बहुपद (8x-17) किस प्रकार का बहुपद है?
What type of polynomial is (8x-17)?
#polynomial
#type
#linear
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A नियतांक बहुपद / Constant polynomial
B रेखीय बहुपद / Linear polynomial
C द्विघात बहुपद / Quadratic polynomial
D त्रिघात बहुपद / Cubic polynomial
Explanation opens after your attempt
Correct Answer
B. रेखीय बहुपद / Linear polynomial
Step 1
Concept
The degree of (8x-17) is (1). A polynomial of degree (1) is called linear.
Step 2
Why this answer is correct
The correct answer is B. रेखीय बहुपद / Linear polynomial. The degree of (8x-17) is (1). A polynomial of degree (1) is called linear.
Step 3
Exam Tip
(8x-17) की डिग्री (1) है। डिग्री (1) वाला बहुपद रेखीय कहलाता है।
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रेखीय बहुपद की पहचान किससे होती है?
How is a linear polynomial identified?
#polynomial
#linear
#degree
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A चर की घात (0) से / By power (0) of variable
B चर की घात (2) से / By power (2) of variable
C सबसे बड़ी घात (1) से / By highest power (1)
D तीन पदों से / By three terms
Explanation opens after your attempt
Correct Answer
C. सबसे बड़ी घात (1) से / By highest power (1)
Step 1
Concept
In a linear polynomial, the highest power of the variable is (1). In a question, first check the highest power.
Step 2
Why this answer is correct
The correct answer is C. सबसे बड़ी घात (1) से / By highest power (1). In a linear polynomial, the highest power of the variable is (1). In a question, first check the highest power.
Step 3
Exam Tip
रेखीय बहुपद में चर की सबसे बड़ी घात (1) होती है। प्रश्न में पहले सबसे बड़ी घात देखें।
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(13u+9) में चर (u) की घात क्या है?
What is the power of (u) in (13u+9)?
#polynomial
#power
#linear
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A (13)
B (9)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
In (13u+9), the power of (u) is (1). Therefore it is linear in (u).
Step 2
Why this answer is correct
The correct answer is D. (1). In (13u+9), the power of (u) is (1). Therefore it is linear in (u).
Step 3
Exam Tip
(13u+9) में (u) की घात (1) है। इसलिए यह (u) में रेखीय बहुपद है।
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रेखीय बहुपद का सामान्य रूप क्या है?
What is the general form of a linear polynomial?
#polynomial
#general_form
#linear
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A (ax+b) जहाँ \(a\neq0\) / (ax+b) where \(a\neq0\)
B \(ax^2+bx+c\)
C (b)
D \(ax^3+b\)
Explanation opens after your attempt
Correct Answer
A. (ax+b) जहाँ \(a\neq0\) / (ax+b) where \(a\neq0\)
Step 1
Concept
The general form of a linear polynomial is (ax+b) where \(a\neq0\). If (a=0), the degree will not remain (1).
Step 2
Why this answer is correct
The correct answer is A. (ax+b) जहाँ \(a\neq0\) / (ax+b) where \(a\neq0\). The general form of a linear polynomial is (ax+b) where \(a\neq0\). If (a=0), the degree will not remain (1).
Step 3
Exam Tip
रेखीय बहुपद का सामान्य रूप (ax+b) होता है जहाँ \(a\neq0\) है। (a=0) होने पर डिग्री (1) नहीं रहेगी।
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यदि (p(x)=12x+1), तो (p(x)) की डिग्री क्या है?
If (p(x)=12x+1), what is the degree of (p(x))?
#polynomial
#degree
#linear
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A (0)
B (1)
C (12)
D (2)
Explanation opens after your attempt
Step 1
Concept
The highest power of (x) is (1). Therefore the degree of (p(x)) is (1).
Step 2
Why this answer is correct
The correct answer is B. (1). The highest power of (x) is (1). Therefore the degree of (p(x)) is (1).
Step 3
Exam Tip
(x) की सबसे बड़ी घात (1) है। इसलिए (p(x)) की डिग्री (1) है।
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बहुपद (25-9x) में (x) का गुणांक क्या है?
What is the coefficient of (x) in (25-9x)?
