A. (x=2,\ y=11) और (x=4,\ y=1)/(x=2,\ y=11) and (x=4,\ y=1)
Step 1
Concept
At (x=2), (y=11), and at (x=4), (y=1). Every point in the value table must satisfy the equation.
Step 2
Why this answer is correct
The correct answer is A. (x=2,\ y=11) और (x=4,\ y=1) / (x=2,\ y=11) and (x=4,\ y=1). At (x=2), (y=11), and at (x=4), (y=1). Every point in the value table must satisfy the equation.
Step 3
Exam Tip
(x=2) पर (y=11) और (x=4) पर (y=1)। मान-सारणी का हर बिंदु समीकरण को संतुष्ट करना चाहिए।
A. बिंदु (\left\(\frac{79}{19},\frac{113}{19}\right\))/Point (\left\(\frac{79}{19},\frac{113}{19}\right\))
Step 1
Concept
Using (y=6x-19) from the first equation gives \(x=\frac{79}{19}\). Then \(y=\frac{113}{19}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{79}{19},\frac{113}{19}\right\)) / Point (\left\(\frac{79}{19},\frac{113}{19}\right\)). Using (y=6x-19) from the first equation gives \(x=\frac{79}{19}\). Then \(y=\frac{113}{19}\).
Step 3
Exam Tip
पहले समीकरण से (y=6x-19) रखकर \(x=\frac{79}{19}\) मिलता है। फिर \(y=\frac{113}{19}\) है।
A. बिंदु (\left\(\frac{25}{7},\frac{37}{7}\right\))/Point (\left\(\frac{25}{7},\frac{37}{7}\right\))
Step 1
Concept
Using (y=4x-9) from (4x-y=9) gives \(x=\frac{25}{7}\). Then \(y=\frac{37}{7}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{25}{7},\frac{37}{7}\right\)) / Point (\left\(\frac{25}{7},\frac{37}{7}\right\)). Using (y=4x-9) from (4x-y=9) gives \(x=\frac{25}{7}\). Then \(y=\frac{37}{7}\).
Step 3
Exam Tip
(4x-y=9) से (y=4x-9) रखकर \(x=\frac{25}{7}\) मिलता है। फिर \(y=\frac{37}{7}\) है।
A. (x=1,\ y=12) और (x=3,\ y=4)/(x=1,\ y=12) and (x=3,\ y=4)
Step 1
Concept
At (x=1), (y=12), and at (x=3), (y=4). Every point in the value table must satisfy the equation.
Step 2
Why this answer is correct
The correct answer is A. (x=1,\ y=12) और (x=3,\ y=4) / (x=1,\ y=12) and (x=3,\ y=4). At (x=1), (y=12), and at (x=3), (y=4). Every point in the value table must satisfy the equation.
Step 3
Exam Tip
(x=1) पर (y=12) और (x=3) पर (y=4)। मान-सारणी का हर बिंदु समीकरण को संतुष्ट करना चाहिए।
A. बिंदु (\left\(\frac{42}{11},\frac{67}{11}\right\))/Point (\left\(\frac{42}{11},\frac{67}{11}\right\))
Step 1
Concept
Using (y=5x-13) from the first equation gives \(x=\frac{42}{11}\). Then \(y=\frac{67}{11}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{42}{11},\frac{67}{11}\right\)) / Point (\left\(\frac{42}{11},\frac{67}{11}\right\)). Using (y=5x-13) from the first equation gives \(x=\frac{42}{11}\). Then \(y=\frac{67}{11}\).
Step 3
Exam Tip
पहले समीकरण से (y=5x-13) रखकर \(x=\frac{42}{11}\) मिलता है। फिर \(y=\frac{67}{11}\) है।
A. बिंदु (\left\(\frac{65}{17},\frac{65}{17}\right\))/Point (\left\(\frac{65}{17},\frac{65}{17}\right\))
Step 1
Concept
Using (x=23-5y) from (x+5y=23) gives \(y=\frac{65}{17}\). Then \(x=\frac{65}{17}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{65}{17},\frac{65}{17}\right\)) / Point (\left\(\frac{65}{17},\frac{65}{17}\right\)). Using (x=23-5y) from (x+5y=23) gives \(y=\frac{65}{17}\). Then \(x=\frac{65}{17}\).
Step 3
Exam Tip
(x+5y=23) से (x=23-5y) रखकर \(y=\frac{65}{17}\) मिलता है। फिर \(x=\frac{65}{17}\) है।
A. (x=2,\ y=1) और (x=4,\ y=7)/(x=2,\ y=1) and (x=4,\ y=7)
Step 1
Concept
At (x=2), (6-y=5) gives (y=1), and at (x=4), (12-y=5) gives (y=7). Every table point must satisfy the equation.
