यदि (2x+5y=16) और (7x-10y=9), तो (4x+y) का मान क्या है?
If (2x+5y=16) and (7x-10y=9), what is the value of (4x+y)?
#pair-linear-equations
#elimination
#multiplier
A (13)
B (14)
C (15)
D (16)
Explanation opens after your attempt
Step 1
Concept
Multiplying the first equation by (2) helps eliminate (y). After finding (x), substitute back carefully before evaluating (4x+y).
Step 2
Why this answer is correct
The correct answer is C. (15). Multiplying the first equation by (2) helps eliminate (y). After finding (x), substitute back carefully before evaluating (4x+y).
Step 3
Exam Tip
पहले समीकरण को (2) से गुणा करने पर (4x+10y=32)। जोड़कर (11x=41), फिर \(y=\frac{34}{25}\) नहीं; सावधानी से पुनः रखें।
Login to save your score, XP, coins and progress. Login
समीकरणों (6x-15y=9) और (4x+5y=23) में (y) हटाने के लिए दूसरे समीकरण को किससे गुणा करना चाहिए?
In (6x-15y=9) and (4x+5y=23), by what should the second equation be multiplied to eliminate (y)?
#linear equations
#elimination
#multiplier
#expert
#class 10
A (2)
B (3)
C (4)
D (5)
Explanation opens after your attempt
Step 1
Concept
Multiplying the second equation by (3) gives (15y). It cancels with (-15y) in the first equation.
Step 2
Why this answer is correct
The correct answer is B. (3). Multiplying the second equation by (3) gives (15y). It cancels with (-15y) in the first equation.
Step 3
Exam Tip
दूसरे समीकरण को (3) से गुणा करने पर (15y) मिलेगा। यह पहले समीकरण के (-15y) के साथ कट जाएगा।
Login to save your score, XP, coins and progress. Login
समीकरणों (4x-9y=13) और (5x+3y=41) में (y) हटाने के लिए दूसरे समीकरण को किस संख्या से गुणा करना चाहिए?
In (4x-9y=13) and (5x+3y=41), by what number should the second equation be multiplied to eliminate (y)?
#linear equations
#elimination
#multiplier
#hard
#class 10
A (2)
B (3)
C (-3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Multiplying the second equation by (3) gives (9y). It cancels with (-9y) in the first equation.
Step 2
Why this answer is correct
The correct answer is B. (3). Multiplying the second equation by (3) gives (9y). It cancels with (-9y) in the first equation.
Step 3
Exam Tip
दूसरे समीकरण को (3) से गुणा करने पर (9y) मिलता है। यह पहले समीकरण के (-9y) के साथ हट जाएगा।
Login to save your score, XP, coins and progress. Login
समीकरणों (5x-6y=11) और (3x+2y=9) में (y) हटाने के लिए दूसरे समीकरण को किससे गुणा करना चाहिए?
In (5x-6y=11) and (3x+2y=9), by what should the second equation be multiplied to eliminate (y)?
#linear equations
#elimination
#multiplier
#hard
#class 10
A (1)
B (2)
C (-2)
D (3)
Explanation opens after your attempt
Step 1
Concept
Multiplying the second equation by (3) gives (6y). It cancels with (-6y) in the first equation.
Step 2
Why this answer is correct
The correct answer is D. (3). Multiplying the second equation by (3) gives (6y). It cancels with (-6y) in the first equation.
Step 3
Exam Tip
दूसरे समीकरण को (3) से गुणा करने पर (6y) मिलेगा। यह पहले समीकरण के (-6y) के साथ हट जाएगा।
Login to save your score, XP, coins and progress. Login
(2x-3y=7) के साथ (y) हटाने के लिए कौन-से समीकरण को (3) से गुणा करना सही होगा?
Which equation should be multiplied by (3) to eliminate (y) with (2x-3y=7)?
#linear-equations
#elimination
#multiplier
#medium
#class-10
A (x+y=5)
B (x-y=5)
C (2x+y=8)
D (3x-y=4)
Explanation opens after your attempt
Correct Answer
A. (x+y=5)
Step 1
Concept
Multiplying (x+y=5) by (3) gives (3x+3y=15). It cancels (y) with (-3y) by addition.
