y-4)^2=y^2-2(y)(4)+4^2=y^2-8y+16\). The two \(4y\) rectangles together give \(-8y\), and the added small square is \(4^2=16\). Option B has a positive middle term, so it represents \((y+4)^2\). Exam tip: in the square of a difference, the middle term is negative.
View question detailsIn \((6+2)^2\), \(6^2\), two \(6\times2\) parts, and \(2^2\) are added. Exam tip: understand the identity using numerical models.
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