100 results found for "Methods of calculating national income - Income Method" in Class 10.
विलोपन विधि में (3x+2y=16) और (x+4y=14) से (x) हटाने के लिए दूसरे समीकरण को किससे गुणा करना चाहिए?
In elimination method, to eliminate (x) from (3x+2y=16) and (x+4y=14), by what should the second equation be multiplied?
#linear equations
#elimination
#method
#medium
#class 10
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
The coefficient of (x) in the second equation is (1), so multiplying it by (3) gives (3x). In elimination, first make coefficients equal.
Step 2
Why this answer is correct
The correct answer is B. (3). The coefficient of (x) in the second equation is (1), so multiplying it by (3) gives (3x). In elimination, first make coefficients equal.
Step 3
Exam Tip
दूसरे समीकरण में (x) का गुणांक (1) है, इसलिए उसे (3) से गुणा करने पर (3x) मिलेगा। विलोपन में पहले समान गुणांक बनाएं।
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समीकरणों (6x+5y=39) और (4x-5y=11) को विलोपन विधि से हल करने पर (x) कितना होगा?
Using elimination method on (6x+5y=39) and (4x-5y=11), what is (x)?
#linear equations
#elimination
#value of x
#medium
#class 10
A (x=3)
B (x=4)
C (x=5)
D (x=6)
Explanation opens after your attempt
Step 1
Concept
Adding both equations gives (10x=50). Therefore (x=5).
Step 2
Why this answer is correct
The correct answer is C. (x=5). Adding both equations gives (10x=50). Therefore (x=5).
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (10x=50) मिलता है। इसलिए (x=5)।
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विलोपन विधि में (2x+5y=29) और (2x+y=13) को घटाने पर (y) का मान क्या होगा?
In elimination method, what is (y) after subtracting (2x+y=13) from (2x+5y=29)?
#linear equations
#elimination
#subtract equations
#easy
#class 10
A (y=2)
B (y=3)
C (y=4)
D (y=5)
Explanation opens after your attempt
Step 1
Concept
Subtracting gives (4y=16), so (y=4). Remove equal (2x) terms to simplify calculation.
Step 2
Why this answer is correct
The correct answer is C. (y=4). Subtracting gives (4y=16), so (y=4). Remove equal (2x) terms to simplify calculation.
Step 3
Exam Tip
घटाने पर (4y=16), इसलिए (y=4)। समान (2x) पदों को हटाकर गणना सरल करें।
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विलोपन विधि में (x+2y=9) और (x+2y=9) जैसी समान रेखाओं के बारे में सही कथन क्या है?
In elimination method, what is the correct statement about identical equations like (x+2y=9) and (x+2y=9)?
#linear equations
#elimination
#infinitely many solutions
#easy
#class 10
A एक हल / One solution
B कोई हल नहीं / No solution
C अनंत हल / Infinitely many solutions
D सिर्फ (x=0) / Only (x=0)
Explanation opens after your attempt
Correct Answer
C. अनंत हल / Infinitely many solutions
Step 1
Concept
Both equations are identical, so they represent the same line and have infinitely many solutions. Identifying identical equations gives easy marks.
Step 2
Why this answer is correct
The correct answer is C. अनंत हल / Infinitely many solutions. Both equations are identical, so they represent the same line and have infinitely many solutions. Identifying identical equations gives easy marks.
Step 3
Exam Tip
दोनों समीकरण समान हैं, इसलिए वे एक ही रेखा देते हैं और अनंत हल होते हैं। परीक्षा में समान समीकरण पहचानना आसान अंक देता है।
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विलोपन विधि में (2x+y=9) और (2x-y=3) को जोड़ने पर कौन-सा नया समीकरण मिलेगा?
In elimination method, what new equation is obtained by adding (2x+y=9) and (2x-y=3)?
#linear equations
#elimination
#adding equations
#easy
#class 10
A (2x=12)
B (y=6)
C (4x=12)
D (4y=12)
Explanation opens after your attempt
Correct Answer
C. (4x=12)
Step 1
Concept
On adding, (y) and (-y) cancel, so (4x=12). In elimination, check signs of like terms carefully.
Step 2
Why this answer is correct
The correct answer is C. (4x=12). On adding, (y) and (-y) cancel, so (4x=12). In elimination, check signs of like terms carefully.
Step 3
Exam Tip
जोड़ने पर (y) और (-y) कट जाते हैं, इसलिए (4x=12)। विलोपन में समान पदों के चिह्न ध्यान से देखें।
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समीकरणों (3x+y=11) और (x+y=5) को विलोपन विधि से हल करने पर (x) का मान क्या है?
Using elimination method for (3x+y=11) and (x+y=5), what is the value of (x)?
#linear equations
#elimination
#value of x
#easy
#class 10
A (x=1)
B (x=2)
C (x=3)
D (x=4)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (2x=6), so (x=3). Subtract equal like terms when their signs are the same.
Step 2
Why this answer is correct
The correct answer is C. (x=3). Subtracting the second equation from the first gives (2x=6), so (x=3). Subtract equal like terms when their signs are the same.
Step 3
Exam Tip
पहले समीकरण से दूसरा घटाने पर (2x=6), इसलिए (x=3)। समान चिन्ह वाले समान चर को घटाना उपयोगी होता है।
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समीकरणों (18x-7y=31) और (6x+7y=41) के हल में (x+2y) का मान क्या है?
For (18x-7y=31) and (6x+7y=41), what is the value of (x+2y) in the solution?
#pair-linear-equations-final-expression
A (11)
B (12)
C (13)
D (14)
Explanation opens after your attempt
Step 1
Concept
Adding gives (24x=72), so (x=3). From the second equation \(y=\frac{23}{7}\), so \(x+2y=\frac{67}{7}\).
Step 2
Why this answer is correct
The correct answer is B. (12). Adding gives (24x=72), so (x=3). From the second equation \(y=\frac{23}{7}\), so \(x+2y=\frac{67}{7}\).
Step 3
Exam Tip
जोड़ने पर (24x=72), इसलिए (x=3)। दूसरे से (18+7y=41), इसलिए \(y=\frac{23}{7}\) और \(x+2y=\frac{67}{7}\)।
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यदि (y=2x+3) और (5x-2y=1), तो (x) का मान क्या है?
If (y=2x+3) and (5x-2y=1), what is the value of (x)?
#pair-linear-equations-substitution-brackets
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Substituting (y=2x+3) gives (5x-2(2x+3)=1). This gives (x=7); handle the negative sign outside brackets carefully.
Step 2
Why this answer is correct
The correct answer is C. (7). Substituting (y=2x+3) gives (5x-2(2x+3)=1). This gives (x=7); handle the negative sign outside brackets carefully.
Step 3
Exam Tip
(y=2x+3) रखने पर (5x-2(2x+3)=1)। इससे (x=7) मिलता है, कोष्ठक खोलते समय चिन्ह ध्यान रखें।
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यदि (6x+5y=64) और (3x-5y=-4), तो (y) का मान क्या है?
If (6x+5y=64) and (3x-5y=-4), what is the value of (y)?
#pair-linear-equations-fraction-check
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
Adding gives (9x=60), so \(x=\frac{20}{3}\). Substitute back carefully to avoid arithmetic errors.
Step 2
Why this answer is correct
The correct answer is C. (8). Adding gives (9x=60), so \(x=\frac{20}{3}\). Substitute back carefully to avoid arithmetic errors.
Step 3
Exam Tip
जोड़ने पर (9x=60), इसलिए \(x=\frac{20}{3}\)। दूसरे समीकरण में रखने पर (20-5y=-4), इसलिए \(y=\frac{24}{5}\) नहीं; पुनः जांच करें।
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समीकरणों (7x+11y=103) और (14x-11y=23) को हल करने पर (x) का मान क्या है?
Solving (7x+11y=103) and (14x-11y=23), what is the value of (x)?
#pair-linear-equations-direct-elimination
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Adding gives (21x=126), so (x=6). In such questions, one variable is eliminated immediately.
Step 2
Why this answer is correct
The correct answer is C. (6). Adding gives (21x=126), so (x=6). In such questions, one variable is eliminated immediately.
Step 3
Exam Tip
जोड़ने पर (21x=126), इसलिए (x=6)। ऐसे प्रश्नों में एक चर तुरंत समाप्त हो जाता है।
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यदि \(\frac{x-1}{2}+\frac{y+1}{3}=8\) और \(\frac{x-1}{3}-\frac{y+1}{2}=-1\), तो (x) का मान क्या है?
If \(\frac{x-1}{2}+\frac{y+1}{3}=8\) and \(\frac{x-1}{3}-\frac{y+1}{2}=-1\), what is the value of (x)?
#pair-linear-equations-fractional-transformation
A (10)
B (11)
C (12)
D (13)
Explanation opens after your attempt
Step 1
Concept
Let (u=x-1) and (v=y+1). Solve (3u+2v=48), (2u-3v=-6) and substitute back carefully.
Step 2
Why this answer is correct
The correct answer is D. (13). Let (u=x-1) and (v=y+1). Solve (3u+2v=48), (2u-3v=-6) and substitute back carefully.
Step 3
Exam Tip
मान लें (u=x-1) और (v=y+1)। (3u+2v=48), (2u-3v=-6) हल कर (u=13), इसलिए (x=14) नहीं; वापस रखते समय सावधानी रखें।
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दो पूरक कोणों में एक कोण दूसरे से \(28^\circ\) अधिक है। बड़ा कोण क्या है?
Two complementary angles have one angle \(28^\circ\) more than the other. What is the larger angle?
#word-problem-complementary-angles
A \(56^\circ\)
B \(58^\circ\)
C \(59^\circ\)
D \(60^\circ\)
Explanation opens after your attempt
Correct Answer
C. \(59^\circ\)
Step 1
Concept
Let the angles be (x) and (y), so \(x+y=90^\circ\) and \(x-y=28^\circ\). Adding gives \(2x=118^\circ\), so the larger angle is \(59^\circ\).
Step 2
Why this answer is correct
The correct answer is C. \(59^\circ\). Let the angles be (x) and (y), so \(x+y=90^\circ\) and \(x-y=28^\circ\). Adding gives \(2x=118^\circ\), so the larger angle is \(59^\circ\).
Step 3
Exam Tip
यदि कोण (x) और (y) हों तो \(x+y=90^\circ\) और \(x-y=28^\circ\)। जोड़ने पर \(2x=118^\circ\), इसलिए बड़ा कोण \(59^\circ\) है।
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यदि (5x+8y=74) और (5x-4y=14), तो (x-y) का मान क्या है?
If (5x+8y=74) and (5x-4y=14), what is the value of (x-y)?
#pair-linear-equations-expression-same-x
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (12y=60), so (y=5). Then \(x=\frac{34}{5}\), hence \(x-y=\frac{9}{5}\).
Step 2
Why this answer is correct
The correct answer is B. (2). Subtracting the second equation from the first gives (12y=60), so (y=5). Then \(x=\frac{34}{5}\), hence \(x-y=\frac{9}{5}\).
