\(2x^2+5x-3=0\) के मूल क्या हैं?
What are the roots of \(2x^2+5x-3=0\)?
#quadratic
#factorisation
#standard-form
A \(x=\frac{1}{2},-3\)
B \(x=-\frac{1}{2},3\)
C (x=2,-3)
D \(x=3,-\frac{1}{2}\)
Explanation opens after your attempt
Correct Answer
A. \(x=\frac{1}{2},-3\)
Step 1
Concept
(2x-2 +5x-3=(2x-1)(x+3)), so \(x=\frac{1}{2}\) and (-3). In exams, write fractional roots correctly.
Step 2
Why this answer is correct
The correct answer is A. \(x=\frac{1}{2},-3\). (2x-2 +5x-3=(2x-1)(x+3)), so \(x=\frac{1}{2}\) and (-3). In exams, write fractional roots correctly.
Step 3
Exam Tip
(2x-2 +5x-3=(2x-1)(x+3)), इसलिए \(x=\frac{1}{2}\) और (-3) हैं। परीक्षा में भिन्न मूल को सही लिखें।
Login to save your score, XP, coins and progress. Login
\(x^2-2x-15=0\) को हल करने के लिए सही गुणनखंड रूप क्या है?
What is the correct factorised form to solve \(x^2-2x-15=0\)?
#quadratic
#factorisation
#mixed-signs
A ((x-5)(x+3)=0)
B ((x+5)(x-3)=0)
C ((x-15)(x+1)=0)
D ((x+15)(x-1)=0)
Explanation opens after your attempt
Correct Answer
A. ((x-5)(x+3)=0)
Step 1
Concept
(-5+3=-2) and \(-5\times3=-15\), so ((x-5)(x+3)) is correct. In exams, match both product and sum.
Step 2
Why this answer is correct
The correct answer is A. ((x-5)(x+3)=0). (-5+3=-2) and \(-5\times3=-15\), so ((x-5)(x+3)) is correct. In exams, match both product and sum.
Step 3
Exam Tip
(-5+3=-2) और \(-5\times3=-15\), इसलिए ((x-5)(x+3)) सही है। परीक्षा में गुणनफल और योग दोनों मिलाएं।
Login to save your score, XP, coins and progress. Login
\(3x^2-2x-1=0\) के मूल कौनसे हैं?
Which are the roots of \(3x^2-2x-1=0\)?
#quadratic
#factorisation
#fraction-roots
A \(x=1,-\frac{1}{3}\)
B \(x=-1,\frac{1}{3}\)
C (x=3,-1)
D \(x=\frac{1}{3},-1\)
Explanation opens after your attempt
Correct Answer
A. \(x=1,-\frac{1}{3}\)
Step 1
Concept
(3x-2 -2x-1=(3x+1)(x-1)), so the roots are (1) and \(-\frac{1}{3}\). In exams, form mixed-sign factors carefully.
Step 2
Why this answer is correct
The correct answer is A. \(x=1,-\frac{1}{3}\). (3x-2 -2x-1=(3x+1)(x-1)), so the roots are (1) and \(-\frac{1}{3}\). In exams, form mixed-sign factors carefully.
Step 3
Exam Tip
(3x-2 -2x-1=(3x+1)(x-1)), इसलिए मूल (1) और \(-\frac{1}{3}\) हैं। परीक्षा में मिश्रित चिन्ह वाले गुणनखंड सावधानी से बनाएं।
Login to save your score, XP, coins and progress. Login
\(2x^2-7x+3=0\) को गुणनखंड विधि से हल करने पर मूल क्या हैं?
What are the roots of \(2x^2-7x+3=0\) by factorisation method?
#quadratic
#factorisation
#medium
A \(x=3,\frac{1}{2}\)
B \(x=-3,-\frac{1}{2}\)
C (x=2,3)
D \(x=\frac{3}{2},1\)
Explanation opens after your attempt
Correct Answer
A. \(x=3,\frac{1}{2}\)
Step 1
Concept
(2x-2 -7x+3=(2x-1)(x-3)), so (x=3) and \(x=\frac{1}{2}\). In exams, solve each linear factor separately.
