In a rectangle model (x^2+2x-15) must be shown using two binomial sides. Which sides are correct?
(5\cdot -3=-15) and (5+(-3)=2) so the sides are (x+5) and (x-3). Exam tip: check both product and sum.
View question detailsMuft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है
SubjectsMathematics
सर्वसमिकाओं के दृश्य मॉडल
In Class 9 Mathematics, under the chapter Exploring Algebraic Identities, students use geometric diagrams and area-based representations to understand algebraic identities visually. They relate squares and rectangles formed from algebraic expressions to expansions such as binomial products, helping them see why both sides of an identity are equal rather than merely memorising formulas.
TOPIC PRACTICE
Up to 20 questions from this page. Select your focus, then start.
(5\cdot -3=-15) and (5+(-3)=2) so the sides are (x+5) and (x-3). Exam tip: check both product and sum.
View question detailsThe governing concept is the visual form of the identity (p + q)² = p² + 2pq + q². A square whose side is divided into lengths p and q contains one p-by-p square, two p-by-q rectangles, and one q-by-q square. Here p = 2a and q = 5. The first square has area (2a)² = 4a². Each rectangle has area (2a)(5) = 10a, so the two rectangles together have area 20a. The final small square has area 5² = 25. Therefore the model shows 4a², 20a, and 25, so option B is correct. Option A counts only one rectangle; C gives an incorrect first area; and D gives an incorrect constant and middle contribution.
View question detailsThe area of a square is found by multiplying its side by itself. For a side of \\(5x-1\\), use the identity \\((a-b)^2=a^2-2ab+b^2\\), with \\(a=5x\\) and \\(b=1\\). The expansion is \\(25x^2-10x+1\\). The middle term is therefore \\(-10x\\), which comes from the two cross-products of the large part and the one-unit strip.
Option B is correct. The negative sign appears because the side is \\(5x-1\\), so the strips are removed rather than added. Option A would be the middle term for \\((5x+1)^2\\), not for the given side. The terms \\(-5x\\) and \\(25x\\) do not represent the required cross-term. Hence the visual model and the algebraic identity give the same answer.
The large square has side \(a+b\), so its area is \((a+b)^2\). Adding its parts gives \(a^2+ab+ab+b^2=a^2+2ab+b^2\). Exam tip: always count both \(ab\) rectangles.
View question detailsThe ((a+b)^2) model has two equal (ab) rectangles. Exam tip: understand (2ab) as two separate rectangles.
View question details(16=4^2) so (x^2-16) is a difference of squares model. Exam tip: view the constant term as a square.
View question detailsThe four parts are (m^2) (2m) (8m) and (16) so the total is (m^2+10m+16). Exam tip: add all parts.
View question detailsWhen two strips are removed the corner is removed twice so it must be added back. Exam tip: treat (+b^2) as a correction term.
View question details(14x) is formed by two equal strips (7x) and (7x). Exam tip: split the middle term into two equal parts.
View question details(9=3^2) and (6x=2\cdot x\cdot 3) so the side is (x-3). Exam tip: the negative sign indicates a removed model.
View question detailsThe area of a rectangle is the product of its side lengths: \((2x+1)(2x-1)\). This matches \((a+b)(a-b)=a^2-b^2\), where \(a=2x\) and \(b=1\). Hence, the area is \((2x)^2-1^2=4x^2-1\). The expression \(4x^2+1\) does not apply the difference-of-squares identity correctly. Exam tip: when two binomials differ only in the middle sign, look for the difference of squares.
View question detailsThe model for \((p+q)^2\) has squares of areas \(p^2\) and \(q^2\), along with two rectangles, each measuring \(p\times q\). Hence the two \(pq\) rectangles have equal area. The squares need not be equal. Exam tip: identify the middle term as \(2pq\).
View question detailsThe product of (-4) and (-5) is (20) and the sum is (-9). Exam tip: two negative terms give a positive constant term.
View question detailsThe area of the square is \((a+2b)^2\). Using \((x+y)^2=x^2+2xy+y^2\), take \(x=a\) and \(y=2b\). The middle term is \(2\times a\times 2b=4ab\). \(2ab\) is incorrect because it does not fully include the coefficient 2 in \(2b\). Exam tip: the middle term in a binomial square is twice the product of the two terms.
View question details(16p^2=(4p)^2) and (9=3^2) with middle term (-24p) so ((4p-3)^2) is correct. Exam tip: identify the first and last squares.
View question detailsThis is a product of sum and difference so ((3x)^2-2^2=9x^2-4). Exam tip: look for the same first part and opposite second part.
View question detailsSplitting a square of side \(a+b\) gives areas \(a^2\), \(ab\), \(ab\), and \(b^2\). Their sum is \(a^2+2ab+b^2\). \(a^2-b^2\) represents a difference, not this complete square model. Exam tip: count both \(ab\) rectangles.
View question detailsThe constant part of a product comes from multiplying the terms that do not contain the variable. The rectangle has sides \\(x-2\\) and \\(x+6\\). Its area is \\( (x-2)(x+6)\\). The constant terms are \\(-2\\) and \\(6\\), so their product is \\((-2)(6)=-12\\). Therefore, the constant part is \\(-12\\), and option B is correct. The negative sign is essential because the first side contains \\(-2\\), not \\(2\\).
For a complete check, distribute the factors: \\(x\cdot x=x^2\\), \\(x\cdot6=6x\\), \\((-2)\cdot x=-2x\\), and \\((-2)\cdot6=-12\\). Thus the full product is \\(x^2+4x-12\\), whose constant term is indeed \\(-12\\). Option A would result from incorrectly treating \\(-2\\) as positive. Options C and D do not come from multiplying the two constant terms. In an area model, the bottom-right constant rectangle has signed area \\(-12\\), so its sign must be retained.
The small square is (81=9^2) and the two strips give (9x+9x=18x). Exam tip: identify the small side from half of the middle term.
View question detailsThe remaining area is (a^2-b^2) and after rearrangement it becomes ((a-b)(a+b)). Exam tip: connect the removed square with difference of squares.
View question detailsQUIZ COMPLETE