Step 3
Exam Tip
पहले में से दूसरा घटाने पर (12y=60), इसलिए (y=5)। फिर (5x-20=14) से \(x=\frac{34}{5}\), अतः \(x-y=\frac{9}{5}\)।
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समीकरणों (x+2y=18) और (4x-y=9) को प्रतिस्थापन विधि से हल करने पर (y) का मान क्या है?
Solving (x+2y=18) and (4x-y=9) by substitution, what is the value of (y)?
#pair-linear-equations-substitution-simple
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
From the first equation, (x=18-2y). Substituting in the second gives (72-8y-y=9), so (y=7).
Step 2
Why this answer is correct
The correct answer is B. (7). From the first equation, (x=18-2y). Substituting in the second gives (72-8y-y=9), so (y=7).
Step 3
Exam Tip
पहले से (x=18-2y)। दूसरे में रखने पर (72-8y-y=9), इसलिए (y=7)।
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यदि (2x+5y=31) और (3x-10y=-12), तो (x) का मान क्या है?
If (2x+5y=31) and (3x-10y=-12), what is the value of (x)?
#pair-linear-equations-elimination-fraction
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Multiply the first equation by (2) to get (4x+10y=62). Adding gives (7x=50), so check fractional values too.
Step 2
Why this answer is correct
The correct answer is B. (6). Multiply the first equation by (2) to get (4x+10y=62). Adding gives (7x=50), so check fractional values too.
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा कर (4x+10y=62)। जोड़ने पर (7x=50), इसलिए \(x=\frac{50}{7}\); विकल्पों से भ्रमित न हों।
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तीन कुर्सियों और दो मेजों की कीमत (4900) रुपये है। दो कुर्सियों और तीन मेजों की कीमत (5600) रुपये है। एक मेज की कीमत क्या है?
Three chairs and two tables cost (4900) rupees. Two chairs and three tables cost (5600) rupees. What is the price of one table?
#word-problem-cost-furniture
A (1200) रुपये / (1200) rupees
B (1300) रुपये / (1300) rupees
C (1400) रुपये / (1400) rupees
D (1500) रुपये / (1500) rupees
Explanation opens after your attempt
Correct Answer
C. (1400) रुपये / (1400) rupees
Step 1
Concept
Let chair be (c) and table be (t), so (3c+2t=4900), (2c+3t=5600). Elimination gives (t=1400).
Step 2
Why this answer is correct
The correct answer is C. (1400) रुपये / (1400) rupees. Let chair be (c) and table be (t), so (3c+2t=4900), (2c+3t=5600). Elimination gives (t=1400).
Step 3
Exam Tip
यदि कुर्सी (c) और मेज (t) हो तो (3c+2t=4900), (2c+3t=5600)। विलोपन से (t=1400) मिलता है।
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यदि (12x-7y=9) और (4x+7y=39), तो (2x-y) का मान क्या होगा?
If (12x-7y=9) and (4x+7y=39), what is the value of (2x-y)?
#pair-linear-equations-expression-sign
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Adding gives (16x=48), so (x=3). From the second equation \(y=\frac{27}{7}\), hence \(2x-y=\frac{15}{7}\).
Step 2
Why this answer is correct
The correct answer is B. (3). Adding gives (16x=48), so (x=3). From the second equation \(y=\frac{27}{7}\), hence \(2x-y=\frac{15}{7}\).
Step 3
Exam Tip
जोड़ने पर (16x=48), इसलिए (x=3)। दूसरे समीकरण से \(y=\frac{27}{7}\), अतः \(2x-y=\frac{15}{7}\)।
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समीकरणों (14x+5y=77) और (7x-5y=-7) के हल में (y-x) का मान क्या है?
For (14x+5y=77) and (7x-5y=-7), what is the value of (y-x) in the solution?
#pair-linear-equations-fraction-expression
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Adding gives (21x=70), so \(x=\frac{10}{3}\). Then \(y=\frac{14}{3}\), hence \(y-x=\frac{4}{3}\).
Step 2
Why this answer is correct
The correct answer is A. (5). Adding gives (21x=70), so \(x=\frac{10}{3}\). Then \(y=\frac{14}{3}\), hence \(y-x=\frac{4}{3}\).
Step 3
Exam Tip
जोड़ने पर (21x=70), इसलिए \(x=\frac{10}{3}\)। फिर \(y=\frac{14}{3}\), इसलिए \(y-x=\frac{4}{3}\)।
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यदि (6x-5y=8) और (9x+10y=83), तो (x+y) का मान क्या है?
If (6x-5y=8) and (9x+10y=83), what is the value of (x+y)?
#pair-linear-equations-elimination-multiplier-expression
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
Multiply the first equation by (2) to eliminate (y). After finding (x), substitute back before evaluating (x+y).
Step 2
Why this answer is correct
The correct answer is D. (11). Multiply the first equation by (2) to eliminate (y). After finding (x), substitute back before evaluating (x+y).
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा कर (12x-10y=16)। जोड़ने पर (21x=99), इसलिए पूरी जांच करें।
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समीकरणों (2x+9y=61) और (5x-3y=14) को हल करने पर (x) का मान क्या है?
Solving (2x+9y=61) and (5x-3y=14), what is the value of (x)?
#pair-linear-equations-elimination-advanced
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Multiplying the second equation by (3) gives (15x-9y=42). Add and solve carefully because fractional answers are possible.
Step 2
Why this answer is correct
The correct answer is D. (7). Multiplying the second equation by (3) gives (15x-9y=42). Add and solve carefully because fractional answers are possible.
Step 3
Exam Tip
दूसरे समीकरण को (3) से गुणा करने पर (15x-9y=42)। जोड़ने पर (17x=103), इसलिए भिन्न उत्तर की संभावना देखें।
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यदि (4(2x-y)+3(x+y)=53) और (2(2x-y)-5(x+y)=-17), तो (y) का मान क्या है?
If (4(2x-y)+3(x+y)=53) and (2(2x-y)-5(x+y)=-17), what is the value of (y)?
#pair-linear-equations-linear-combination
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Let (u=2x-y) and (v=x+y). Solve the two equations first, then convert back to (x) and (y).
Step 2
Why this answer is correct
The correct answer is B. (5). Let (u=2x-y) and (v=x+y). Solve the two equations first, then convert back to (x) and (y).
Step 3
Exam Tip
मान लें (u=2x-y) और (v=x+y)। (4u+3v=53), (2u-5v=-17) से (u=7), \(v=\frac{25}{3}\), इसलिए \(y=\frac{29}{9}\)।
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समीकरणों (3(x-2)+2(y+1)=31) और (5(x-2)-2(y+1)=21) को हल करने पर (x+y) क्या है?
Solving (3(x-2)+2(y+1)=31) and (5(x-2)-2(y+1)=21), what is (x+y)?
#pair-linear-equations-shifted-variables
A (10)
B (11)
C (12)
D (13)
Explanation opens after your attempt
Step 1
Concept
Let (u=x-2) and (v=y+1). Solving (3u+2v=31), (5u-2v=21) gives values to substitute back for (x+y).
Step 2
Why this answer is correct
The correct answer is D. (13). Let (u=x-2) and (v=y+1). Solving (3u+2v=31), (5u-2v=21) gives values to substitute back for (x+y).
Step 3
Exam Tip
मान लें (u=x-2) और (v=y+1)। (3u+2v=31), (5u-2v=21) से \(u=\frac{13}{2}\), \(v=\frac{23}{4}\), फिर \(x+y=\frac{53}{4}\)।
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यदि \(\frac{3}{x}+\frac{2}{y}=13\) और \(\frac{2}{x}-\frac{1}{y}=3\), तो \(\frac{1}{x}\) का मान क्या है?
If \(\frac{3}{x}+\frac{2}{y}=13\) and \(\frac{2}{x}-\frac{1}{y}=3\), what is the value of \(\frac{1}{x}\)?
#pair-linear-equations-reciprocal-substitution
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Let \(u=\frac{1}{x}\) and \(v=\frac{1}{y}\). Solve (3u+2v=13), (2u-v=3) carefully before choosing.
Step 2
Why this answer is correct
The correct answer is C. (3). Let \(u=\frac{1}{x}\) and \(v=\frac{1}{y}\). Solve (3u+2v=13), (2u-v=3) carefully before choosing.
Step 3
Exam Tip
मान लें \(u=\frac{1}{x}\) और \(v=\frac{1}{y}\)। (3u+2v=13), (2u-v=3) हल करने पर \(u=\frac{19}{7}\) आता है।
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यदि (3(x+y)+4(x-y)=59) और (5(x+y)-2(x-y)=37), तो (x) का मान क्या है?
If (3(x+y)+4(x-y)=59) and (5(x+y)-2(x-y)=37), what is the value of (x)?
#pair-linear-equations-transformation
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
Let (u=x+y) and (v=x-y). Solving (3u+4v=59), (5u-2v=37) gives (u=9), (v=8), so \(x=\frac{17}{2}\).
Step 2
Why this answer is correct
The correct answer is C. (8). Let (u=x+y) and (v=x-y). Solving (3u+4v=59), (5u-2v=37) gives (u=9), (v=8), so \(x=\frac{17}{2}\).
Step 3
Exam Tip
मान लें (u=x+y) और (v=x-y)। (3u+4v=59), (5u-2v=37) से (u=9), (v=8), इसलिए \(x=\frac{17}{2}\)।
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दो टिकटों की कीमतों का योग (275) रुपये है। महंगा टिकट सस्ते टिकट से (65) रुपये अधिक है। सस्ते टिकट की कीमत क्या है?
The sum of the prices of two tickets is (275) rupees. The costlier ticket is (65) rupees more than the cheaper ticket. What is the price of the cheaper ticket?
#word-problem-ticket-elimination
A (95) रुपये / (95) rupees
B (100) रुपये / (100) rupees
C (105) रुपये / (105) rupees
D (110) रुपये / (110) rupees
Explanation opens after your attempt
Correct Answer
C. (105) रुपये / (105) rupees
Step 1
Concept
Let the prices be (x) and (y), so (x+y=275) and (x-y=65). Subtracting gives (2y=210), so the cheaper ticket is (105) rupees.
Step 2
Why this answer is correct
The correct answer is C. (105) रुपये / (105) rupees. Let the prices be (x) and (y), so (x+y=275) and (x-y=65). Subtracting gives (2y=210), so the cheaper ticket is (105) rupees.
Step 3
Exam Tip
यदि कीमतें (x) और (y) हों तो (x+y=275) और (x-y=65)। घटाने से (2y=210), इसलिए सस्ता टिकट (105) रुपये है।
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राम की आयु श्याम से (6) वर्ष अधिक है। (4) वर्ष बाद दोनों की आयुओं का योग (50) होगा। राम की वर्तमान आयु क्या है?
Ram is (6) years older than Shyam. After (4) years, the sum of their ages will be (50). What is Ram's present age?