Step 2
Why this answer is correct
The correct answer is A. \(x=3,\frac{1}{2}\). (2x-2 -7x+3=(2x-1)(x-3)), so (x=3) and \(x=\frac{1}{2}\). In exams, solve each linear factor separately.
Step 3
Exam Tip
(2x-2 -7x+3=(2x-1)(x-3)), इसलिए (x=3) और \(x=\frac{1}{2}\) हैं। परीक्षा में रैखिक गुणनखंड को अलग-अलग हल करें।
Login to save your score, XP, coins and progress. Login
\(25x^2-1=0\) का सही गुणनखंड रूप कौनसा है?
What is the correct factorised form of \(25x^2-1=0\)?
#quadratic
#difference-of-squares
#factorisation
A ((5x-1)(5x+1)=0)
B ((25x-1)(x+1)=0)
C ((5x-1)2 =0)
D ((x-1)(25x+1)=0)
Explanation opens after your attempt
Correct Answer
A. ((5x-1)(5x+1)=0)
Step 1
Concept
(25x-2 -1=(5x)2 -12 ), so ((5x-1)(5x+1)=0) is correct. In exams, quickly identify the difference of squares.
Step 2
Why this answer is correct
The correct answer is A. ((5x-1)(5x+1)=0). (25x-2 -1=(5x)2 -12 ), so ((5x-1)(5x+1)=0) is correct. In exams, quickly identify the difference of squares.
Step 3
Exam Tip
(25x-2 -1=(5x)2 -12 ), इसलिए ((5x-1)(5x+1)=0) सही है। परीक्षा में वर्गों के अंतर को जल्दी पहचानें।
Login to save your score, XP, coins and progress. Login
\(x^2+6x-55=0\) के सही गुणनखंड कौनसे हैं?
What are the correct factors of \(x^2+6x-55=0\)?
#quadratic
#factorisation
#mixed-signs
A ((x+11)(x-5))
B ((x-11)(x+5))
C ((x+55)(x-1))
D ((x-55)(x+1))
Explanation opens after your attempt
Correct Answer
A. ((x+11)(x-5))
Step 1
Concept
(11+(-5)=6) and \(11\times(-5)=-55\), so ((x+11)(x-5)) is correct. In exams, keep one sign positive and one negative.
Step 2
Why this answer is correct
The correct answer is A. ((x+11)(x-5)). (11+(-5)=6) and \(11\times(-5)=-55\), so ((x+11)(x-5)) is correct. In exams, keep one sign positive and one negative.
Step 3
Exam Tip
(11+(-5)=6) और \(11\times(-5)=-55\), इसलिए ((x+11)(x-5)) सही है। परीक्षा में एक चिन्ह धनात्मक और एक ऋणात्मक रखें।
Login to save your score, XP, coins and progress. Login
\(3x^2-11x+6=0\) के गुणनखंड कौनसे हैं?
What are the factors of \(3x^2-11x+6=0\)?
#quadratic
#factorisation
#middle-term
A ((3x-2)(x-3))
B ((3x+2)(x+3))
C ((3x-3)(x-2))
D ((x-6)(x-3))
Explanation opens after your attempt
Correct Answer
A. ((3x-2)(x-3))
Step 1
Concept
(3x-2 -11x+6=(3x-2)(x-3)). In exams, expand back to check (-11x).
Step 2
Why this answer is correct
The correct answer is A. ((3x-2)(x-3)). (3x-2 -11x+6=(3x-2)(x-3)). In exams, expand back to check (-11x).
Step 3
Exam Tip
(3x-2 -11x+6=(3x-2)(x-3)) है। परीक्षा में विस्तार करके (-11x) वापस जांचें।
Login to save your score, XP, coins and progress. Login
\(x^2-19x+90=0\) के मूल क्या हैं?