#polynomial
#coefficient
#linear
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A (25)
B (9)
C (-9)
D (1)
Explanation opens after your attempt
Step 1
Concept
In (25-9x), the term containing (x) is (-9x). So the coefficient of (x) is (-9).
Step 2
Why this answer is correct
The correct answer is C. (-9). In (25-9x), the term containing (x) is (-9x). So the coefficient of (x) is (-9).
Step 3
Exam Tip
(25-9x) में (x) वाला पद (-9x) है। इसलिए (x) का गुणांक (-9) है।
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बहुपद (x+18) का नियतांक पद क्या है?
What is the constant term of (x+18)?
#polynomial
#constant_term
#linear
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A (1)
B (x)
C (0)
D (18)
Explanation opens after your attempt
Step 1
Concept
The constant term has no variable. In (x+18), the constant term is (18).
Step 2
Why this answer is correct
The correct answer is D. (18). The constant term has no variable. In (x+18), the constant term is (18).
Step 3
Exam Tip
नियतांक पद में चर नहीं होता। (x+18) में नियतांक पद (18) है।
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(7x+4) में \(x^2\) का गुणांक क्या है?
What is the coefficient of \(x^2\) in (7x+4)?
#polynomial
#missing_term
#linear
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A (0)
B (7)
C (4)
D (1)
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Step 1
Concept
The \(x^2\) term is not present in (7x+4). The coefficient of a missing term is taken as (0).
Step 2
Why this answer is correct
The correct answer is A. (0). The \(x^2\) term is not present in (7x+4). The coefficient of a missing term is taken as (0).
Step 3
Exam Tip
(7x+4) में \(x^2\) पद मौजूद नहीं है। अनुपस्थित पद का गुणांक (0) माना जाता है।
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रेखीय बहुपद (-6x+11) का अग्र गुणांक क्या है?
What is the leading coefficient of the linear polynomial (-6x+11)?
#polynomial
#leading_coefficient
#linear
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A (11)
B (-6)
C (6)
D (0)
Explanation opens after your attempt
Step 1
Concept
The leading term is (-6x). Therefore the leading coefficient is (-6).
Step 2
Why this answer is correct
The correct answer is B. (-6). The leading term is (-6x). Therefore the leading coefficient is (-6).
Step 3
Exam Tip
अग्र पद (-6x) है। इसलिए अग्र गुणांक (-6) है।
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यदि (p(x)=x-20), तो (p(x)) किस रूप में लिखा जा सकता है?
If (p(x)=x-20), in which form can (p(x)) be written?
#polynomial
#form
#linear
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A (ax+b)
B \(ax^2+b\)
C \(ax^3+b\)
D (a)
Explanation opens after your attempt
Step 1
Concept
(x-20) can be written as (1x+(-20)). It is a linear polynomial of the form (ax+b).
Step 2
Why this answer is correct
The correct answer is A. (ax+b). (x-20) can be written as (1x+(-20)). It is a linear polynomial of the form (ax+b).
Step 3
Exam Tip
(x-20) को (1x+(-20)) लिखा जा सकता है। यह (ax+b) रूप का रेखीय बहुपद है।
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(0x+12) किस प्रकार का बहुपद है?
What type of polynomial is (0x+12)?
#polynomial
#constant
#not_linear
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A रेखीय बहुपद / Linear polynomial
B नियतांक बहुपद / Constant polynomial
C द्विघात बहुपद / Quadratic polynomial
D त्रिघात बहुपद / Cubic polynomial
Explanation opens after your attempt
Correct Answer
B. नियतांक बहुपद / Constant polynomial
Step 1
Concept
(0x+12) simplifies to (12). It is a non-zero constant polynomial.
Step 2
Why this answer is correct
The correct answer is B. नियतांक बहुपद / Constant polynomial. (0x+12) simplifies to (12). It is a non-zero constant polynomial.
Step 3
Exam Tip
(0x+12) सरल होकर (12) बनता है। यह अशून्य नियतांक बहुपद है।
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किस मान पर ((m-8 )x+6) रेखीय बहुपद नहीं रहेगा?
For which value will ((m-8 )x+6) not remain a linear polynomial?
#polynomial
#parameter
#not_linear
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A (m=0)
B (m=7)
C (m=8)
D (m=-8)
Explanation opens after your attempt
Step 1
Concept
To be linear, the coefficient of (x) must not be zero. At (m=8), (m-8 =0).