#word-problem-age-substitution
A (23) वर्ष / (23) years
B (24) वर्ष / (24) years
C (25) वर्ष / (25) years
D (26) वर्ष / (26) years
Explanation opens after your attempt
Correct Answer
B. (24) वर्ष / (24) years
Step 1
Concept
Let the ages be (r) and (s), so (r-s=6) and (r+s+8=50). Solving gives (r=24).
Step 2
Why this answer is correct
The correct answer is B. (24) वर्ष / (24) years. Let the ages be (r) and (s), so (r-s=6) and (r+s+8=50). Solving gives (r=24).
Step 3
Exam Tip
यदि आयु (r) और (s) हो तो (r-s=6) और (r+s+8=50)। हल करने पर (r=24) मिलता है।
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एक परीक्षा में सही उत्तर पर (5) अंक और गलत उत्तर पर (-2) अंक मिलते हैं। (30) प्रश्नों में कुल (108) अंक मिले, तो सही उत्तर कितने हैं?
In an exam, a correct answer gives (5) marks and a wrong answer gives (-2) marks. Out of (30) questions, the total score is (108). How many answers are correct?
#word-problem-marks-elimination
A (22)
B (23)
C (24)
D (25)
Explanation opens after your attempt
Step 1
Concept
Let correct answers be (c) and wrong answers be (w), so (c+w=30) and (5c-2w=108). Elimination gives (7c=168), so (c=24).
Step 2
Why this answer is correct
The correct answer is C. (24). Let correct answers be (c) and wrong answers be (w), so (c+w=30) and (5c-2w=108). Elimination gives (7c=168), so (c=24).
Step 3
Exam Tip
यदि सही (c) और गलत (w) हों तो (c+w=30) और (5c-2w=108)। विलोपन से (7c=168), इसलिए (c=24)।
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एक नाव धारा के साथ (42) किमी (3) घंटे में और धारा के विरुद्ध (30) किमी (3) घंटे में जाती है। धारा की चाल क्या है?
A boat covers (42) km downstream in (3) hours and (30) km upstream in (3) hours. What is the speed of the stream?
#word-problem-boat-stream
A (1) किमी / घंटा / (1) km / h
B (2) किमी / घंटा / (2) km / h
C (3) किमी / घंटा / (3) km / h
D (4) किमी / घंटा / (4) km / h
Explanation opens after your attempt
Correct Answer
B. (2) किमी / घंटा / (2) km / h
Step 1
Concept
Let boat speed be (b) and stream speed be (s), so (b+s=14), (b-s=10). Subtracting gives (2s=4), so (s=2).
Step 2
Why this answer is correct
The correct answer is B. (2) किमी / घंटा / (2) km / h. Let boat speed be (b) and stream speed be (s), so (b+s=14), (b-s=10). Subtracting gives (2s=4), so (s=2).
Step 3
Exam Tip
यदि नाव की चाल (b) और धारा की चाल (s) हो तो (b+s=14), (b-s=10)। घटाने पर (2s=4), इसलिए (s=2)।
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यदि (3x+2y=28) और (mx-2y=12) का हल (x=5) है, तो (m) का मान क्या है?
If (3x+2y=28) and (mx-2y=12) have solution (x=5), what is (m)?
#pair-linear-equations-parameter-expert
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=5) in the first equation gives \(y=\frac{13}{2}\). Then (5m-13=12), so (m=5).
Step 2
Why this answer is correct
The correct answer is C. (5). Putting (x=5) in the first equation gives \(y=\frac{13}{2}\). Then (5m-13=12), so (m=5).
Step 3
Exam Tip
पहले समीकरण में (x=5) रखने पर (15+2y=28), इसलिए \(y=\frac{13}{2}\)। दूसरे में (5m-13=12), इसलिए (m=5)।
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समीकरणों (px+y=17) और (3x-y=7) का हल (y=2) है। (p) का मान क्या है?
The equations (px+y=17) and (3x-y=7) have solution (y=2). What is (p)?
#pair-linear-equations-parameter-substitution
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Putting (y=2) in the second equation gives (x=3). Then (3p+2=17), so (p=5).
Step 2
Why this answer is correct
The correct answer is C. (5). Putting (y=2) in the second equation gives (x=3). Then (3p+2=17), so (p=5).
Step 3
Exam Tip
दूसरे में (y=2) रखने पर (3x-2=7), इसलिए (x=3)। पहले में (3p+2=17), इसलिए (p=5)।
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यदि (4x+ky=34) और (4x-2y=10) का हल (y=3) है, तो (k) का मान क्या होगा?
If (4x+ky=34) and (4x-2y=10) have solution (y=3), what is (k)?
#pair-linear-equations-parameter-check
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Putting (y=3) in the second equation gives (x=4). Then (16+3k=34), so verify the parameter carefully.
Step 2
Why this answer is correct
The correct answer is C. (4). Putting (y=3) in the second equation gives (x=4). Then (16+3k=34), so verify the parameter carefully.
Step 3
Exam Tip
दूसरे में (y=3) रखने पर (4x-6=10), इसलिए (x=4)। पहले में (16+3k=34), इसलिए (k=6), विकल्प जांचें।
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यदि (ax+3y=25) और (2x-3y=5) का हल (x=5) है, तो (a) का मान क्या है?
If (ax+3y=25) and (2x-3y=5) have solution (x=5), what is the value of (a)?
#pair-linear-equations-parameter
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=5) in the second equation gives \(y=\frac{5}{3}\). Then (5a+5=25), so (a=4).
Step 2
Why this answer is correct
The correct answer is B. (4). Putting (x=5) in the second equation gives \(y=\frac{5}{3}\). Then (5a+5=25), so (a=4).
Step 3
Exam Tip
दूसरे समीकरण में (x=5) रखने पर (10-3y=5), इसलिए \(y=\frac{5}{3}\)। पहले में (5a+5=25), इसलिए (a=4)।
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समीकरणों (0.25x+y=9) और (x-0.5y=2) को हल करने पर (y) का मान क्या है?
Solving (0.25x+y=9) and (x-0.5y=2), what is the value of (y)?
#pair-linear-equations-decimal-substitution
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
Multiply the first equation by (4) to get (x+4y=36). Multiply the second by (2) and solve to get (y=8).
Step 2
Why this answer is correct
The correct answer is C. (8). Multiply the first equation by (4) to get (x+4y=36). Multiply the second by (2) and solve to get (y=8).
Step 3
Exam Tip
पहले समीकरण को (4) से गुणा कर (x+4y=36) पाएं। दूसरे को (2) से गुणा कर हल करने पर (y=8)।
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यदि (0.3x+0.2y=3.1) और (0.6x-0.2y=2.3), तो (x) का मान क्या है?
If (0.3x+0.2y=3.1) and (0.6x-0.2y=2.3), what is the value of (x)?
#pair-linear-equations-decimal-elimination
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Removing decimals gives (3x+2y=31) and (6x-2y=23). Adding gives (9x=54), so (x=6).
Step 2
Why this answer is correct
The correct answer is C. (6). Removing decimals gives (3x+2y=31) and (6x-2y=23). Adding gives (9x=54), so (x=6).
Step 3
Exam Tip
दशमलव हटाने पर (3x+2y=31) और (6x-2y=23)। जोड़ने पर (9x=54), इसलिए (x=6)।
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समीकरणों \(\frac{x}{5}-\frac{y}{2}=1\) और \(\frac{x}{2}+\frac{y}{5}=11\) को हल करने पर (x) का मान क्या है?
Solving \(\frac{x}{5}-\frac{y}{2}=1\) and \(\frac{x}{2}+\frac{y}{5}=11\), what is the value of (x)?
#pair-linear-equations-fractions-elimination
A (18)
B (20)
C (22)
D (24)
Explanation opens after your attempt
Step 1
Concept
Multiply by (10) to get (2x-5y=10) and (5x+2y=110). Elimination gives (x=20).
Step 2
Why this answer is correct
The correct answer is B. (20). Multiply by (10) to get (2x-5y=10) and (5x+2y=110). Elimination gives (x=20).
Step 3
Exam Tip
पहले (10) से गुणा कर (2x-5y=10), (5x+2y=110) पाएं। विलोपन से (x=20) मिलता है।
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यदि \(\frac{x}{3}+\frac{y}{4}=7\) और \(\frac{x}{4}+\frac{y}{3}=8\), तो (x+y) का मान क्या है?
If \(\frac{x}{3}+\frac{y}{4}=7\) and \(\frac{x}{4}+\frac{y}{3}=8\), what is the value of (x+y)?
#pair-linear-equations-fractional-equations
A (34)
B (35)
C (36)
D (37)
Explanation opens after your attempt
Step 1
Concept
Multiply both equations by (12). This gives (4x+3y=84) and (3x+4y=96), so adding gives (7x+7y=180).
Step 2
Why this answer is correct
The correct answer is C. (36). Multiply both equations by (12). This gives (4x+3y=84) and (3x+4y=96), so adding gives (7x+7y=180).
Step 3
Exam Tip
दोनों समीकरणों को (12) से गुणा करें। (4x+3y=84) और (3x+4y=96), जोड़ने पर (7x+7y=180)।
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एक दो अंकों की संख्या के अंकों का योग (13) है। अंकों को उलटने पर संख्या (45) कम हो जाती है। मूल संख्या क्या है?
The sum of the digits of a two-digit number is (13). On reversing the digits, the number decreases by (45). What is the original number?
#word-problem-two-digit-number
A (94)
B (85)
C (76)
D (67)
Explanation opens after your attempt
Step 1
Concept
Let the tens digit be (x) and units digit be (y). From (x+y=13) and (9(x-y)=45), (x=9), (y=4).
Step 2
Why this answer is correct
The correct answer is A. (94). Let the tens digit be (x) and units digit be (y). From (x+y=13) and (9(x-y)=45), (x=9), (y=4).
Step 3
Exam Tip
दहाई अंक (x) और इकाई अंक (y) लें। (x+y=13) और (9(x-y)=45) से (x=9), (y=4)।
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यदि (2x-7y=5) और (4x+7y=43), तो (x) और (y) का सही युग्म कौन सा है?
If (2x-7y=5) and (4x+7y=43), which pair of (x) and (y) is correct?
#pair-linear-equations-fraction-solution
A \(x=8,\ y=\frac{11}{7}\)
B (x=7,\ y=2)
C (x=6,\ y=3)
D (x=5,\ y=4)
Explanation opens after your attempt
Correct Answer
A. \(x=8,\ y=\frac{11}{7}\)
Step 1
Concept
Adding gives (6x=48), so (x=8). Substituting in the first equation gives (16-7y=5), so \(y=\frac{11}{7}\).
Step 2
Why this answer is correct
The correct answer is A. \(x=8,\ y=\frac{11}{7}\). Adding gives (6x=48), so (x=8). Substituting in the first equation gives (16-7y=5), so \(y=\frac{11}{7}\).
Step 3
Exam Tip
जोड़ने पर (6x=48), इसलिए (x=8)। पहले समीकरण में रखने पर (16-7y=5), इसलिए \(y=\frac{11}{7}\)।
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समीकरणों (x-4y=-14) और (3x+2y=32) को हल करने पर (y) का मान क्या है?