What are the roots of \(x^2-19x+90=0\)?
#quadratic
#roots
#factorisation
A (x=9,10)
B (x=-9,-10)
C (x=6,15)
D (x=-6,-15)
Explanation opens after your attempt
Correct Answer
A. (x=9,10)
Step 1
Concept
((x-9)(x-10)=0), so (x=9) and (x=10). In exams, roots are obtained by taking opposite signs of factors.
Step 2
Why this answer is correct
The correct answer is A. (x=9,10). ((x-9)(x-10)=0), so (x=9) and (x=10). In exams, roots are obtained by taking opposite signs of factors.
Step 3
Exam Tip
((x-9)(x-10)=0), इसलिए (x=9) और (x=10) हैं। परीक्षा में गुणनखंड के विपरीत चिन्ह से मूल मिलते हैं।
Login to save your score, XP, coins and progress. Login
\(x^2-19x+90=0\) के गुणनखंड कौनसे होंगे?
What will be the factors of \(x^2-19x+90=0\)?
#quadratic
#factorisation
#negative-middle-term
A ((x-9)(x-10))
B ((x+9)(x+10))
C ((x-6)(x-15))
D ((x+6)(x+15))
Explanation opens after your attempt
Correct Answer
A. ((x-9)(x-10))
Step 1
Concept
(9+10=19) and \(9\times10=90\), so ((x-9)(x-10)) is correct. In exams, take both negative signs for a negative middle term.
Step 2
Why this answer is correct
The correct answer is A. ((x-9)(x-10)). (9+10=19) and \(9\times10=90\), so ((x-9)(x-10)) is correct. In exams, take both negative signs for a negative middle term.
Step 3
Exam Tip
(9+10=19) और \(9\times10=90\), इसलिए ((x-9)(x-10)) सही है। परीक्षा में ऋणात्मक मध्य पद के लिए दोनों ऋणात्मक चिन्ह लें।
Login to save your score, XP, coins and progress. Login
\(16x^2-25=0\) का सही गुणनखंड रूप कौनसा है?
What is the correct factorised form of \(16x^2-25=0\)?
#quadratic
#difference-of-squares
#factorisation
A ((4x-5)(4x+5)=0)
B ((16x-5)(x+5)=0)
C ((4x-5)2 =0)
D ((x-5)(16x+5)=0)
Explanation opens after your attempt
Correct Answer
A. ((4x-5)(4x+5)=0)
Step 1
Concept
(16x-2 -25=(4x)2 -52 ), so ((4x-5)(4x+5)) is obtained. In exams, identify both squares first.
Step 2
Why this answer is correct
The correct answer is A. ((4x-5)(4x+5)=0). (16x-2 -25=(4x)2 -52 ), so ((4x-5)(4x+5)) is obtained. In exams, identify both squares first.
Step 3
Exam Tip
(16x-2 -25=(4x)2 -52 ), इसलिए ((4x-5)(4x+5)) मिलता है। परीक्षा में दोनों वर्गों को पहले पहचानें।
Login to save your score, XP, coins and progress. Login
\(x^2+7x+10=0\) के मूल क्या हैं?
What are the roots of \(x^2+7x+10=0\)?
#quadratic
#roots
#factorisation
A (x=-5,-2)
B (x=5,2)
C (x=-7,-10)
D (x=0,-10)
Explanation opens after your attempt
Correct Answer
A. (x=-5,-2)
Step 1
Concept
((x+5)(x+2)=0), so (x=-5) and (x=-2). In exams, from ((x+a)=0), write (x=-a).
Step 2
Why this answer is correct
The correct answer is A. (x=-5,-2). ((x+5)(x+2)=0), so (x=-5) and (x=-2). In exams, from ((x+a)=0), write (x=-a).