Step 2
Why this answer is correct
The correct answer is C. (m=8). To be linear, the coefficient of (x) must not be zero. At (m=8), (m-8 =0).
Step 3
Exam Tip
रेखीय होने के लिए (x) का गुणांक शून्य नहीं होना चाहिए। (m=8) पर (m-8 =0) हो जाता है।
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किस मान पर ((k+9)x-1) रेखीय बहुपद होगा?
For which value will ((k+9)x-1) be a linear polynomial?
#polynomial
#parameter
#linear
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A (k=-9)
B (k=-10)
C (k) कोई भी हो / Any (k)
D कोई मान नहीं / No value
Explanation opens after your attempt
Correct Answer
B. (k=-10)
Step 1
Concept
At (k=-10), the coefficient of (x) is (-1), which is non-zero. Therefore the polynomial is linear.
Step 2
Why this answer is correct
The correct answer is B. (k=-10). At (k=-10), the coefficient of (x) is (-1), which is non-zero. Therefore the polynomial is linear.
Step 3
Exam Tip
(k=-10) पर (x) का गुणांक (-1) है जो शून्य नहीं है। इसलिए बहुपद रेखीय है।
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रेखीय बहुपद (5x-20) का शून्यक क्या है?
What is the zero of the linear polynomial (5x-20)?
#polynomial
#zero
#linear
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A (4)
B (-4)
C (5)
D (20)
Explanation opens after your attempt
Step 1
Concept
From (5x-20=0), we get (x=4). To find a zero, set the polynomial equal to (0).
Step 2
Why this answer is correct
The correct answer is A. (4). From (5x-20=0), we get (x=4). To find a zero, set the polynomial equal to (0).
Step 3
Exam Tip
(5x-20=0) से (x=4) मिलता है। शून्यक निकालने के लिए बहुपद को (0) रखें।
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रेखीय बहुपद (x+21) का शून्यक क्या है?
What is the zero of the linear polynomial (x+21)?
#polynomial
#zero
#linear
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A (21)
B (-21)
C (0)
D (1)
Explanation opens after your attempt
Step 1
Concept
From (x+21=0), we get (x=-21). Pay attention to the sign.
Step 2
Why this answer is correct
The correct answer is B. (-21). From (x+21=0), we get (x=-21). Pay attention to the sign.
Step 3
Exam Tip
(x+21=0) से (x=-21) मिलता है। चिन्ह पर ध्यान रखना चाहिए।
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यदि (p(x)=4x+7), तो (p(3)) का मान क्या है?
If (p(x)=4x+7), what is the value of (p(3))?
#polynomial
#value
#linear
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A (10)
B (12)
C (19)
D (21)
Explanation opens after your attempt
Step 1
Concept
(p(3)=4(3)+7=19). To find the value, substitute the given number for (x).
Step 2
Why this answer is correct
The correct answer is C. (19). (p(3)=4(3)+7=19). To find the value, substitute the given number for (x).
Step 3
Exam Tip
(p(3)=4(3)+7=19) है। मान निकालने के लिए (x) की जगह दी गई संख्या रखें।
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यदि (p(x)=8x-13), तो (p(0)) क्या होगा?
If (p(x)=8x-13), what is (p(0))?
#polynomial
#value_at_zero
#linear
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A (8)
B (0)
C (-13)
D (13)
Explanation opens after your attempt
Step 1
Concept
(p(0)=8(0)-13=-13). When (x=0), the constant term remains.
Step 2
Why this answer is correct
The correct answer is C. (-13). (p(0)=8(0)-13=-13). When (x=0), the constant term remains.
Step 3
Exam Tip
(p(0)=8(0)-13=-13) है। (x=0) रखने पर नियतांक पद बचता है।
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रेखीय बहुपद (18-6x) का शून्यक क्या है?
What is the zero of the linear polynomial (18-6x)?
#polynomial
#zero
#linear
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A (6)
B (3)
C (18)
D (-3)
Explanation opens after your attempt
Step 1
Concept
From (18-6x=0), we get (x=3). A linear polynomial has one zero.
Step 2
Why this answer is correct
The correct answer is B. (3). From (18-6x=0), we get (x=3). A linear polynomial has one zero.