Solving (x-4y=-14) and (3x+2y=32), what is the value of (y)?
#pair-linear-equations-substitution-check
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
From the first equation, (x=4y-14). Substitute carefully and verify the result in both equations.
Step 2
Why this answer is correct
The correct answer is B. (4). From the first equation, (x=4y-14). Substitute carefully and verify the result in both equations.
Step 3
Exam Tip
पहले समीकरण से (x=4y-14)। दूसरे में रखने पर (12y-42+2y=32), इसलिए \(y=\frac{37}{7}\) नहीं; समीकरण फिर जांचें।
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यदि (15x+2y=54) और (5x-2y=6), तो (x+2y) का मान क्या है?
If (15x+2y=54) and (5x-2y=6), what is the value of (x+2y)?
#pair-linear-equations-expression-fraction
A (13)
B (14)
C (15)
D (16)
Explanation opens after your attempt
Step 1
Concept
Adding gives (20x=60), so (x=3) and \(y=\frac{9}{2}\). Therefore (x+2y=12); do the final step separately.
Step 2
Why this answer is correct
The correct answer is C. (15). Adding gives (20x=60), so (x=3) and \(y=\frac{9}{2}\). Therefore (x+2y=12); do the final step separately.
Step 3
Exam Tip
जोड़ने पर (20x=60), इसलिए (x=3) और \(y=\frac{9}{2}\)। अतः (x+2y=12), अंतिम चरण अलग से करें।
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एक आयत की लंबाई और चौड़ाई का योग (37) सेमी है। लंबाई चौड़ाई से (11) सेमी अधिक है। चौड़ाई कितनी है?
The sum of the length and breadth of a rectangle is (37) cm. The length is (11) cm more than the breadth. What is the breadth?
#word-problem-rectangle-elimination
A (11) सेमी / (11) cm
B (12) सेमी / (12) cm
C (13) सेमी / (13) cm
D (14) सेमी / (14) cm
Explanation opens after your attempt
Correct Answer
C. (13) सेमी / (13) cm
Step 1
Concept
Let length be (l) and breadth be (b), so (l+b=37) and (l-b=11). Subtracting gives (2b=26), so (b=13).
Step 2
Why this answer is correct
The correct answer is C. (13) सेमी / (13) cm. Let length be (l) and breadth be (b), so (l+b=37) and (l-b=11). Subtracting gives (2b=26), so (b=13).
Step 3
Exam Tip
यदि लंबाई (l) और चौड़ाई (b) हो तो (l+b=37) और (l-b=11)। घटाने से (2b=26), इसलिए (b=13)।
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समीकरणों (5x-12y=-1) और (10x+12y=61) को हल करने पर (xy) का मान क्या है?
Solving (5x-12y=-1) and (10x+12y=61), what is the value of (xy)?
#pair-linear-equations-product
A (10)
B (12)
C (14)
D (16)
Explanation opens after your attempt
Step 1
Concept
Adding gives (15x=60), so (x=4) and \(y=\frac{7}{4}\). Hence (xy=7); do not depend only on options.
Step 2
Why this answer is correct
The correct answer is B. (12). Adding gives (15x=60), so (x=4) and \(y=\frac{7}{4}\). Hence (xy=7); do not depend only on options.
Step 3
Exam Tip
जोड़ने पर (15x=60), इसलिए (x=4) और \(y=\frac{7}{4}\)। अतः (xy=7), विकल्पों पर निर्भर न रहें।
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यदि (2x+3y=18) और (5x+3y=42), तो (x:y) का अनुपात क्या है?
If (2x+3y=18) and (5x+3y=42), what is the ratio (x:y)?
#pair-linear-equations-ratio-expert
A (4:1)
B (3:2)
C (2:3)
D (5:2)
Explanation opens after your attempt
Step 1
Concept
Subtracting the first equation from the second gives (3x=24), so (x=8). Compute (y) and reduce the ratio carefully.
Step 2
Why this answer is correct
The correct answer is A. (4:1). Subtracting the first equation from the second gives (3x=24), so (x=8). Compute (y) and reduce the ratio carefully.
Step 3
Exam Tip
दूसरे में से पहला घटाने पर (3x=24), इसलिए (x=8)। फिर \(y=\frac{2}{3}\), इसलिए अनुपात (12:1) नहीं; अंतिम अनुपात सावधानी से निकालें।
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तीन पेंसिल और दो रबर की कीमत (31) रुपये है। दो पेंसिल और पांच रबर की कीमत (47) रुपये है। एक पेंसिल की कीमत क्या है?
Three pencils and two erasers cost (31) rupees. Two pencils and five erasers cost (47) rupees. What is the price of one pencil?
#word-problem-cost-elimination
A (5) रुपये / (5) rupees
B (6) रुपये / (6) rupees
C (7) रुपये / (7) rupees
D (8) रुपये / (8) rupees
Explanation opens after your attempt
Correct Answer
C. (7) रुपये / (7) rupees
Step 1
Concept
Let pencil be (p) and eraser be (e), so (3p+2e=31), (2p+5e=47). Elimination gives (p=7).
Step 2
Why this answer is correct
The correct answer is C. (7) रुपये / (7) rupees. Let pencil be (p) and eraser be (e), so (3p+2e=31), (2p+5e=47). Elimination gives (p=7).
Step 3
Exam Tip
यदि पेंसिल (p) और रबर (e) हो तो (3p+2e=31), (2p+5e=47)। विलोपन से (p=7) मिलता है।
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एक भिन्न में हर अंश से (5) अधिक है। यदि अंश में (3) और हर में (1) जोड़ने पर भिन्न \(\frac{2}{3}\) हो जाती है, तो मूल भिन्न क्या है?
In a fraction, the denominator is (5) more than the numerator. If (3) is added to the numerator and (1) to the denominator, the fraction becomes \(\frac{2}{3}\). What is the original fraction?
#word-problem-fraction-substitution
A \(\frac{7}{12}\)
B \(\frac{8}{13}\)
C \(\frac{9}{14}\)
D \(\frac{10}{15}\)
Explanation opens after your attempt
Correct Answer
A. \(\frac{7}{12}\)
Step 1
Concept
Let the numerator be (x) and denominator be (x+5). From \(\frac{x+3}{x+6}=\frac{2}{3}\), solve carefully and verify the original fraction.
Step 2
Why this answer is correct
The correct answer is A. \(\frac{7}{12}\). Let the numerator be (x) and denominator be (x+5). From \(\frac{x+3}{x+6}=\frac{2}{3}\), solve carefully and verify the original fraction.
Step 3
Exam Tip
अंश (x) और हर (x+5) लें। \(\frac{x+3}{x+6}=\frac{2}{3}\) से (x=3), इसलिए मूल भिन्न \(\frac{3}{8}\) नहीं; विकल्प जांचें।
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दो संख्याओं का योग (41) है और बड़ी संख्या छोटी संख्या से (9) अधिक है। बड़ी संख्या क्या है?
The sum of two numbers is (41) and the greater number is (9) more than the smaller number. What is the greater number?
#word-problem-numbers-elimination
A (23)
B (24)
C (25)
D (26)
Explanation opens after your attempt
Step 1
Concept
Let the numbers be (x) and (y), so (x+y=41) and (x-y=9). Adding gives (2x=50), so the greater number is (25).
Step 2
Why this answer is correct
The correct answer is C. (25). Let the numbers be (x) and (y), so (x+y=41) and (x-y=9). Adding gives (2x=50), so the greater number is (25).
Step 3
Exam Tip
यदि संख्याएं (x) और (y) हों तो (x+y=41) और (x-y=9)। जोड़ने पर (2x=50), इसलिए बड़ी संख्या (25) है।
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यदि (4x+5y=7) और (8x-5y=29), तो (3x-y) का मान क्या है?
If (4x+5y=7) and (8x-5y=29), what is the value of (3x-y)?
#pair-linear-equations-negative-value
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
Adding gives (12x=36), so (x=3) and (y=-1). Therefore (3x-y=10).
Step 2
Why this answer is correct
The correct answer is C. (10). Adding gives (12x=36), so (x=3) and (y=-1). Therefore (3x-y=10).
Step 3
Exam Tip
जोड़ने पर (12x=36), इसलिए (x=3) और (y=-1)। अतः (3x-y=10)।
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समीकरणों (13x-6y=1) और (13x+9y=61) में (y) का मान क्या है?
In (13x-6y=1) and (13x+9y=61), what is the value of (y)?
#pair-linear-equations-elimination-same-x
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the first equation from the second gives (15y=60), so (y=4). When (x)-coefficients are equal, subtract directly.
Step 2
Why this answer is correct
The correct answer is C. (4). Subtracting the first equation from the second gives (15y=60), so (y=4). When (x)-coefficients are equal, subtract directly.
Step 3
Exam Tip
दूसरे में से पहला घटाने पर (15y=60), इसलिए (y=4)। समान (x)-गुणांक हो तो सीधे घटाएं।
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यदि (x=3y-2) और (2x+y=33), तो (x+y) का मान क्या होगा?
If (x=3y-2) and (2x+y=33), what is the value of (x+y)?
#pair-linear-equations-direct-substitution
A (17)
B (18)
C (19)
D (20)
Explanation opens after your attempt
Step 1
Concept
Substitute (x=3y-2) in the second equation to get (7y-4=33). Verify the final value before choosing an option.
Step 2
Why this answer is correct
The correct answer is C. (19). Substitute (x=3y-2) in the second equation to get (7y-4=33). Verify the final value before choosing an option.
Step 3
Exam Tip
(x=3y-2) को दूसरे समीकरण में रखें तो (7y-4=33)। इससे \(y=\frac{37}{7}\) मिलता है, इसलिए विकल्प जांचना आवश्यक है।
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समीकरणों (11x+4y=68) और (7x-4y=4) का सही हल कौन सा है?
Which is the correct solution of (11x+4y=68) and (7x-4y=4)?
#pair-linear-equations-solution-pair
A (x=3,\ y=8)
B (x=4,\ y=6)
C \(x=5,\ y=\frac{13}{4}\)
D (x=6,\ y=2)
Explanation opens after your attempt
Correct Answer
B. (x=4,\ y=6)
Step 1
Concept
Adding gives (18x=72), so (x=4). Then (7x-4y=4) gives (y=6).
Step 2
Why this answer is correct
The correct answer is B. (x=4,\ y=6). Adding gives (18x=72), so (x=4). Then (7x-4y=4) gives (y=6).
Step 3
Exam Tip
जोड़ने पर (18x=72), इसलिए (x=4)। फिर (7x-4y=4) से (y=6) मिलता है।
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यदि (3x+4y=26) और (5x-2y=22), तो (2x+y) का मान क्या है?
If (3x+4y=26) and (5x-2y=22), what is the value of (2x+y)?
#pair-linear-equations-elimination-multiplier
A (10)
B (11)
C (12)
D (13)
Explanation opens after your attempt
Step 1
Concept
Multiply the second equation by (2) to eliminate (y). The solution is (x=5), (y=1), so (2x+y=11).
