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What are the roots of the quadratic equation \(x^2+4x+3=0\)?
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Answer and explanation
Correct answer: \(\{-1,-3\}\)
Factoring gives \(x^2+4x+3=(x+1)(x+3)\). Thus, \((x+1)(x+3)=0\) implies \(x=-1\) or \(x=-3\), so the roots are \(\{-1,-3\}\). Option B has the signs reversed; \(x+1=0\) gives \(x=-1\). Exam tip: Set each linear factor equal to zero to find the roots.
Frequently asked questions
What is the correct answer to this question?
\(\{-1,-3\}\)
Why is this the correct answer?
Factoring gives \(x^2+4x+3=(x+1)(x+3)\). Thus, \((x+1)(x+3)=0\) implies \(x=-1\) or \(x=-3\), so the roots are \(\{-1,-3\}\). Option B has the signs reversed; \(x+1=0\) gives \(x=-1\). Exam tip: Set each linear factor equal to zero to find the roots.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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