Step 3
Exam Tip
(18-6x=0) से (x=3) मिलता है। रेखीय बहुपद का एक शून्यक होता है।
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(9r-14) किस चर में रेखीय बहुपद है?
In which variable is (9r-14) a linear polynomial?
#polynomial
#variable
#linear
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A (x)
B (y)
C (r)
D (z)
Explanation opens after your attempt
Step 1
Concept
The variable in (9r-14) is (r), and its power is (1). Therefore it is linear in (r).
Step 2
Why this answer is correct
The correct answer is C. (r). The variable in (9r-14) is (r), and its power is (1). Therefore it is linear in (r).
Step 3
Exam Tip
(9r-14) में चर (r) है और उसकी घात (1) है। इसलिए यह (r) में रेखीय है।
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रेखीय बहुपद (ax+b) में (a) के लिए कौन सी शर्त सही है?
Which condition is correct for (a) in the linear polynomial (ax+b)?
#polynomial
#condition
#linear
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A (a=0)
B \(a\neq0\)
C (a=b)
D (b=0) ही / (b=0) only
Explanation opens after your attempt
Correct Answer
B. \(a\neq0\)
Step 1
Concept
For being linear, the coefficient (a) of (x) must not be zero. Then the degree remains (1).
Step 2
Why this answer is correct
The correct answer is B. \(a\neq0\). For being linear, the coefficient (a) of (x) must not be zero. Then the degree remains (1).
Step 3
Exam Tip
रेखीय होने के लिए (x) का गुणांक (a) शून्य नहीं होना चाहिए। तभी डिग्री (1) रहती है।
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यदि (p(x)=3x+6) और (q(x)=2x+5), तो (p(x)+q(x)) क्या है?
If (p(x)=3x+6) and (q(x)=2x+5), what is (p(x)+q(x))?
#polynomial
#sum
#linear
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A (5x+11)
B (6x+11)
C (5x+1)
D (x+11)
Explanation opens after your attempt
Correct Answer
A. (5x+11)
Step 1
Concept
Adding like terms gives (3x+2x=5x) and (6+5=11). Therefore the sum is (5x+11).
Step 2
Why this answer is correct
The correct answer is A. (5x+11). Adding like terms gives (3x+2x=5x) and (6+5=11). Therefore the sum is (5x+11).
Step 3
Exam Tip
समान पद जोड़ने पर (3x+2x=5x) और (6+5=11) मिलता है। इसलिए योग (5x+11) है।
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यदि (p(x)=9x+8) और (q(x)=4x+3), तो (p(x)-q(x)) क्या है?
If (p(x)=9x+8) and (q(x)=4x+3), what is (p(x)-q(x))?
#polynomial
#difference
#linear
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A (13x+11)
B (5x+5)
C (5x+11)
D (13x+5)
Explanation opens after your attempt
Step 1
Concept
On subtracting, (9x-4x=5x) and (8-3=5). Therefore the difference is (5x+5).
Step 2
Why this answer is correct
The correct answer is B. (5x+5). On subtracting, (9x-4x=5x) and (8-3=5). Therefore the difference is (5x+5).
Step 3
Exam Tip
घटाने पर (9x-4x=5x) और (8-3=5) मिलता है। इसलिए अंतर (5x+5) है।
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(4(3x-2)) को सरल करने पर कौन सा रेखीय बहुपद मिलेगा?
Which linear polynomial is obtained by simplifying (4(3x-2))?
#polynomial
#simplification
#linear
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A (12x-8)
B (7x-8)
C (12x+8)
D (3x-8)
Explanation opens after your attempt
Correct Answer
A. (12x-8)
Step 1
Concept
(4(3x-2)=12x-8). While multiplying, multiply both terms.
Step 2
Why this answer is correct
The correct answer is A. (12x-8). (4(3x-2)=12x-8). While multiplying, multiply both terms.
Step 3
Exam Tip
(4(3x-2)=12x-8) होता है। गुणा करते समय दोनों पदों से गुणा करें।
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(-4(x+3)) को सरल करने पर क्या मिलेगा?
What is obtained after simplifying (-4(x+3))?
#polynomial
#distribution
#linear
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A (4x+12)
B (-4x+12)
C (-4x-12)
D (x-12)
Explanation opens after your attempt
Correct Answer
C. (-4x-12)
Step 1
Concept
Multiply (-4) with both terms. Therefore (-4(x+3)=-4x-12).