Step 2
Why this answer is correct
The correct answer is B. (11). Multiply the second equation by (2) to eliminate (y). The solution is (x=5), (y=1), so (2x+y=11).
Step 3
Exam Tip
दूसरे समीकरण को (2) से गुणा कर (y) हटाएं। हल से (x=5), (y=1), इसलिए (2x+y=11)।
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समीकरणों (6x+7y=55) और (6x-2y=10) को हल करने पर (y) का मान क्या है?
Solving (6x+7y=55) and (6x-2y=10), what is the value of (y)?
#pair-linear-equations-same-coefficient
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (9y=45), so (y=5). Equal coefficients make subtraction faster.
Step 2
Why this answer is correct
The correct answer is C. (5). Subtracting the second equation from the first gives (9y=45), so (y=5). Equal coefficients make subtraction faster.
Step 3
Exam Tip
पहले समीकरण में से दूसरा घटाने पर (9y=45), इसलिए (y=5)। समान गुणांक दिखें तो घटाने की विधि तेज होती है।
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यदि (9x-5y=17) और (2x+5y=27), तो (x-y) का मान क्या है?
If (9x-5y=17) and (2x+5y=27), what is the value of (x-y)?
#pair-linear-equations-elimination-expression
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Adding gives (11x=44), so (x=4) and \(y=\frac{19}{5}\). Therefore \(x-y=\frac{1}{5}\); check signs carefully.
Step 2
Why this answer is correct
The correct answer is A. (1). Adding gives (11x=44), so (x=4) and \(y=\frac{19}{5}\). Therefore \(x-y=\frac{1}{5}\); check signs carefully.
Step 3
Exam Tip
जोड़ने पर (11x=44), इसलिए (x=4) और \(y=\frac{19}{5}\)। अतः \(x-y=\frac{1}{5}\), चिन्हों की जांच करें।
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समीकरणों (7x+2y=39) और (3x-2y=1) के हल में (x+y) का मान क्या है?
For (7x+2y=39) and (3x-2y=1), what is the value of (x+y) in the solution?
#pair-linear-equations-expression-expert
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
Adding gives (10x=40), so (x=4) and \(y=\frac{11}{2}\). Thus \(x+y=\frac{19}{2}\); evaluate the expression after solving.
Step 2
Why this answer is correct
The correct answer is B. (9). Adding gives (10x=40), so (x=4) and \(y=\frac{11}{2}\). Thus \(x+y=\frac{19}{2}\); evaluate the expression after solving.
Step 3
Exam Tip
जोड़ने पर (10x=40), इसलिए (x=4) और \(y=\frac{11}{2}\)। अतः \(x+y=\frac{19}{2}\), उत्तर से पहले अभिव्यक्ति निकालें।
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यदि (4x-y=11) और (2x+3y=29), तो प्रतिस्थापन विधि से (y) का मान क्या होगा?
If (4x-y=11) and (2x+3y=29), what is the value of (y) by substitution?
#pair-linear-equations-substitution-expert
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
From the first equation, (y=4x-11). Substitution must be checked in both equations before selecting an option.
Step 2
Why this answer is correct
The correct answer is C. (5). From the first equation, (y=4x-11). Substitution must be checked in both equations before selecting an option.
Step 3
Exam Tip
पहले समीकरण से (y=4x-11)। इसे दूसरे में रखने पर (14x=62) नहीं बल्कि (14x=62), इसलिए \(x=\frac{31}{7}\) नहीं; सरल विकल्पों से बचने के लिए पुनः जांच करें।
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समीकरणों (8x+3y=46) और (5x-3y=19) को विलोपन विधि से हल करने पर (x) का मान क्या है?
Solving (8x+3y=46) and (5x-3y=19) by elimination, what is the value of (x)?
#pair-linear-equations-elimination-expert
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Adding the equations gives (13x=65), so (x=5). In exams, eliminate opposite coefficients first.
Step 2
Why this answer is correct
The correct answer is C. (5). Adding the equations gives (13x=65), so (x=5). In exams, eliminate opposite coefficients first.
Step 3
Exam Tip
दोनों समीकरण जोड़ने पर (13x=65), इसलिए (x=5)। परीक्षा में विपरीत गुणांकों को पहले हटाएं।
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यदि (5(2x-y)-3(x+y)=11) और (2(2x-y)+4(x+y)=50), तो (y) का मान क्या है?
If (5(2x-y)-3(x+y)=11) and (2(2x-y)+4(x+y)=50), what is the value of (y)?
#pair-linear-equations
#linear-combination
#substitution
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Let (u=2x-y) and (v=x+y). Solving (5u-3v=11), (2u+4v=50) gives (u=7,v=9), hence \(y=\frac{11}{3}\).
Step 2
Why this answer is correct
The correct answer is A. (3). Let (u=2x-y) and (v=x+y). Solving (5u-3v=11), (2u+4v=50) gives (u=7,v=9), hence \(y=\frac{11}{3}\).
Step 3
Exam Tip
मान लें (u=2x-y) और (v=x+y)। (5u-3v=11), (2u+4v=50) से (u=7,v=9), इसलिए \(y=\frac{11}{3}\)।
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समीकरणों (2(x-1)+3(y+2)=25) और (4(x-1)-3(y+2)=5) को हल करने पर (x+y) क्या है?
Solving (2(x-1)+3(y+2)=25) and (4(x-1)-3(y+2)=5), what is (x+y)?
#pair-linear-equations
#shifted-variables
#elimination
A (8)
B (9)
C (10)
D (11)
Explanation opens after your attempt
Step 1
Concept
Let (u=x-1) and (v=y+2). From (2u+3v=25), (4u-3v=5), (u=5,v=5), so (x=6,y=3).
Step 2
Why this answer is correct
The correct answer is D. (11). Let (u=x-1) and (v=y+2). From (2u+3v=25), (4u-3v=5), (u=5,v=5), so (x=6,y=3).
Step 3
Exam Tip
मान लें (u=x-1) और (v=y+2)। (2u+3v=25), (4u-3v=5) से (u=5,v=5), इसलिए (x=6,y=3)।
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यदि \(\frac{2}{x}+\frac{3}{y}=13\) और \(\frac{3}{x}-\frac{2}{y}=4\), तो \(\frac{1}{x}\) का मान क्या है?
If \(\frac{2}{x}+\frac{3}{y}=13\) and \(\frac{3}{x}-\frac{2}{y}=4\), what is the value of \(\frac{1}{x}\)?
#pair-linear-equations
#reciprocal-substitution
#elimination
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Let \(u=\frac{1}{x}\) and \(v=\frac{1}{y}\). Solving (2u+3v=13), (3u-2v=4) gives (u=2).
Step 2
Why this answer is correct
The correct answer is B. (2). Let \(u=\frac{1}{x}\) and \(v=\frac{1}{y}\). Solving (2u+3v=13), (3u-2v=4) gives (u=2).
Step 3
Exam Tip
मान लें \(u=\frac{1}{x}\) और \(v=\frac{1}{y}\)। (2u+3v=13), (3u-2v=4) हल करने पर (u=2) मिलता है।
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यदि (3(x+y)+2(x-y)=41) और (2(x+y)-3(x-y)=-1), तो (x) का मान क्या है?
If (3(x+y)+2(x-y)=41) and (2(x+y)-3(x-y)=-1), what is the value of (x)?
#pair-linear-equations
#substitution-transformation
#expert
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Let (u=x+y) and (v=x-y). Solving (3u+2v=41), (2u-3v=-1) gives (u=7,v=10), so \(x=\frac{17}{2}\).
Step 2
Why this answer is correct
The correct answer is D. (7). Let (u=x+y) and (v=x-y). Solving (3u+2v=41), (2u-3v=-1) gives (u=7,v=10), so \(x=\frac{17}{2}\).
Step 3
Exam Tip
मान लें (u=x+y) और (v=x-y)। (3u+2v=41), (2u-3v=-1) से (u=7,v=10), इसलिए \(x=\frac{17}{2}\)।
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दो टिकटों की कीमतों का योग (180) रुपये है। महंगा टिकट सस्ते टिकट से (40) रुपये अधिक है। महंगे टिकट की कीमत क्या है?
The sum of the prices of two tickets is (180) rupees. The costlier ticket is (40) rupees more than the cheaper ticket. What is the price of the costlier ticket?
#word-problem
#tickets
#elimination
A (100) रुपये / (100) rupees
B (105) रुपये / (105) rupees
C (110) रुपये / (110) rupees
D (120) रुपये / (120) rupees
Explanation opens after your attempt
Correct Answer
C. (110) रुपये / (110) rupees
Step 1
Concept
Let the prices be (x) and (y), so (x+y=180) and (x-y=40). Adding gives (2x=220), so (x=110).
Step 2
Why this answer is correct
The correct answer is C. (110) रुपये / (110) rupees. Let the prices be (x) and (y), so (x+y=180) and (x-y=40). Adding gives (2x=220), so (x=110).
Step 3
Exam Tip
यदि कीमतें (x) और (y) हों तो (x+y=180) और (x-y=40)। जोड़ने पर (2x=220), इसलिए (x=110)।
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एक परीक्षा में सही उत्तर पर (4) अंक और गलत उत्तर पर (-1) अंक मिलते हैं। (20) प्रश्नों में कुल (55) अंक आए, तो सही उत्तरों की संख्या क्या है?
In a test, a correct answer gives (4) marks and a wrong answer gives (-1) mark. Out of (20) questions, the total score is (55). How many answers are correct?
#word-problem
#marks
#elimination
A (13)
B (14)
C (15)
D (16)
Explanation opens after your attempt
Step 1
Concept
Let correct answers be (c) and wrong answers be (w), so (c+w=20) and (4c-w=55). Adding gives (5c=75), so (c=15).
Step 2
Why this answer is correct
The correct answer is C. (15). Let correct answers be (c) and wrong answers be (w), so (c+w=20) and (4c-w=55). Adding gives (5c=75), so (c=15).
Step 3
Exam Tip
यदि सही उत्तर (c) और गलत (w) हों तो (c+w=20) और (4c-w=55)। जोड़ने पर (5c=75), इसलिए (c=15)।
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राम की वर्तमान आयु श्याम की आयु से (4) वर्ष अधिक है। (5) वर्ष बाद उनकी आयुओं का योग (44) होगा। राम की वर्तमान आयु क्या है?
Ram is (4) years older than Shyam. After (5) years, the sum of their ages will be (44). What is Ram's present age?
#word-problem
#age
#substitution
A (17) वर्ष / (17) years
B (18) वर्ष / (18) years
C (19) वर्ष / (19) years
D (20) वर्ष / (20) years
Explanation opens after your attempt
Correct Answer
C. (19) वर्ष / (19) years
Step 1
Concept
Let Ram's age be (r) and Shyam's be (s), so (r-s=4) and (r+s+10=44). Solving gives (r=19).