Step 3
Exam Tip
((x+5)(x+2)=0), इसलिए (x=-5) और (x=-2) हैं। परीक्षा में ((x+a)=0) से (x=-a) लिखें।
Login to save your score, XP, coins and progress. Login
\(x^2+7x+10=0\) को हल करने के लिए सबसे आसान विधि कौनसी है?
Which is the easiest method to solve \(x^2+7x+10=0\)?
#quadratic
#method-selection
#factorisation
A गुणनखंड विधि / Factorisation method
B लंबा भाग विधि / Long division method
C सारणी विधि / Table method
D केवल ग्राफ विधि / Only graph method
Explanation opens after your attempt
Correct Answer
A. गुणनखंड विधि / Factorisation method
Step 1
Concept
It factors easily as ((x+5)(x+2)=0). In exams, choose factorisation when coefficients are small.
Step 2
Why this answer is correct
The correct answer is A. गुणनखंड विधि / Factorisation method. It factors easily as ((x+5)(x+2)=0). In exams, choose factorisation when coefficients are small.
Step 3
Exam Tip
यह ((x+5)(x+2)=0) में आसानी से टूटता है। परीक्षा में छोटे गुणांक देखकर गुणनखंड विधि चुनें।
Login to save your score, XP, coins and progress. Login
\(9x^2-27x=0\) को गुणनखंड करके क्या मिलेगा?
What will be obtained by factoring \(9x^2-27x=0\)?
#quadratic
#common-factor
#factorisation
A (9x(x-3)=0)
B (9(x-3)=0)
C (x(9x+27)=0)
D (9x(x+3)=0)
Explanation opens after your attempt
Correct Answer
A. (9x(x-3)=0)
Step 1
Concept
Taking common factor (9x) gives (9x(x-3)=0). In exams, check by expanding after factoring.
Step 2
Why this answer is correct
The correct answer is A. (9x(x-3)=0). Taking common factor (9x) gives (9x(x-3)=0). In exams, check by expanding after factoring.
Step 3
Exam Tip
सामान्य गुणनखंड (9x) निकालने पर (9x(x-3)=0) मिलता है। परीक्षा में गुणनखंड निकालने के बाद विस्तार करके जांचें।
Login to save your score, XP, coins and progress. Login
\(x^2-17x+72=0\) के मूल क्या होंगे?
What will be the roots of \(x^2-17x+72=0\)?
#quadratic
#factorisation
#roots
A (x=8,9)
B (x=-8,-9)
C (x=6,12)
D (x=4,18)
Explanation opens after your attempt
Correct Answer
A. (x=8,9)
Step 1
Concept
(x-2 -17x+72=(x-8)(x-9)), so the roots are (8) and (9). In exams, check (8+9=17) and \(8\times9=72\).
Step 2
Why this answer is correct
The correct answer is A. (x=8,9). (x-2 -17x+72=(x-8)(x-9)), so the roots are (8) and (9). In exams, check (8+9=17) and \(8\times9=72\).
Step 3
Exam Tip
(x-2 -17x+72=(x-8)(x-9)), इसलिए मूल (8) और (9) हैं। परीक्षा में (8+9=17) और \(8\times9=72\) जांचें।
Login to save your score, XP, coins and progress. Login
सामान्य गुणनखंड निकालकर \(4x^2+28x=0\) को कैसे लिखा जाएगा?
By taking common factor, how will \(4x^2+28x=0\) be written?
#quadratic
#common-factor
#factorisation
A (4x(x+7)=0)
B (4(x+7)=0)
C (x(4x-28)=0)
D (4x(x-7)=0)
Explanation opens after your attempt
Correct Answer
A. (4x(x+7)=0)
Step 1
Concept
(4x) is the common factor, so (4x(x+7)=0). In exams, take out the greatest common factor.
Step 2
Why this answer is correct
The correct answer is A. (4x(x+7)=0). (4x) is the common factor, so (4x(x+7)=0). In exams, take out the greatest common factor.