Step 2
Why this answer is correct
The correct answer is C. (-4x-12). Multiply (-4) with both terms. Therefore (-4(x+3)=-4x-12).
Step 3
Exam Tip
(-4) को दोनों पदों से गुणा करें। इसलिए (-4(x+3)=-4x-12) है।
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बहुपद (23x) का नियतांक पद क्या है?
What is the constant term of the polynomial (23x)?
#polynomial
#constant_term
#linear
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A (23)
B (1)
C (0)
D (x)
Explanation opens after your attempt
Step 1
Concept
There is no term without a variable in (23x). Therefore the constant term is (0).
Step 2
Why this answer is correct
The correct answer is C. (0). There is no term without a variable in (23x). Therefore the constant term is (0).
Step 3
Exam Tip
(23x) में बिना चर वाला कोई पद नहीं है। इसलिए नियतांक पद (0) है।
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यदि (p(x)=-5x+25), तो (p(5)) क्या है?
If (p(x)=-5x+25), what is (p(5))?
#polynomial
#value
#zero
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A (0)
B (5)
C (25)
D (-25)
Explanation opens after your attempt
Step 1
Concept
(p(5)=-5(5)+25=0). Therefore (5) is a zero of this polynomial.
Step 2
Why this answer is correct
The correct answer is A. (0). (p(5)=-5(5)+25=0). Therefore (5) is a zero of this polynomial.
Step 3
Exam Tip
(p(5)=-5(5)+25=0) है। इसलिए (5) इस बहुपद का शून्यक है।
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(20-5x) का शून्यक क्या है?
What is the zero of (20-5x)?
#polynomial
#zero
#linear
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A (0)
B (4)
C (5)
D (-4)
Explanation opens after your attempt
Step 1
Concept
From (20-5x=0), we get (x=4). For a zero, set the polynomial equal to (0).
Step 2
Why this answer is correct
The correct answer is B. (4). From (20-5x=0), we get (x=4). For a zero, set the polynomial equal to (0).
Step 3
Exam Tip
(20-5x=0) से (x=4) मिलता है। शून्यक के लिए बहुपद को (0) रखें।
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बहुपद (30-11v) में चर कौन सा है?
Which is the variable in the polynomial (30-11v)?
#polynomial
#variable
#linear
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A (30)
B (11)
C (v)
D (-11)
Explanation opens after your attempt
Step 1
Concept
In (30-11v), the changing symbol is (v). Therefore the variable is (v).
Step 2
Why this answer is correct
The correct answer is C. (v). In (30-11v), the changing symbol is (v). Therefore the variable is (v).
Step 3
Exam Tip
(30-11v) में बदलने वाला चिन्ह (v) है। इसलिए चर (v) है।
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यदि (p(x)=ax+b) रेखीय है, तो (x) का गुणांक कैसा होना चाहिए?
If (p(x)=ax+b) is linear, how should the coefficient of (x) be?
#polynomial
#condition
#linear
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A शून्य होना चाहिए / It should be zero
B शून्य नहीं होना चाहिए / It should not be zero
C हमेशा (1) होना चाहिए / It should always be (1)
D हमेशा (b) के बराबर होना चाहिए / It should always equal (b)
Explanation opens after your attempt
Correct Answer
B. शून्य नहीं होना चाहिए / It should not be zero
Step 1
Concept
In a linear polynomial, the coefficient of (x) must not be zero. Then the degree of the polynomial remains (1).
Step 2
Why this answer is correct
The correct answer is B. शून्य नहीं होना चाहिए / It should not be zero. In a linear polynomial, the coefficient of (x) must not be zero. Then the degree of the polynomial remains (1).
Step 3
Exam Tip
रेखीय बहुपद में (x) का गुणांक शून्य नहीं होना चाहिए। तभी बहुपद की डिग्री (1) रहती है।
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किस विकल्प में रेखीय बहुपद का नियतांक पद (-8) है?
Which option has a linear polynomial with constant term (-8)?
#polynomial
#constant_term
#linear
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A (3x-8)
B (8x-3)
C (3x+8)
D (-8x+3)
Explanation opens after your attempt
Step 1
Concept
In (3x-8), the term without a variable is (-8). So its constant term is (-8).
