Concept-wise Practice

multiplier MCQ Questions for Class 10

multiplier se related questions ko ek jagah revise karein. Har question me bilingual content, answer feedback aur explanation available hai.

Practice Questions

9 questions tagged with multiplier.

यदि (2x+5y=16) और (7x-10y=9), तो (4x+y) का मान क्या है?

If (2x+5y=16) and (7x-10y=9), what is the value of (4x+y)?

Explanation opens after your attempt
Correct Answer

C. (15)

Step 1

Concept

Multiplying the first equation by (2) helps eliminate (y). After finding (x), substitute back carefully before evaluating (4x+y).

Step 2

Why this answer is correct

The correct answer is C. (15). Multiplying the first equation by (2) helps eliminate (y). After finding (x), substitute back carefully before evaluating (4x+y).

Step 3

Exam Tip

पहले समीकरण को (2) से गुणा करने पर (4x+10y=32)। जोड़कर (11x=41), फिर \(y=\frac{34}{25}\) नहीं; सावधानी से पुनः रखें।

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समीकरणों (6x-15y=9) और (4x+5y=23) में (y) हटाने के लिए दूसरे समीकरण को किससे गुणा करना चाहिए?

In (6x-15y=9) and (4x+5y=23), by what should the second equation be multiplied to eliminate (y)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

Multiplying the second equation by (3) gives (15y). It cancels with (-15y) in the first equation.

Step 2

Why this answer is correct

The correct answer is B. (3). Multiplying the second equation by (3) gives (15y). It cancels with (-15y) in the first equation.

Step 3

Exam Tip

दूसरे समीकरण को (3) से गुणा करने पर (15y) मिलेगा। यह पहले समीकरण के (-15y) के साथ कट जाएगा।

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समीकरणों (4x-9y=13) और (5x+3y=41) में (y) हटाने के लिए दूसरे समीकरण को किस संख्या से गुणा करना चाहिए?

In (4x-9y=13) and (5x+3y=41), by what number should the second equation be multiplied to eliminate (y)?

Explanation opens after your attempt
Correct Answer

B. (3)

Step 1

Concept

Multiplying the second equation by (3) gives (9y). It cancels with (-9y) in the first equation.

Step 2

Why this answer is correct

The correct answer is B. (3). Multiplying the second equation by (3) gives (9y). It cancels with (-9y) in the first equation.

Step 3

Exam Tip

दूसरे समीकरण को (3) से गुणा करने पर (9y) मिलता है। यह पहले समीकरण के (-9y) के साथ हट जाएगा।

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समीकरणों (5x-6y=11) और (3x+2y=9) में (y) हटाने के लिए दूसरे समीकरण को किससे गुणा करना चाहिए?

In (5x-6y=11) and (3x+2y=9), by what should the second equation be multiplied to eliminate (y)?

Explanation opens after your attempt
Correct Answer

D. (3)

Step 1

Concept

Multiplying the second equation by (3) gives (6y). It cancels with (-6y) in the first equation.

Step 2

Why this answer is correct

The correct answer is D. (3). Multiplying the second equation by (3) gives (6y). It cancels with (-6y) in the first equation.

Step 3

Exam Tip

दूसरे समीकरण को (3) से गुणा करने पर (6y) मिलेगा। यह पहले समीकरण के (-6y) के साथ हट जाएगा।

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(2x-3y=7) के साथ (y) हटाने के लिए कौन-से समीकरण को (3) से गुणा करना सही होगा?

Which equation should be multiplied by (3) to eliminate (y) with (2x-3y=7)?

Explanation opens after your attempt
Correct Answer

A. (x+y=5)

Step 1

Concept

Multiplying (x+y=5) by (3) gives (3x+3y=15). It cancels (y) with (-3y) by addition.

Step 2

Why this answer is correct

The correct answer is A. (x+y=5). Multiplying (x+y=5) by (3) gives (3x+3y=15). It cancels (y) with (-3y) by addition.

Step 3

Exam Tip

(x+y=5) को (3) से गुणा करने पर (3x+3y=15) मिलता है। यह (-3y) के साथ जुड़कर (y) हटाता है।

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(3x+4y=17) के साथ (5x-2y=1) में (y) हटाने के लिए दूसरे समीकरण को किस संख्या से गुणा करना चाहिए?

By what number should (5x-2y=1) be multiplied to eliminate (y) with (3x+4y=17)?

Explanation opens after your attempt
Correct Answer

B. (2)

Step 1

Concept

Multiplying the second equation by (2) gives (-4y). It cancels with (4y) by addition.

Step 2

Why this answer is correct

The correct answer is B. (2). Multiplying the second equation by (2) gives (-4y). It cancels with (4y) by addition.

Step 3

Exam Tip

दूसरे समीकरण को (2) से गुणा करने पर (-4y) मिलेगा। यह (4y) के साथ जुड़कर हट जाएगा।

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किस समीकरण को (3) से गुणा करके (3x+2y=16) के साथ (x) हटाया जा सकता है?

Which equation can be multiplied by (3) to eliminate (x) with (3x+2y=16)?

Explanation opens after your attempt
Correct Answer

B. (-x+y=2)

Step 1

Concept

Multiplying (-x+y=2) by (3) gives (-3x+3y=6). This cancels (3x) by addition.

Step 2

Why this answer is correct

The correct answer is B. (-x+y=2). Multiplying (-x+y=2) by (3) gives (-3x+3y=6). This cancels (3x) by addition.

Step 3

Exam Tip

(-x+y=2) को (3) से गुणा करने पर (-3x+3y=6) बनता है। यह (3x) को जोड़कर हटा देगा।

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किस संख्या से (2x+3y=13) को गुणा करना चाहिए ताकि (4x-5y=1) के साथ (x) हट सके?

By what number should (2x+3y=13) be multiplied so that (x) can be eliminated with (4x-5y=1)?

Explanation opens after your attempt
Correct Answer

B. (-2)

Step 1

Concept

Multiplying (2x) by (-2) gives (-4x). It cancels with (4x) when added.

Step 2

Why this answer is correct

The correct answer is B. (-2). Multiplying (2x) by (-2) gives (-4x). It cancels with (4x) when added.

Step 3

Exam Tip

(2x) को (-2) से गुणा करने पर (-4x) बनेगा। यह (4x) के साथ जुड़कर हट जाएगा।

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यदि \(x=2^2\times3^3\times5\) है, तो (x) को पूर्ण वर्ग बनाने के लिए सबसे छोटी गुणक संख्या कौन सी है?

If \(x=2^2\times3^3\times5\), what is the smallest multiplier that makes (x) a perfect square?

Explanation opens after your attempt
Correct Answer

A. \(3\times5\)

Step 1

Concept

A perfect square needs all exponents to be even.

Step 2

Why this answer is correct

\(2^2\) is already fine, \(3^3\) needs one (3), and \(5^1\) needs one (5).

Step 3

Exam Tip

Make only the odd exponents even. चरण 1: पूर्ण वर्ग में सभी घातें सम होनी चाहिए। चरण 2: \(2^2\) ठीक है, \(3^3\) को \(3^4\) बनाने के लिए (3) और \(5^1\) को \(5^2\) बनाने के लिए (5) चाहिए। चरण 3: केवल विषम घातों को एक-एक बढ़ाकर सम बनाएं।

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