Step 3
Exam Tip
(4x) सामान्य गुणनखंड है, इसलिए (4x(x+7)=0) मिलता है। परीक्षा में सबसे बड़ा सामान्य गुणनखंड निकालें।
Login to save your score, XP, coins and progress. Login
\(x^2+18x+81=0\) को किस रूप में लिखा जा सकता है?
In which form can \(x^2+18x+81=0\) be written?
#quadratic
#perfect-square
#factorisation
A ((x+9)2 =0)
B ((x-9)2 =0)
C ((x+18)2 =0)
D ((x-18)2 =0)
Explanation opens after your attempt
Correct Answer
A. ((x+9)2 =0)
Step 1
Concept
(x-2 +18x+81=(x+9)2 ), so it is a perfect square. In exams, match it using \(2\cdot9x=18x\).
Step 2
Why this answer is correct
The correct answer is A. ((x+9)2 =0). (x-2 +18x+81=(x+9)2 ), so it is a perfect square. In exams, match it using \(2\cdot9x=18x\).
Step 3
Exam Tip
(x-2 +18x+81=(x+9)2 ), इसलिए यह पूर्ण वर्ग है। परीक्षा में \(2\cdot9x=18x\) से मिलान करें।
Login to save your score, XP, coins and progress. Login
\(x^2-6x-27=0\) के सही गुणनखंड कौनसे हैं?
What are the correct factors of \(x^2-6x-27=0\)?
#quadratic
#factorisation
#mixed-signs
A ((x-9)(x+3))
B ((x+9)(x-3))
C ((x-27)(x+1))
D ((x+9)(x+3))
Explanation opens after your attempt
Correct Answer
A. ((x-9)(x+3))
Step 1
Concept
Since (-9+3=-6) and \(-9\times3=-27\), ((x-9)(x+3)) is correct. In exams, choose mixed signs carefully.
Step 2
Why this answer is correct
The correct answer is A. ((x-9)(x+3)). Since (-9+3=-6) and \(-9\times3=-27\), ((x-9)(x+3)) is correct. In exams, choose mixed signs carefully.
Step 3
Exam Tip
(-9+3=-6) और \(-9\times3=-27\), इसलिए ((x-9)(x+3)) सही है। परीक्षा में मिश्रित चिन्ह वाले गुणनखंड ध्यान से चुनें।
Login to save your score, XP, coins and progress. Login
\(x^2+13x+42=0\) का सही गुणनखंड रूप कौनसा है?
What is the correct factorised form of \(x^2+13x+42=0\)?
#quadratic
#factorisation
#standard-form
A ((x+6)(x+7)=0)
B ((x-6)(x-7)=0)
C ((x+3)(x+14)=0)
D ((x+2)(x+21)=0)
Explanation opens after your attempt
Correct Answer
A. ((x+6)(x+7)=0)
Step 1
Concept
(6+7=13) and \(6\times7=42\), so the correct factors are ((x+6)(x+7)). In exams, match the signs carefully.
Step 2
Why this answer is correct
The correct answer is A. ((x+6)(x+7)=0). (6+7=13) and \(6\times7=42\), so the correct factors are ((x+6)(x+7)). In exams, match the signs carefully.
Step 3
Exam Tip
(6+7=13) और \(6\times7=42\), इसलिए सही गुणनखंड ((x+6)(x+7)) हैं। परीक्षा में संकेतों को ध्यान से मिलाएं।
Login to save your score, XP, coins and progress. Login
गुणनखंड विधि से \(x^2-15x+56=0\) के मूल क्या होंगे?
Using factorisation method, what will be the roots of \(x^2-15x+56=0\)?
#quadratic
#factorisation
#roots
A (x=7,8)
B (x=-7,-8)
C (x=4,14)
D (x=1,56)
Explanation opens after your attempt
Correct Answer
A. (x=7,8)
Step 1
Concept
(x-2 -15x+56=(x-7)(x-8)), so the roots are (7) and (8). In exams, check both sum and product.