Step 2
Why this answer is correct
The correct answer is A. (x+y=5). Multiplying (x+y=5) by (3) gives (3x+3y=15). It cancels (y) with (-3y) by addition.
Step 3
Exam Tip
(x+y=5) को (3) से गुणा करने पर (3x+3y=15) मिलता है। यह (-3y) के साथ जुड़कर (y) हटाता है।
Login to save your score, XP, coins and progress. Login
(3x+4y=17) के साथ (5x-2y=1) में (y) हटाने के लिए दूसरे समीकरण को किस संख्या से गुणा करना चाहिए?
By what number should (5x-2y=1) be multiplied to eliminate (y) with (3x+4y=17)?
#linear-equations
#elimination
#multiplier
#medium
#class-10
A (1)
B (2)
C (3)
D (4)
Explanation opens after your attempt
Step 1
Concept
Multiplying the second equation by (2) gives (-4y). It cancels with (4y) by addition.
Step 2
Why this answer is correct
The correct answer is B. (2). Multiplying the second equation by (2) gives (-4y). It cancels with (4y) by addition.
Step 3
Exam Tip
दूसरे समीकरण को (2) से गुणा करने पर (-4y) मिलेगा। यह (4y) के साथ जुड़कर हट जाएगा।
Login to save your score, XP, coins and progress. Login
किस समीकरण को (3) से गुणा करके (3x+2y=16) के साथ (x) हटाया जा सकता है?
Which equation can be multiplied by (3) to eliminate (x) with (3x+2y=16)?
#linear equations
#elimination
#multiplier
#medium
#class 10
A (x+y=5)
B (-x+y=2)
C (2x-y=4)
D (-2x+y=1)
Explanation opens after your attempt
Correct Answer
B. (-x+y=2)
Step 1
Concept
Multiplying (-x+y=2) by (3) gives (-3x+3y=6). This cancels (3x) by addition.
Step 2
Why this answer is correct
The correct answer is B. (-x+y=2). Multiplying (-x+y=2) by (3) gives (-3x+3y=6). This cancels (3x) by addition.
Step 3
Exam Tip
(-x+y=2) को (3) से गुणा करने पर (-3x+3y=6) बनता है। यह (3x) को जोड़कर हटा देगा।
Login to save your score, XP, coins and progress. Login
किस संख्या से (2x+3y=13) को गुणा करना चाहिए ताकि (4x-5y=1) के साथ (x) हट सके?
By what number should (2x+3y=13) be multiplied so that (x) can be eliminated with (4x-5y=1)?
#linear equations
#elimination
#multiplier
#medium
#class 10
A (2)
B (-2)
C (3)
D (-3)
Explanation opens after your attempt
Step 1
Concept
Multiplying (2x) by (-2) gives (-4x). It cancels with (4x) when added.
Step 2
Why this answer is correct
The correct answer is B. (-2). Multiplying (2x) by (-2) gives (-4x). It cancels with (4x) when added.
Step 3
Exam Tip
(2x) को (-2) से गुणा करने पर (-4x) बनेगा। यह (4x) के साथ जुड़कर हट जाएगा।
Login to save your score, XP, coins and progress. Login
यदि \(x=2^2\times3^3\times5\) है, तो (x) को पूर्ण वर्ग बनाने के लिए सबसे छोटी गुणक संख्या कौन सी है?
If \(x=2^2\times3^3\times5\), what is the smallest multiplier that makes (x) a perfect square?
#real numbers
#perfect square
#multiplier
#prime factorisation
A \(3\times5\)
B \(2\times3\)
C \(2\times5\)
D \(3^2\times5\)
Explanation opens after your attempt
Correct Answer
A. \(3\times5\)
Step 1
Concept
A perfect square needs all exponents to be even.
Step 2
Why this answer is correct
\(2^2\) is already fine, \(3^3\) needs one (3), and \(5^1\) needs one (5).
Step 3
Exam Tip
Make only the odd exponents even. चरण 1: पूर्ण वर्ग में सभी घातें सम होनी चाहिए। चरण 2: \(2^2\) ठीक है, \(3^3\) को \(3^4\) बनाने के लिए (3) और \(5^1\) को \(5^2\) बनाने के लिए (5) चाहिए। चरण 3: केवल विषम घातों को एक-एक बढ़ाकर सम बनाएं।
Login to save your score, XP, coins and progress. Login