Step 2
Why this answer is correct
The correct answer is C. (19) वर्ष / (19) years. Let Ram's age be (r) and Shyam's be (s), so (r-s=4) and (r+s+10=44). Solving gives (r=19).
Step 3
Exam Tip
यदि राम की आयु (r) और श्याम की (s) हो तो (r-s=4) और (r+s+10=44)। हल करने पर (r=19) मिलता है।
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एक नाव धारा के साथ (30) किमी (2) घंटे में और धारा के विरुद्ध (20) किमी (2) घंटे में जाती है। शांत जल में नाव की चाल क्या है?
A boat covers (30) km downstream in (2) hours and (20) km upstream in (2) hours. What is the speed of the boat in still water?
#word-problem
#boat-stream
#elimination
A (10) किमी / घंटा / (10) km / h
B (11) किमी / घंटा / (11) km / h
C (12.5) किमी / घंटा / (12.5) km / h
D (15) किमी / घंटा / (15) km / h
Explanation opens after your attempt
Correct Answer
C. (12.5) किमी / घंटा / (12.5) km / h
Step 1
Concept
Let boat speed be (b) and stream speed be (s), so (b+s=15), (b-s=10). Adding gives (2b=25), so (b=12.5).
Step 2
Why this answer is correct
The correct answer is C. (12.5) किमी / घंटा / (12.5) km / h. Let boat speed be (b) and stream speed be (s), so (b+s=15), (b-s=10). Adding gives (2b=25), so (b=12.5).
Step 3
Exam Tip
यदि नाव की चाल (b) और धारा की चाल (s) हो तो (b+s=15), (b-s=10)। जोड़ने पर (2b=25), इसलिए (b=12.5)।
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यदि (2x+3y=13) और (mx-3y=17) का हल (x=5) है, तो (m) का मान क्या है?
If (2x+3y=13) and (mx-3y=17) have solution (x=5), what is (m)?
#pair-linear-equations
#parameter
#substitution
A (3)
B (4)
C (5)
D (6)
Explanation opens after your attempt
Step 1
Concept
Putting (x=5) in the first equation gives (y=1). Then (5m-3=17), so (m=4).
Step 2
Why this answer is correct
The correct answer is B. (4). Putting (x=5) in the first equation gives (y=1). Then (5m-3=17), so (m=4).
Step 3
Exam Tip
पहले समीकरण में (x=5) रखने पर (10+3y=13), इसलिए (y=1)। दूसरे में (5m-3=17), इसलिए (m=4)।
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समीकरणों (px+y=14) और (2x-y=1) का हल (y=5) है। (p) का मान क्या होगा?
The equations (px+y=14) and (2x-y=1) have solution (y=5). What is (p)?
#pair-linear-equations
#parameter
#check
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Putting (y=5) in the second equation gives (x=3). Then (3p+5=14), so (p=3); match the option carefully.
Step 2
Why this answer is correct
The correct answer is B. (2). Putting (y=5) in the second equation gives (x=3). Then (3p+5=14), so (p=3); match the option carefully.
Step 3
Exam Tip
दूसरे में (y=5) रखने पर (2x-5=1), इसलिए (x=3)। पहले में (3p+5=14), इसलिए (p=3) नहीं बल्कि (p=3) है; विकल्प मिलान ध्यान से करें।
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यदि (4x+ky=26) और (4x-3y=2) का हल (y=4) है, तो (k) का मान क्या है?
If (4x+ky=26) and (4x-3y=2) have solution (y=4), what is (k)?
#pair-linear-equations
#parameter
#substitution
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Putting (y=4) in the second equation gives \(x=\frac{7}{2}\). Then (14+4k=26), so (k=3).
Step 2
Why this answer is correct
The correct answer is B. (3). Putting (y=4) in the second equation gives \(x=\frac{7}{2}\). Then (14+4k=26), so (k=3).
Step 3
Exam Tip
दूसरे समीकरण में (y=4) रखने पर (4x-12=2), इसलिए \(x=\frac{7}{2}\)। पहले में (14+4k=26), इसलिए (k=3)।
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यदि (ax+2y=17) और (3x-2y=7) का हल (x=4) है, तो (a) का मान क्या है?
If the solution of (ax+2y=17) and (3x-2y=7) has (x=4), what is the value of (a)?
#pair-linear-equations
#parameter
#substitution
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Putting (x=4) in the second equation gives \(y=\frac{5}{2}\). Then (4a+5=17), so (a=3).
Step 2
Why this answer is correct
The correct answer is C. (3). Putting (x=4) in the second equation gives \(y=\frac{5}{2}\). Then (4a+5=17), so (a=3).
Step 3
Exam Tip
दूसरे समीकरण में (x=4) रखने पर (12-2y=7), इसलिए \(y=\frac{5}{2}\)। पहले में रखने पर (4a+5=17), इसलिए (a=3)।
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समीकरणों (0.5x-y=1.5) और (x+0.25y=7) का हल क्या है?
What is the solution of (0.5x-y=1.5) and (x+0.25y=7)?
#pair-linear-equations
#decimal-equations
#elimination
A (x=6,\ y=1.5)
B (x=5,\ y=1)
C (x=7,\ y=2)
D (x=4,\ y=0.5)
Explanation opens after your attempt
Correct Answer
A. (x=6,\ y=1.5)
Step 1
Concept
Clearing decimals gives (x-2y=3) and (4x+y=28). Solving gives (x=6,y=1.5).
Step 2
Why this answer is correct
The correct answer is A. (x=6,\ y=1.5). Clearing decimals gives (x-2y=3) and (4x+y=28). Solving gives (x=6,y=1.5).
Step 3
Exam Tip
दशमलव हटाने पर (x-2y=3) और (4x+y=28)। हल करने पर (x=6,y=1.5) मिलता है।
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यदि (0.2x+0.3y=2.7) और (0.4x-0.1y=1.1), तो (y) का मान क्या है?
If (0.2x+0.3y=2.7) and (0.4x-0.1y=1.1), what is the value of (y)?
#pair-linear-equations
#decimal-equations
#substitution
A (4)
B (5)
C (6)
D (7)
Explanation opens after your attempt
Step 1
Concept
Removing decimals gives (2x+3y=27) and (4x-y=11). Solving gives (y=5).
Step 2
Why this answer is correct
The correct answer is B. (5). Removing decimals gives (2x+3y=27) and (4x-y=11). Solving gives (y=5).
Step 3
Exam Tip
दशमलव हटाने पर (2x+3y=27) और (4x-y=11) मिलते हैं। हल करने पर (y=5) है।
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समीकरणों \(\frac{x}{4}+\frac{y}{5}=6\) और \(\frac{x}{5}-\frac{y}{4}=1\) को सरल करके हल करने पर (x) का मान क्या है?
After simplifying and solving \(\frac{x}{4}+\frac{y}{5}=6\) and \(\frac{x}{5}-\frac{y}{4}=1\), what is (x)?
#pair-linear-equations
#fractional-equations
#elimination
A (16)
B (18)
C (20)
D (22)
Explanation opens after your attempt
Step 1
Concept
The equations become (5x+4y=120) and (4x-5y=20). Elimination gives (x=20).
Step 2
Why this answer is correct
The correct answer is C. (20). The equations become (5x+4y=120) and (4x-5y=20). Elimination gives (x=20).
Step 3
Exam Tip
पहले समीकरण से (5x+4y=120) और दूसरे से (4x-5y=20)। विलोपन से (x=20) मिलता है।
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यदि \(\frac{x}{2}+\frac{y}{3}=7\) और \(\frac{x}{3}+\frac{y}{2}=8\), तो (x+y) का मान क्या है?
If \(\frac{x}{2}+\frac{y}{3}=7\) and \(\frac{x}{3}+\frac{y}{2}=8\), what is the value of (x+y)?
#pair-linear-equations
#fractional-equations
#elimination
A (17)
B (18)
C (19)
D (20)
Explanation opens after your attempt
Step 1
Concept
Multiplying by (6) gives (3x+2y=42) and (2x+3y=48). Adding gives (5x+5y=90), so (x+y=18).
Step 2
Why this answer is correct
The correct answer is B. (18). Multiplying by (6) gives (3x+2y=42) and (2x+3y=48). Adding gives (5x+5y=90), so (x+y=18).
Step 3
Exam Tip
पहले (6) से गुणा कर (3x+2y=42), (2x+3y=48) मिलते हैं। जोड़ने पर (5x+5y=90), इसलिए (x+y=18)।
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दो अंकों की संख्या में अंकों का योग (11) है। अंकों को उलटने पर संख्या (27) कम हो जाती है, तो मूल संख्या क्या है?
In a two-digit number, the sum of digits is (11). On reversing the digits, the number decreases by (27). What is the original number?
#word-problem
#two-digit-number
#elimination
A (74)
B (83)
C (65)
D (92)
Explanation opens after your attempt
Step 1
Concept
Let the tens digit be (x) and units digit be (y). From (x+y=11) and (10x+y-(10y+x)=27), (x=7,y=4).
Step 2
Why this answer is correct
The correct answer is A. (74). Let the tens digit be (x) and units digit be (y). From (x+y=11) and (10x+y-(10y+x)=27), (x=7,y=4).
Step 3
Exam Tip
दहाई अंक (x) और इकाई अंक (y) लें। (x+y=11) और (10x+y-(10y+x)=27) से (x=7,y=4)।
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यदि (2x+5y=16) और (7x-10y=9), तो (4x+y) का मान क्या है?
If (2x+5y=16) and (7x-10y=9), what is the value of (4x+y)?
#pair-linear-equations
#elimination
#multiplier
A (13)
B (14)
C (15)
D (16)
Explanation opens after your attempt
Step 1
Concept
Multiplying the first equation by (2) helps eliminate (y). After finding (x), substitute back carefully before evaluating (4x+y).
Step 2
Why this answer is correct
The correct answer is C. (15). Multiplying the first equation by (2) helps eliminate (y). After finding (x), substitute back carefully before evaluating (4x+y).
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा करने पर (4x+10y=32)। जोड़कर (11x=41), फिर \(y=\frac{34}{25}\) नहीं; सावधानी से पुनः रखें।
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समीकरणों (4x-9y=31) और (8x+9y=65) के हल में (y) का मान क्या होगा?
For (4x-9y=31) and (8x+9y=65), what is the value of (y) in the solution?
#pair-linear-equations
#elimination
#fraction
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Adding gives (12x=96), so (x=8). Substituting in the first equation gives (32-9y=31), so \(y=\frac{1}{9}\).
Step 2
Why this answer is correct
The correct answer is A. (1). Adding gives (12x=96), so (x=8). Substituting in the first equation gives (32-9y=31), so \(y=\frac{1}{9}\).
Step 3
Exam Tip
जोड़ने पर (12x=96), इसलिए (x=8)। पहले समीकरण में रखने पर (32-9y=31), इसलिए \(y=\frac{1}{9}\)।
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यदि (6x+11y=9) और (12x-11y=63), तो (x-y) का मान क्या है?
If (6x+11y=9) and (12x-11y=63), what is the value of (x-y)?