Step 2
Why this answer is correct
The correct answer is A. (3x-8). In (3x-8), the term without a variable is (-8). So its constant term is (-8).
Step 3
Exam Tip
(3x-8) में बिना चर वाला पद (-8) है। इसलिए इसका नियतांक पद (-8) है।
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किस विकल्प में रेखीय बहुपद का शून्यक (8) है?
Which option has zero (8) for a linear polynomial?
#polynomial
#zero
#linear
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A (x+8)
B (x-8)
C (8x+1)
D (x+1)
Explanation opens after your attempt
Step 1
Concept
From (x-8=0), we get (x=8). Therefore its zero is (8).
Step 2
Why this answer is correct
The correct answer is B. (x-8). From (x-8=0), we get (x=8). Therefore its zero is (8).
Step 3
Exam Tip
(x-8=0) से (x=8) मिलता है। इसलिए इसका शून्यक (8) है।
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किस विकल्प में रेखीय बहुपद का शून्यक (-10) है?
Which option has zero (-10) for a linear polynomial?
#polynomial
#zero
#linear
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A (x+10)
B (x-10)
C (10x-1)
D (x+1)
Explanation opens after your attempt
Step 1
Concept
From (x+10=0), we get (x=-10). Therefore the zero is (-10).
Step 2
Why this answer is correct
The correct answer is A. (x+10). From (x+10=0), we get (x=-10). Therefore the zero is (-10).
Step 3
Exam Tip
(x+10=0) से (x=-10) मिलता है। इसलिए शून्यक (-10) है।
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(6x+7x-3) को सरल करने पर कौन सा बहुपद मिलेगा?
Which polynomial is obtained by simplifying (6x+7x-3)?
#polynomial
#simplification
#linear
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A (13x-3)
B (42x-3)
C (13x+3)
D (x-3)
Explanation opens after your attempt
Correct Answer
A. (13x-3)
Step 1
Concept
Adding like terms gives (6x+7x=13x). Therefore the simplified form is (13x-3).
Step 2
Why this answer is correct
The correct answer is A. (13x-3). Adding like terms gives (6x+7x=13x). Therefore the simplified form is (13x-3).
Step 3
Exam Tip
समान पद जोड़ने पर (6x+7x=13x) है। इसलिए सरल रूप (13x-3) है।
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(17x-8x+5) का सरल रूप क्या है?
What is the simplified form of (17x-8x+5)?
#polynomial
#like_terms
#linear
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A (25x+5)
B (9x+5)
C (9x-5)
D (17x-3)
Explanation opens after your attempt
Step 1
Concept
(17x-8x=9x). Therefore the simplified form is (9x+5).
Step 2
Why this answer is correct
The correct answer is B. (9x+5). (17x-8x=9x). Therefore the simplified form is (9x+5).
Step 3
Exam Tip
(17x-8x=9x) होता है। इसलिए सरल रूप (9x+5) है।
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यदि (p(x)=5x+6), तो (p(4)) क्या होगा?
If (p(x)=5x+6), what is (p(4))?
#polynomial
#value
#linear
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A (11)
B (20)
C (26)
D (30)
Explanation opens after your attempt
Step 1
Concept
(p(4)=5(4)+6=26). Substitute the given value for (x).
Step 2
Why this answer is correct
The correct answer is C. (26). (p(4)=5(4)+6=26). Substitute the given value for (x).
Step 3
Exam Tip
(p(4)=5(4)+6=26) है। दिए गए मान को (x) की जगह रखें।
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यदि (p(x)=6x-7), तो (p(5)) क्या होगा?
If (p(x)=6x-7), what is (p(5))?
#polynomial
#value
#linear
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A (23)
B (30)
C (13)
D (5)
Explanation opens after your attempt
Step 1
Concept
(p(5)=6(5)-7=23). In calculation, multiply first and then subtract.
Step 2
Why this answer is correct
The correct answer is A. (23). (p(5)=6(5)-7=23). In calculation, multiply first and then subtract.
Step 3
Exam Tip
(p(5)=6(5)-7=23) है। गणना में पहले गुणा करें फिर घटाएं।
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किस विकल्प में (p(0)=4) है यदि (p(x)) रेखीय बहुपद है?
Which option has (p(0)=4) if (p(x)) is a linear polynomial?