Step 2
Why this answer is correct
The correct answer is A. (x=2,\ y=1) और (x=4,\ y=7) / (x=2,\ y=1) and (x=4,\ y=7). At (x=2), (6-y=5) gives (y=1), and at (x=4), (12-y=5) gives (y=7). Every table point must satisfy the equation.
Step 3
Exam Tip
(x=2) पर (6-y=5) से (y=1), और (x=4) पर (12-y=5) से (y=7)। मान-सारणी का हर बिंदु समीकरण को संतुष्ट करे।
A. बिंदु (\left\(\frac{18}{7},\frac{23}{7}\right\))/Point (\left\(\frac{18}{7},\frac{23}{7}\right\))
Step 1
Concept
The first equation gives (x=2y-4). Substituting in (3x+y=11) gives \(y=\frac{23}{7}\) and \(x=\frac{18}{7}\).
Step 2
Why this answer is correct
The correct answer is A. बिंदु (\left\(\frac{18}{7},\frac{23}{7}\right\)) / Point (\left\(\frac{18}{7},\frac{23}{7}\right\)). The first equation gives (x=2y-4). Substituting in (3x+y=11) gives \(y=\frac{23}{7}\) and \(x=\frac{18}{7}\).
Step 3
Exam Tip
पहले समीकरण से (x=2y-4) मिलता है। इसे (3x+y=11) में रखने पर \(y=\frac{23}{7}\) और \(x=\frac{18}{7}\) है।
A. (x=2,\ y=2) और (x=3,\ y=5)/(x=2,\ y=2) and (x=3,\ y=5)
Step 1
Concept
At (x=2), (6-y=4) gives (y=2), and at (x=3), (9-y=4) gives (y=5). Every table point must satisfy the equation.
Step 2
Why this answer is correct
The correct answer is A. (x=2,\ y=2) और (x=3,\ y=5) / (x=2,\ y=2) and (x=3,\ y=5). At (x=2), (6-y=4) gives (y=2), and at (x=3), (9-y=4) gives (y=5). Every table point must satisfy the equation.
Step 3
Exam Tip
(x=2) पर (6-y=4) से (y=2), और (x=3) पर (9-y=4) से (y=5)। तालिका के हर बिंदु को समीकरण संतुष्ट करना चाहिए।
A. क्योंकि (2(0)+3(0)\ne18)/Because (2(0)+3(0)\ne18)
Step 1
Concept
Substituting the origin ( (0,0) ) gives left side (0), not (18). Check passing through origin by direct substitution.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि (2(0)+3(0)\ne18) / Because (2(0)+3(0)\ne18). Substituting the origin ( (0,0) ) gives left side (0), not (18). Check passing through origin by direct substitution.
Step 3
Exam Tip
मूलबिंदु ( (0,0) ) रखने पर बायाँ पक्ष (0) आता है, (18) नहीं। मूलबिंदु से गुजरने की जाँच सीधे प्रतिस्थापन से करें।
A. (x=2,\ y=1) और (x=3,\ y=3)/(x=2,\ y=1) and (x=3,\ y=3)
Step 1
Concept
At (x=2), (4-y=3) gives (y=1), and at (x=3), (6-y=3) gives (y=3). Table points must satisfy the equation.
Step 2
Why this answer is correct
The correct answer is A. (x=2,\ y=1) और (x=3,\ y=3) / (x=2,\ y=1) and (x=3,\ y=3). At (x=2), (4-y=3) gives (y=1), and at (x=3), (6-y=3) gives (y=3). Table points must satisfy the equation.
Step 3
Exam Tip
(x=2) पर (4-y=3) से (y=1), और (x=3) पर (6-y=3) से (y=3)। मान-सारणी के बिंदु समीकरण को संतुष्ट करने चाहिए।
A. क्योंकि (2(0)+3(0)\ne6)/Because (2(0)+3(0)\ne6)
Step 1
Concept
Substituting the origin ( (0,0) ) gives left side (0), not (6). Check whether a line passes through origin by substitution.
Step 2
Why this answer is correct
The correct answer is A. क्योंकि (2(0)+3(0)\ne6) / Because (2(0)+3(0)\ne6). Substituting the origin ( (0,0) ) gives left side (0), not (6). Check whether a line passes through origin by substitution.
Step 3
Exam Tip
मूलबिंदु ( (0,0) ) रखने पर बायाँ पक्ष (0) आता है, (6) नहीं। किसी रेखा के मूलबिंदु से गुजरने की जाँच substitution से करें।