Step 2
Why this answer is correct
The correct answer is A. (x=7,8). (x-2 -15x+56=(x-7)(x-8)), so the roots are (7) and (8). In exams, check both sum and product.
Step 3
Exam Tip
(x-2 -15x+56=(x-7)(x-8)), इसलिए मूल (7) और (8) हैं। परीक्षा में योग और गुणनफल दोनों मिलाकर जांचें।
Login to save your score, XP, coins and progress. Login
\(4x^2+4x+1=0\) को किस पूर्ण वर्ग रूप में लिखा जा सकता है?
In which perfect square form can \(4x^2+4x+1=0\) be written?
#quadratic
#perfect-square
#factorisation
A ((2x+1)2 =0)
B ((2x-1)2 =0)
C ((4x+1)2 =0)
D ((x+2)2 =0)
Explanation opens after your attempt
Correct Answer
A. ((2x+1)2 =0)
Step 1
Concept
(4x-2 +4x+1=(2x+1)2 ), so it is a perfect square equation. In exams, recognize ((a+b)2 ) to solve quickly.
Step 2
Why this answer is correct
The correct answer is A. ((2x+1)2 =0). (4x-2 +4x+1=(2x+1)2 ), so it is a perfect square equation. In exams, recognize ((a+b)2 ) to solve quickly.
Step 3
Exam Tip
(4x-2 +4x+1=(2x+1)2 ), इसलिए यह पूर्ण वर्ग समीकरण है। परीक्षा में ((a+b)2 ) पहचानकर जल्दी हल करें।
Login to save your score, XP, coins and progress. Login
\(x^2+5x-14=0\) के सही गुणनखंड कौनसे हैं?
What are the correct factors of \(x^2+5x-14=0\)?
#quadratic
#factorisation
#mixed-signs
A ((x+7)(x-2))
B ((x-7)(x+2))
C ((x+14)(x-1))
D ((x-14)(x+1))
Explanation opens after your attempt
Correct Answer
A. ((x+7)(x-2))
Step 1
Concept
(7+(-2)=5) and \(7\times(-2)=-14\), so ((x+7)(x-2)) is correct. In exams, keep one sign positive and one negative.
Step 2
Why this answer is correct
The correct answer is A. ((x+7)(x-2)). (7+(-2)=5) and \(7\times(-2)=-14\), so ((x+7)(x-2)) is correct. In exams, keep one sign positive and one negative.
Step 3
Exam Tip
(7+(-2)=5) और \(7\times(-2)=-14\), इसलिए ((x+7)(x-2)) सही है। परीक्षा में एक चिन्ह धनात्मक और एक ऋणात्मक रखें।
Login to save your score, XP, coins and progress. Login
\(2x^2-7x+5=0\) के गुणनखंड कौनसे हैं?
What are the factors of \(2x^2-7x+5=0\)?
#quadratic
#factorisation
#middle-term
A ((2x-5)(x-1))
B ((2x+5)(x+1))
C ((2x-1)(x-5))
D ((x-5)(x-2))
Explanation opens after your attempt
Correct Answer
A. ((2x-5)(x-1))
Step 1
Concept
(2x-2 -7x+5=(2x-5)(x-1)). In exams, expand back to check (-7x).
Step 2
Why this answer is correct
The correct answer is A. ((2x-5)(x-1)). (2x-2 -7x+5=(2x-5)(x-1)). In exams, expand back to check (-7x).
Step 3
Exam Tip
(2x-2 -7x+5=(2x-5)(x-1)) है। परीक्षा में विस्तार करके (-7x) वापस जांचें।
Login to save your score, XP, coins and progress. Login
\(x^2-13x+40=0\) के मूल क्या हैं?
What are the roots of \(x^2-13x+40=0\)?