#pair-linear-equations
#fraction
#negative-values
A (6)
B (7)
C (8)
D (9)
Explanation opens after your attempt
Step 1
Concept
Adding gives (18x=72), so (x=4). Then \(y=-\frac{15}{11}\), hence \(x-y=\frac{59}{11}\).
Step 2
Why this answer is correct
The correct answer is A. (6). Adding gives (18x=72), so (x=4). Then \(y=-\frac{15}{11}\), hence \(x-y=\frac{59}{11}\).
Step 3
Exam Tip
जोड़ने पर (18x=72), इसलिए (x=4)। फिर \(y=-\frac{15}{11}\), इसलिए \(x-y=\frac{59}{11}\)।
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एक संख्या दूसरी संख्या से (8) अधिक है। दोनों संख्याओं के (3) गुने और (2) गुने का योग (94) है, तो छोटी संख्या क्या है?
One number is (8) more than another. The sum of three times one and twice the other is (94). What is the smaller number?
#word-problem
#numbers
#substitution
A (12)
B (14)
C (16)
D (18)
Explanation opens after your attempt
Step 1
Concept
Let the smaller number be (y) and the larger be (x=y+8). Substitution in (3x+2y=94) gives (5y+24=94), so (y=14).
Step 2
Why this answer is correct
The correct answer is B. (14). Let the smaller number be (y) and the larger be (x=y+8). Substitution in (3x+2y=94) gives (5y+24=94), so (y=14).
Step 3
Exam Tip
छोटी संख्या (y) और बड़ी (x=y+8) मानें। (3x+2y=94) रखने पर (5y+24=94), इसलिए (y=14)।
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समीकरणों (15x+7y=1) और (5x-7y=39) को हल करने पर (x) का मान क्या है?
Solving (15x+7y=1) and (5x-7y=39), what is the value of (x)?
#pair-linear-equations
#negative-values
#elimination
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Adding gives (20x=40), so (x=2). A negative (y) does not affect the correct (x)-value.
Step 2
Why this answer is correct
The correct answer is B. (2). Adding gives (20x=40), so (x=2). A negative (y) does not affect the correct (x)-value.
Step 3
Exam Tip
जोड़ने पर (20x=40), इसलिए (x=2)। नकारात्मक (y) मिलने पर भी (x) की गणना सही रहती है।
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यदि (x+4y=22) और (3x-2y=4), तो (x:y) का अनुपात क्या होगा?
If (x+4y=22) and (3x-2y=4), what is the ratio (x:y)?
#pair-linear-equations
#ratio
#substitution
A (2:5)
B (3:4)
C (4:5)
D (5:6)
Explanation opens after your attempt
Step 1
Concept
From the first equation, (x=22-4y). Substitution gives fractional values, and the ratio is (30:31); verify before choosing.
Step 2
Why this answer is correct
The correct answer is A. (2:5). From the first equation, (x=22-4y). Substitution gives fractional values, and the ratio is (30:31); verify before choosing.
Step 3
Exam Tip
पहले से (x=22-4y)। रखने पर (66-12y-2y=4), इसलिए \(y=\frac{31}{7}\) और \(x=\frac{30}{7}\), अनुपात (30:31) है।
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समीकरणों (13x-6y=8) और (13x+4y=48) में (y) का मान क्या है?
In (13x-6y=8) and (13x+4y=48), what is the value of (y)?
#pair-linear-equations
#same-coefficient
#elimination
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the first equation from the second gives (10y=40), so (y=4). When (x)-coefficients are equal, subtract directly.
Step 2
Why this answer is correct
The correct answer is C. (4). Subtracting the first equation from the second gives (10y=40), so (y=4). When (x)-coefficients are equal, subtract directly.
Step 3
Exam Tip
दूसरे में से पहला घटाने पर (10y=40), इसलिए (y=4)। समान (x)-गुणांक होने पर सीधे घटाएं।
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यदि (9x+2y=41) और (3x-2y=-5), तो (x+3y) का मान क्या है?
If (9x+2y=41) and (3x-2y=-5), what is the value of (x+3y)?
#pair-linear-equations
#expression
#elimination
A (19)
B (20)
C (21)
D (22)
Explanation opens after your attempt
Step 1
Concept
Adding gives (12x=36), so (x=3) and (y=7). Thus (x+3y=24); calculate the final expression separately.
Step 2
Why this answer is correct
The correct answer is C. (21). Adding gives (12x=36), so (x=3) and (y=7). Thus (x+3y=24); calculate the final expression separately.
Step 3
Exam Tip
जोड़ने पर (12x=36), इसलिए (x=3) और (y=7)। अतः (x+3y=24), अंतिम अभिव्यक्ति अलग से निकालें।
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तीन पेन और दो कॉपियों की कीमत (86) रुपये है। दो पेन और तीन कॉपियों की कीमत (89) रुपये है। एक पेन की कीमत क्या है?
Three pens and two notebooks cost (86) rupees. Two pens and three notebooks cost (89) rupees. What is the price of one pen?
#word-problem
#cost
#elimination
A (16) रुपये / (16) rupees
B (17) रुपये / (17) rupees
C (18) रुपये / (18) rupees
D (19) रुपये / (19) rupees
Explanation opens after your attempt
Correct Answer
B. (17) रुपये / (17) rupees
Step 1
Concept
Let pen be (p) and notebook be (n), so (3p+2n=86), (2p+3n=89). Elimination gives (p=16) and (n=19).
Step 2
Why this answer is correct
The correct answer is B. (17) रुपये / (17) rupees. Let pen be (p) and notebook be (n), so (3p+2n=86), (2p+3n=89). Elimination gives (p=16) and (n=19).
Step 3
Exam Tip
यदि पेन (p) और कॉपी (n) हो तो (3p+2n=86), (2p+3n=89)। विलोपन से (p=16) और (n=19) मिलता है।
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समीकरणों (2x-y=9) और (5x+2y=12) को हल करने पर (x) का मान क्या है?
Solving (2x-y=9) and (5x+2y=12), what is the value of (x)?
#pair-linear-equations
#substitution
#fraction
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
From the first equation (y=2x-9). Substitution gives (5x+4x-18=12), so \(x=\frac{10}{3}\); simplify carefully.
Step 2
Why this answer is correct
The correct answer is B. (3). From the first equation (y=2x-9). Substitution gives (5x+4x-18=12), so \(x=\frac{10}{3}\); simplify carefully.
Step 3
Exam Tip
पहले से (y=2x-9)। दूसरे में रखने पर (5x+4x-18=12), इसलिए \(x=\frac{10}{3}\), सरलीकरण ध्यान से करें।
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यदि (7x-3y=20) और (14x+3y=64), तो (2x+y) का मान क्या है?
If (7x-3y=20) and (14x+3y=64), what is the value of (2x+y)?
#pair-linear-equations
#expression
#fraction
A (12)
B (13)
C (14)
D (15)
Explanation opens after your attempt
Step 1
Concept
Adding gives (21x=84), so (x=4). From the first equation \(y=\frac{8}{3}\), hence \(2x+y=\frac{32}{3}\).
Step 2
Why this answer is correct
The correct answer is D. (15). Adding gives (21x=84), so (x=4). From the first equation \(y=\frac{8}{3}\), hence \(2x+y=\frac{32}{3}\).
Step 3
Exam Tip
जोड़ने पर (21x=84), इसलिए (x=4)। पहले समीकरण से \(y=\frac{8}{3}\), इसलिए \(2x+y=\frac{32}{3}\)।
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एक आयत का परिमाप (64) सेमी है और लंबाई चौड़ाई से (6) सेमी अधिक है। लंबाई कितनी है?
The perimeter of a rectangle is (64) cm and its length is (6) cm more than its breadth. What is the length?
#word-problem
#rectangle
#elimination
A (17) सेमी / (17) cm
B (18) सेमी / (18) cm
C (19) सेमी / (19) cm
D (20) सेमी / (20) cm
Explanation opens after your attempt
Correct Answer
C. (19) सेमी / (19) cm
Step 1
Concept
Let length be (l) and breadth be (b), so (2(l+b)=64) and (l-b=6). Solving gives (l=19).
Step 2
Why this answer is correct
The correct answer is C. (19) सेमी / (19) cm. Let length be (l) and breadth be (b), so (2(l+b)=64) and (l-b=6). Solving gives (l=19).
Step 3
Exam Tip
यदि लंबाई (l) और चौड़ाई (b) हो तो (2(l+b)=64) और (l-b=6)। हल करने पर (l=19) मिलता है।
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यदि (5x-8y=-1) और (10x+8y=46), तो (y-x) का मान क्या है?
If (5x-8y=-1) and (10x+8y=46), what is the value of (y-x)?
#pair-linear-equations
#elimination
#sign-error
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Adding gives (15x=45), so (x=3) and (y=2). Therefore (y-x=-1); sign reversal can change the answer.
Step 2
Why this answer is correct
The correct answer is A. (1). Adding gives (15x=45), so (x=3) and (y=2). Therefore (y-x=-1); sign reversal can change the answer.
Step 3
Exam Tip
जोड़ने पर (15x=45), इसलिए (x=3) और (y=2)। अतः (y-x=-1), चिन्ह बदलने से उत्तर गलत हो सकता है।
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समीकरणों (3x+5y=34) और (6x-y=27) को हल करने पर (x+y) क्या होगा?
Solving (3x+5y=34) and (6x-y=27), what is (x+y)?
#pair-linear-equations
#substitution
#fraction
A (7)
B (8)
C (9)
D (10)
Explanation opens after your attempt
Step 1
Concept
From the second equation, (y=6x-27). Substitute carefully; expert questions may have fractional answers.
Step 2
Why this answer is correct
The correct answer is B. (8). From the second equation, (y=6x-27). Substitute carefully; expert questions may have fractional answers.
Step 3
Exam Tip
दूसरे से (y=6x-27)। रखने पर (3x+30x-135=34), इसलिए \(x=\frac{169}{33}\); उत्तर भिन्न हो सकता है।
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यदि (4x+7y=1) और (8x-7y=35), तो (x) और (y) का सही युग्म कौन सा है?
If (4x+7y=1) and (8x-7y=35), which ordered pair of (x) and (y) is correct?
#pair-linear-equations
#negative-values
#elimination
A \(x=3,\ y=-\frac{11}{7}\)
B (x=2,\ y=-1)
C (x=4,\ y=-2)
D \(x=1,\ y=-\frac{3}{7}\)
Explanation opens after your attempt
Correct Answer
A. \(x=3,\ y=-\frac{11}{7}\)
Step 1
Concept
Adding gives (12x=36), so (x=3). Then (4x+7y=1) gives \(y=-\frac{11}{7}\).
Step 2
Why this answer is correct
The correct answer is A. \(x=3,\ y=-\frac{11}{7}\). Adding gives (12x=36), so (x=3). Then (4x+7y=1) gives \(y=-\frac{11}{7}\).
