Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 581-590 of 600 questions.
A. एक अद्वितीय हलOne unique solution
यहां (7/4 \ne 5/(-3)), इसलिए रेखाएं कटती हैं। ऐसे युग्म का एक अद्वितीय हल होता है। / Here (7/4 \ne 5/(-3)), so the lines intersect. Such a pair has one unique solution.
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What is the relation among all three ratios in the equations (11x+18y=86) and (33x+54y=258)?
A. तीनों बराबर हैंAll three are equal
यहां (11/33=18/54=86/258)। इसलिए दोनों समीकरण एक ही रेखा बनाते हैं। / Here (11/33=18/54=86/258). Therefore, both equations form the same line.
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Which relation is correct for the equations (18x+27y=126) and (2x+3y=16)?
C. (182=27 / 3 \ne 126 / 16)
पहले दो अनुपात बराबर हैं लेकिन स्थिर पद का अनुपात अलग है। इसलिए कोई हल नहीं है। / The first two ratios are equal but the constant ratio is different. Therefore, there is no solution.
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Which statement is correct for the equations (12x+13y=55) and (24x+25y=107)?
B. (1224 \ne 13 / 25), इसलिए एक अद्वितीय हल / 25), so one unique solution
यहां \(12/24 \ne 13/25\), इसलिए रेखाएं कटती हैं। इस कारण एक अद्वितीय हल है। / Here \(12/24 \ne 13/25\), so the lines intersect. Therefore, there is one unique solution.
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What should (s) be for the equations (9x+16y=77) and (27x+48y=s) to be consistent and dependent?
C. (231)
संगत और आश्रित होने के लिए दूसरा समीकरण पहले का (3) गुना होना चाहिए। अतः (s=231)। / To be consistent and dependent, the second equation must be (3) times the first. Hence, (s=231).
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Which condition is correct for the equations (13x+8y=49) and (26x+16y=r) to be inconsistent?
B. \(r\ne98\)
पहले दो अनुपात बराबर हैं। असंगत होने के लिए स्थिर पद का अनुपात अलग होना चाहिए इसलिए \(r\ne98\)। / The first two ratios are equal. For inconsistency, the constant ratio must be different so \(r\ne98\).
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What will (a) be for the equations (10x+9y=38) and (20x+ay=91) to have no solution?
C. (18)
कोई हल नहीं के लिए (10/20=9/a) और (38/91) अलग होना चाहिए। इससे (a=18) मिलता है। / For no solution, (10/20=9/a) and (38/91) must be different. This gives (a=18).
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What will (k) be for the equations (12x+ky=132) and (3x+10y=33) to have infinitely many solutions?
C. (40)
पहला समीकरण दूसरे का (4) गुना होना चाहिए। इसलिए (k=40) है। / The first equation must be (4) times the second. Therefore, (k=40).
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If (lx+17y=68) and (20x+34y=139) have no solution, what will be the value of (l)?
C. (10)
कोई हल नहीं के लिए (l/20=17/34) और (68/139) अलग होना चाहिए। इसलिए (l=10)। / For no solution, (l/20=17/34) and (68/139) must be different. Hence, (l=10).
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Which statement is correct by observing the equations (18x+13y=89) and (36x+26y=178)?
B. रेखाएं एक ही हैंLines are the same
दूसरा समीकरण पहले का (2) गुना है। इसलिए दोनों रेखाएं एक ही हैं। / The second equation is (2) times the first. Therefore, both lines are the same.
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