#quadratic
#roots
#factorisation
A (x=5,8)
B (x=-5,-8)
C (x=4,10)
D (x=-4,-10)
Explanation opens after your attempt
Correct Answer
A. (x=5,8)
Step 1
Concept
((x-5)(x-8)=0), so (x=5) and (x=8). In exams, roots are obtained by taking opposite signs of factors.
Step 2
Why this answer is correct
The correct answer is A. (x=5,8). ((x-5)(x-8)=0), so (x=5) and (x=8). In exams, roots are obtained by taking opposite signs of factors.
Step 3
Exam Tip
((x-5)(x-8)=0), इसलिए (x=5) और (x=8) हैं। परीक्षा में गुणनखंड के विपरीत चिन्ह से मूल मिलते हैं।
Login to save your score, XP, coins and progress. Login
\(x^2-13x+40=0\) के गुणनखंड कौनसे होंगे?
What will be the factors of \(x^2-13x+40=0\)?
#quadratic
#factorisation
#negative-middle-term
A ((x-5)(x-8))
B ((x+5)(x+8))
C ((x-4)(x-10))
D ((x+4)(x+10))
Explanation opens after your attempt
Correct Answer
A. ((x-5)(x-8))
Step 1
Concept
(5+8=13) and \(5\times8=40\), so ((x-5)(x-8)) is correct. In exams, take both negative signs for a negative middle term.
Step 2
Why this answer is correct
The correct answer is A. ((x-5)(x-8)). (5+8=13) and \(5\times8=40\), so ((x-5)(x-8)) is correct. In exams, take both negative signs for a negative middle term.
Step 3
Exam Tip
(5+8=13) और \(5\times8=40\), इसलिए ((x-5)(x-8)) सही है। परीक्षा में ऋणात्मक मध्य पद के लिए दोनों ऋणात्मक चिन्ह लें।
Login to save your score, XP, coins and progress. Login
\(9x^2-16=0\) का सही गुणनखंड रूप कौनसा है?
What is the correct factorised form of \(9x^2-16=0\)?
#quadratic
#difference-of-squares
#factorisation
A ((3x-4)(3x+4)=0)
B ((9x-4)(x+4)=0)
C ((3x-4)2 =0)
D ((x-4)(9x+4)=0)
Explanation opens after your attempt
Correct Answer
A. ((3x-4)(3x+4)=0)
Step 1
Concept
(9x-2 -16=(3x)2 -42 ), so ((3x-4)(3x+4)) is obtained. In exams, identify both squares first.
Step 2
Why this answer is correct
The correct answer is A. ((3x-4)(3x+4)=0). (9x-2 -16=(3x)2 -42 ), so ((3x-4)(3x+4)) is obtained. In exams, identify both squares first.
Step 3
Exam Tip
(9x-2 -16=(3x)2 -42 ), इसलिए ((3x-4)(3x+4)) मिलता है। परीक्षा में दोनों वर्गों को पहले पहचानें।
Login to save your score, XP, coins and progress. Login
\(x^2+4x+3=0\) के मूल क्या हैं?
What are the roots of \(x^2+4x+3=0\)?
#quadratic
#roots
#factorisation
A (x=-1,-3)
B (x=1,3)
C (x=-4,-3)
D (x=0,-3)
Explanation opens after your attempt
Correct Answer
A. (x=-1,-3)
Step 1
Concept
((x+1)(x+3)=0), so (x=-1) and (x=-3). In exams, from ((x+a)=0), write (x=-a).
Step 2
Why this answer is correct
The correct answer is A. (x=-1,-3). ((x+1)(x+3)=0), so (x=-1) and (x=-3). In exams, from ((x+a)=0), write (x=-a).
Step 3
Exam Tip
((x+1)(x+3)=0), इसलिए (x=-1) और (x=-3) हैं। परीक्षा में ((x+a)=0) से (x=-a) लिखें।
Login to save your score, XP, coins and progress. Login
\(x^2+4x+3=0\) को हल करने के लिए सबसे आसान विधि कौनसी है?