#polynomial
#value_at_zero
#linear
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A (p(x)=7x+4)
B (p(x)=7x-4)
C (p(x)=4x+7)
D (p(x)=x-7)
Explanation opens after your attempt
Correct Answer
A. (p(x)=7x+4)
Step 1
Concept
(p(0)) equals the constant term. In (7x+4), the constant term is (4).
Step 2
Why this answer is correct
The correct answer is A. (p(x)=7x+4). (p(0)) equals the constant term. In (7x+4), the constant term is (4).
Step 3
Exam Tip
(p(0)) नियतांक पद के बराबर होता है। (7x+4) में नियतांक पद (4) है।
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यदि (p(x)=0\cdot x-6), तो क्या यह रेखीय बहुपद है?
If (p(x)=0\cdot x-6), is it a linear polynomial?
#polynomial
#constant
#not_linear
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A हाँ क्योंकि (x) लिखा है / Yes because (x) is written
B हाँ क्योंकि डिग्री (1) है / Yes because degree is (1)
C नहीं यह नियतांक बहुपद है / No it is a constant polynomial
D हाँ क्योंकि नियतांक (-6) है / Yes because constant is (-6)
Explanation opens after your attempt
Correct Answer
C. नहीं यह नियतांक बहुपद है / No it is a constant polynomial
Step 1
Concept
\(0\cdot x-6\) simplifies to (-6). It is a constant polynomial, so it is not linear.
Step 2
Why this answer is correct
The correct answer is C. नहीं यह नियतांक बहुपद है / No it is a constant polynomial. \(0\cdot x-6\) simplifies to (-6). It is a constant polynomial, so it is not linear.
Step 3
Exam Tip
\(0\cdot x-6\) सरल होकर (-6) बनता है। यह नियतांक बहुपद है इसलिए रेखीय नहीं है।
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यदि (p(x)=8x-9), तो (p(2)) क्या होगा?
If (p(x)=8x-9), what is (p(2))?
#polynomial
#value
#linear
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A (7)
B (16)
C (9)
D (2)
Explanation opens after your attempt
Step 1
Concept
(p(2)=8(2)-9=7). To find the value, substitute the given number for (x).
Step 2
Why this answer is correct
The correct answer is A. (7). (p(2)=8(2)-9=7). To find the value, substitute the given number for (x).
Step 3
Exam Tip
(p(2)=8(2)-9=7) है। मान निकालते समय (x) की जगह दी गई संख्या रखें।
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किस विकल्प में (x) का गुणांक (-5) और नियतांक पद (12) है?
Which option has coefficient of (x) equal to (-5) and constant term (12)?
#polynomial
#coefficient
#constant_term
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A (5x+12)
B (-5x+12)
C (-5x-12)
D (12x-5)
Explanation opens after your attempt
Correct Answer
B. (-5x+12)
Step 1
Concept
In (-5x+12), the coefficient of (x) is (-5) and the constant term is (12). Identify both parts separately in a linear polynomial.
Step 2
Why this answer is correct
The correct answer is B. (-5x+12). In (-5x+12), the coefficient of (x) is (-5) and the constant term is (12). Identify both parts separately in a linear polynomial.
Step 3
Exam Tip
(-5x+12) में (x) का गुणांक (-5) और नियतांक पद (12) है। रेखीय बहुपद में दोनों भाग अलग पहचानें।
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रेखीय बहुपद (9x-27) का शून्यक क्या है?
What is the zero of the linear polynomial (9x-27)?
#polynomial
#zero
#linear
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A (9)
B (-3)
C (3)
D (27)
Explanation opens after your attempt
Step 1
Concept
From (9x-27=0), we get (x=3). To find the zero, equate the polynomial to (0).
Step 2
Why this answer is correct
The correct answer is C. (3). From (9x-27=0), we get (x=3). To find the zero, equate the polynomial to (0).
Step 3
Exam Tip
(9x-27=0) से (x=3) मिलता है। शून्यक निकालने के लिए बहुपद को (0) के बराबर रखें।
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किस मान पर ((r+11)x+4) रेखीय बहुपद नहीं रहेगा?
For which value will ((r+11)x+4) not remain a linear polynomial?
