एक \(x+7\) भुजा वाले वर्ग में छोटे कोने का वर्ग \(7^2\) है। उस छोटे वर्ग का क्षेत्रफल कितना है?
In a square of side \(x+7\), the small corner square is \(7^2\). What is its area?
Explanation opens after your attempt
C. \(49\)
Concept
The small square has side \(7\), so its area is \(7^2=49\). Exam tip: treat the square of the number as the constant term.
Why this answer is correct
The correct answer is C. \(49\). The small square has side \(7\), so its area is \(7^2=49\). Exam tip: treat the square of the number as the constant term.
Exam Tip
छोटे वर्ग की भुजा \(7\) है इसलिए क्षेत्रफल \(7^2=49\) होगा। परीक्षा में संख्या के वर्ग को स्थिर पद समझें।
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