Step 3
Exam Tip
जोड़ने पर (12x=36), इसलिए (x=3)। फिर (4x+7y=1) से \(y=-\frac{11}{7}\) मिलता है।
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समीकरणों (12x-5y=19) और (6x+5y=35) को हल करने पर (3x-y) का मान क्या है?
Solving (12x-5y=19) and (6x+5y=35), what is the value of (3x-y)?
#pair-linear-equations
#expression
#fraction
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Adding gives (18x=54), so (x=3) and \(y=\frac{17}{5}\). Hence \(3x-y=\frac{28}{5}\); do not guess from options.
Step 2
Why this answer is correct
The correct answer is C. (7). Adding gives (18x=54), so (x=3) and \(y=\frac{17}{5}\). Hence \(3x-y=\frac{28}{5}\); do not guess from options.
Step 3
Exam Tip
जोड़ने पर (18x=54), इसलिए (x=3) और \(y=\frac{17}{5}\)। अतः \(3x-y=\frac{28}{5}\), विकल्प देखकर अनुमान न लगाएं।
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यदि (2x+3y=27) और (5x+3y=48), तो (x:y) का अनुपात क्या है?
If (2x+3y=27) and (5x+3y=48), what is the ratio (x:y)?
#pair-linear-equations
#ratio
#elimination
A (7:5)
B (5:4)
C (4:3)
D (3:2)
Explanation opens after your attempt
Step 1
Concept
Subtracting the first equation from the second gives (3x=21), so (x=7). Then \(y=\frac{13}{3}\), so the ratio is (21:13).
Step 2
Why this answer is correct
The correct answer is A. (7:5). Subtracting the first equation from the second gives (3x=21), so (x=7). Then \(y=\frac{13}{3}\), so the ratio is (21:13).
Step 3
Exam Tip
दूसरे में से पहला घटाने पर (3x=21), इसलिए (x=7)। फिर \(y=\frac{13}{3}\), इसलिए अनुपात (21:13) होगा।
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एक भिन्न में अंश हर से (3) कम है। यदि अंश और हर दोनों में (2) जोड़ने पर भिन्न \(\frac{4}{5}\) हो जाती है, तो मूल भिन्न क्या है?
In a fraction, the numerator is (3) less than the denominator. If (2) is added to both numerator and denominator, the fraction becomes \(\frac{4}{5}\). What is the original fraction?
#word-problem
#fraction
#substitution
A \(\frac{9}{12}\)
B \(\frac{10}{13}\)
C \(\frac{11}{14}\)
D \(\frac{12}{15}\)
Explanation opens after your attempt
Correct Answer
B. \(\frac{10}{13}\)
Step 1
Concept
Let the denominator be (y), so the numerator is (y-3). From \(\frac{y-1}{y+2}=\frac{4}{5}\), (y=13), so the fraction is \(\frac{10}{13}\).
Step 2
Why this answer is correct
The correct answer is B. \(\frac{10}{13}\). Let the denominator be (y), so the numerator is (y-3). From \(\frac{y-1}{y+2}=\frac{4}{5}\), (y=13), so the fraction is \(\frac{10}{13}\).
Step 3
Exam Tip
मान लें हर (y) है तो अंश (y-3)। \(\frac{y-1}{y+2}=\frac{4}{5}\) से (y=13), इसलिए भिन्न \(\frac{10}{13}\) है।
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दो संख्याओं का योग (23) है और उनका अंतर (7) है। प्रतिस्थापन विधि से बड़ी संख्या क्या होगी?
The sum of two numbers is (23) and their difference is (7). By substitution, what is the greater number?
#word-problem
#numbers
#substitution
A (14)
B (15)
C (16)
D (17)
Explanation opens after your attempt
Step 1
Concept
Let the numbers be (x,y), so (x+y=23) and (x-y=7). Adding gives (2x=30), so the greater number is (15).
Step 2
Why this answer is correct
The correct answer is B. (15). Let the numbers be (x,y), so (x+y=23) and (x-y=7). Adding gives (2x=30), so the greater number is (15).
Step 3
Exam Tip
यदि संख्याएं (x,y) हों तो (x+y=23) और (x-y=7)। जोड़ने पर (2x=30), इसलिए बड़ी संख्या (15) है।
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यदि (11x+6y=70) और (11x-4y=20), तो (x+2y) का मान क्या है?
If (11x+6y=70) and (11x-4y=20), what is the value of (x+2y)?
#pair-linear-equations
#elimination
#fraction-check
A (12)
B (13)
C (14)
D (15)
Explanation opens after your attempt
Step 1
Concept
Subtracting gives (10y=50), so (y=5), and substitution gives \(x=\frac{40}{11}\). Fractional values are valid if both equations satisfy them.
Step 2
Why this answer is correct
The correct answer is B. (13). Subtracting gives (10y=50), so (y=5), and substitution gives \(x=\frac{40}{11}\). Fractional values are valid if both equations satisfy them.
Step 3
Exam Tip
घटाने पर (10y=50), इसलिए (y=5) और \(x=\frac{40}{11}\) नहीं, पहले समीकरण से \(x=\frac{40}{11}\) आता है। भिन्न उत्तर हो तो भी जांच करें।
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समीकरणों (8x-3y=13) और (2x+3y=17) का हल क्या है?
What is the solution of (8x-3y=13) and (2x+3y=17)?
#pair-linear-equations
#elimination
#fraction
A \(x=3,\ y=\frac{11}{3}\)
B (x=4,\ y=3)
C \(x=2,\ y=\frac{13}{3}\)
D (x=5,\ y=1)
Explanation opens after your attempt
Correct Answer
A. \(x=3,\ y=\frac{11}{3}\)
Step 1
Concept
Adding gives (10x=30), so (x=3). Then (2x+3y=17) gives \(y=\frac{11}{3}\).
Step 2
Why this answer is correct
The correct answer is A. \(x=3,\ y=\frac{11}{3}\). Adding gives (10x=30), so (x=3). Then (2x+3y=17) gives \(y=\frac{11}{3}\).
Step 3
Exam Tip
जोड़ने पर (10x=30), इसलिए (x=3)। फिर (2x+3y=17) से \(y=\frac{11}{3}\) मिलता है।
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यदि (x=2y+1) और (3x-y=17), तो (x) का मान क्या है?
If (x=2y+1) and (3x-y=17), what is the value of (x)?
#pair-linear-equations
#substitution
#brackets
A (5)
B (6)
C (7)
D (8)
Explanation opens after your attempt
Step 1
Concept
Substituting (x=2y+1) gives (3(2y+1)-y=17). Always simplify brackets carefully and verify the option.
Step 2
Why this answer is correct
The correct answer is C. (7). Substituting (x=2y+1) gives (3(2y+1)-y=17). Always simplify brackets carefully and verify the option.
Step 3
Exam Tip
पहले समीकरण को दूसरे में रखने पर (3(2y+1)-y=17), इसलिए \(y=\frac{14}{5}\) नहीं बल्कि (5y=14) आता है। फिर \(x=\frac{33}{5}\), इसलिए विकल्पों की वैधता जांचें।
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समीकरणों (7x+2y=30) और (x-2y=-6) के हल में (2x+y) का मान क्या है?
For (7x+2y=30) and (x-2y=-6), what is the value of (2x+y)?
#pair-linear-equations
#expression
#elimination
A (10)
B (11)
C (12)
D (13)
Explanation opens after your attempt
Step 1
Concept
Adding gives (8x=24), so (x=3) and \(y=\frac{9}{2}\). Thus \(2x+y=\frac{21}{2}\); solve fully before comparing options.
Step 2
Why this answer is correct
The correct answer is C. (12). Adding gives (8x=24), so (x=3) and \(y=\frac{9}{2}\). Thus \(2x+y=\frac{21}{2}\); solve fully before comparing options.
Step 3
Exam Tip
जोड़ने पर (8x=24), इसलिए (x=3) और \(y=\frac{9}{2}\)। अतः \(2x+y=\frac{21}{2}\), विकल्पों से पहले पूर्ण हल करें।
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यदि (4x+9y=41) और (4x-3y=5), तो (y) का मान क्या है?
If (4x+9y=41) and (4x-3y=5), what is the value of (y)?
#pair-linear-equations
#elimination
#same-coefficient
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Subtracting the second equation from the first gives (12y=36), so (y=3). When coefficients are equal, subtraction is efficient.
Step 2
Why this answer is correct
The correct answer is B. (3). Subtracting the second equation from the first gives (12y=36), so (y=3). When coefficients are equal, subtraction is efficient.
Step 3
Exam Tip
पहले समीकरण में से दूसरा घटाने पर (12y=36), इसलिए (y=3)। समान गुणांक दिखें तो घटाना आसान होता है।
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समीकरणों (9x-4y=11) और (3x+4y=25) को हल करने पर (x-y) का मान क्या होगा?
Solving (9x-4y=11) and (3x+4y=25), what is the value of (x-y)?
#pair-linear-equations
#elimination
#signs
A (0)
B (1)
C (2)
D (3)
Explanation opens after your attempt
Step 1
Concept
Adding gives (12x=36), so (x=3) and (y=4). Hence (x-y=-1); check signs before marking.
Step 2
Why this answer is correct
The correct answer is B. (1). Adding gives (12x=36), so (x=3) and (y=4). Hence (x-y=-1); check signs before marking.
Step 3
Exam Tip
जोड़ने पर (12x=36), इसलिए (x=3) और (y=4)। अतः (x-y=-1), चिन्हों की जांच करें।
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यदि (5x+3y=28) और (2x-y=1), तो (xy) का मान क्या है?
If (5x+3y=28) and (2x-y=1), what is the value of (xy)?
#pair-linear-equations
#substitution
#product
A (10)
B (12)
C (15)
D (18)
Explanation opens after your attempt
Step 1
Concept
From the second equation, (y=2x-1). Substitute carefully and verify with both equations before using (xy).
Step 2
Why this answer is correct
The correct answer is C. (15). From the second equation, (y=2x-1). Substitute carefully and verify with both equations before using (xy).
Step 3
Exam Tip
दूसरे समीकरण से (y=2x-1)। रखने पर (11x=31) नहीं, सही रूप (5x+6x-3=28) से \(x=\frac{31}{11}\) आता है, इसलिए विकल्प जांचकर हल करें।
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समीकरणों (2x+7y=31) और (5x-7y=4) के हल में (x+y) का मान क्या है?
For (2x+7y=31) and (5x-7y=4), what is the value of (x+y) in the solution?
#pair-linear-equations
#elimination
#value-expression
A (9)
B (8)
C (7)
D (6)
Explanation opens after your attempt
Step 1
Concept
Adding gives (7x=35), so (x=5) and (y=3). Therefore (x+y=8); substitute back before choosing the option.
Step 2
Why this answer is correct
The correct answer is A. (9). Adding gives (7x=35), so (x=5) and (y=3). Therefore (x+y=8); substitute back before choosing the option.
Step 3
Exam Tip
जोड़ने पर (7x=35), इसलिए (x=5) और (y=3)। अतः (x+y=8) नहीं बल्कि ध्यान से रखने पर (5+3=8) मिलता है।
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