Which is the easiest method to solve \(x^2+4x+3=0\)?
#quadratic
#method-selection
#factorisation
A गुणनखंड विधि / Factorisation method
B लंबा भाग विधि / Long division method
C सारणी विधि / Table method
D केवल ग्राफ विधि / Only graph method
Explanation opens after your attempt
Correct Answer
A. गुणनखंड विधि / Factorisation method
Step 1
Concept
It factors easily as ((x+1)(x+3)=0). In exams, choose factorisation when coefficients are small.
Step 2
Why this answer is correct
The correct answer is A. गुणनखंड विधि / Factorisation method. It factors easily as ((x+1)(x+3)=0). In exams, choose factorisation when coefficients are small.
Step 3
Exam Tip
यह ((x+1)(x+3)=0) में आसानी से टूटता है। परीक्षा में छोटे गुणांक देखकर गुणनखंड विधि चुनें।
Login to save your score, XP, coins and progress. Login
\(7x^2-14x=0\) को गुणनखंड करके क्या मिलेगा?
What will be obtained by factoring \(7x^2-14x=0\)?
#quadratic
#common-factor
#factorisation
A (7x(x-2)=0)
B (7(x-2)=0)
C (x(7x+14)=0)
D (7x(x+2)=0)
Explanation opens after your attempt
Correct Answer
A. (7x(x-2)=0)
Step 1
Concept
Taking common factor (7x) gives (7x(x-2)=0). In exams, you can check by expanding after factoring.
Step 2
Why this answer is correct
The correct answer is A. (7x(x-2)=0). Taking common factor (7x) gives (7x(x-2)=0). In exams, you can check by expanding after factoring.
Step 3
Exam Tip
सामान्य गुणनखंड (7x) निकालने पर (7x(x-2)=0) मिलता है। परीक्षा में गुणनखंड निकालने के बाद विस्तार करके जांच सकते हैं।
Login to save your score, XP, coins and progress. Login
\(x^2-11x+28=0\) के मूल क्या होंगे?
What will be the roots of \(x^2-11x+28=0\)?
#quadratic
#factorisation
#roots
A (x=4,7)
B (x=-4,-7)
C (x=2,14)
D (x=1,28)
Explanation opens after your attempt
Correct Answer
A. (x=4,7)
Step 1
Concept
(x-2 -11x+28=(x-4)(x-7)), so the roots are (4) and (7). In exams, check (4+7=11) and \(4\times7=28\).
Step 2
Why this answer is correct
The correct answer is A. (x=4,7). (x-2 -11x+28=(x-4)(x-7)), so the roots are (4) and (7). In exams, check (4+7=11) and \(4\times7=28\).
Step 3
Exam Tip
(x-2 -11x+28=(x-4)(x-7)), इसलिए मूल (4) और (7) हैं। परीक्षा में (4+7=11) और \(4\times7=28\) जांचें।
Login to save your score, XP, coins and progress. Login
सामान्य गुणनखंड निकालकर \(5x^2+15x=0\) को कैसे लिखा जाएगा?
By taking common factor, how will \(5x^2+15x=0\) be written?
#quadratic
#common-factor
#factorisation
A (5x(x+3)=0)
B (5(x+3)=0)
C (x(5x-15)=0)
D (5x(x-3)=0)
Explanation opens after your attempt
Correct Answer
A. (5x(x+3)=0)
Step 1
Concept
(5x) is the common factor, so (5x(x+3)=0). In exams, take out the greatest common factor.
Step 2
Why this answer is correct
The correct answer is A. (5x(x+3)=0). (5x) is the common factor, so (5x(x+3)=0). In exams, take out the greatest common factor.
Step 3
Exam Tip
(5x) सामान्य गुणनखंड है, इसलिए (5x(x+3)=0) मिलता है। परीक्षा में सबसे बड़ा सामान्य गुणनखंड निकालें।
Login to save your score, XP, coins and progress. Login