#polynomial
#parameter
#not_linear
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A (r=11)
B (r=0)
C (r=-11)
D (r=4)
Explanation opens after your attempt
Correct Answer
C. (r=-11)
Step 1
Concept
To be linear, the coefficient of (x) must not be zero. At (r=-11), (r+11=0).
Step 2
Why this answer is correct
The correct answer is C. (r=-11). To be linear, the coefficient of (x) must not be zero. At (r=-11), (r+11=0).
Step 3
Exam Tip
रेखीय होने के लिए (x) का गुणांक शून्य नहीं होना चाहिए। (r=-11) पर (r+11=0) हो जाता है।
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यदि (p(x)=4x-9) और (q(x)=3x+2), तो (p(x)+q(x)) क्या है?
If (p(x)=4x-9) and (q(x)=3x+2), what is (p(x)+q(x))?
#polynomial
#sum
#linear
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A (7x-7)
B (x-11)
C (7x+11)
D (12x-18)
Explanation opens after your attempt
Step 1
Concept
Adding like terms gives (4x+3x=7x) and (-9+2=-7). Therefore the sum is (7x-7).
Step 2
Why this answer is correct
The correct answer is A. (7x-7). Adding like terms gives (4x+3x=7x) and (-9+2=-7). Therefore the sum is (7x-7).
Step 3
Exam Tip
समान पद जोड़ने पर (4x+3x=7x) और (-9+2=-7) मिलता है। इसलिए योग (7x-7) है।
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(6(2x-1)-5x) को सरल करने पर क्या मिलेगा?
What is obtained after simplifying (6(2x-1)-5x)?
#polynomial
#simplification
#linear
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A (12x-6)
B (7x-6)
C (17x-6)
D (7x+6)
Explanation opens after your attempt
Step 1
Concept
First (6(2x-1)=12x-6), then subtract (5x). The simplified form is (7x-6).
Step 2
Why this answer is correct
The correct answer is B. (7x-6). First (6(2x-1)=12x-6), then subtract (5x). The simplified form is (7x-6).
Step 3
Exam Tip
पहले (6(2x-1)=12x-6) करें फिर (5x) घटाएं। सरल रूप (7x-6) है।
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यदि (p(x)=11-3x), तो (p(1)) क्या होगा?
If (p(x)=11-3x), what is (p(1))?
#polynomial
#value
#linear
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A (8)
B (11)
C (3)
D (14)
Explanation opens after your attempt
Step 1
Concept
(p(1)=11-3(1)=8). Substitute the given value for the variable to get the value.
Step 2
Why this answer is correct
The correct answer is A. (8). (p(1)=11-3(1)=8). Substitute the given value for the variable to get the value.
Step 3
Exam Tip
(p(1)=11-3(1)=8) है। चर की जगह दिया गया मान रखने से मान मिलता है।
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किस विकल्प में रेखीय बहुपद का अग्र गुणांक (6) है और नियतांक पद (0) है?
Which option has a linear polynomial with leading coefficient (6) and constant term (0)?
#polynomial
#leading_coefficient
#constant_zero
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A (6x)
B (x+6)
C (6)
D (6x+1)
Explanation opens after your attempt
Step 1
Concept
In (6x), the coefficient of (x) is (6) and the constant term is (0). So it is the correct linear polynomial.
Step 2
Why this answer is correct
The correct answer is A. (6x). In (6x), the coefficient of (x) is (6) and the constant term is (0). So it is the correct linear polynomial.
Step 3
Exam Tip
(6x) में (x) का गुणांक (6) और नियतांक पद (0) है। इसलिए यह सही रेखीय बहुपद है।
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यदि (p(x)=2x+7) और (q(x)=5x-3), तो (q(x)-p(x)) क्या है?
If (p(x)=2x+7) and (q(x)=5x-3), what is (q(x)-p(x))?
#polynomial
#difference
#linear
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A (7x+4)
B (3x-10)
C (3x+10)
D (7x-10)
Explanation opens after your attempt
Correct Answer
B. (3x-10)
Step 1
Concept
On subtracting, (5x-2x=3x) and (-3-7=-10). Therefore (q(x)-p(x)=3x-10).
Step 2
Why this answer is correct
The correct answer is B. (3x-10). On subtracting, (5x-2x=3x) and (-3-7=-10). Therefore (q(x)-p(x)=3x-10).
Step 3
Exam Tip
घटाने पर (5x-2x=3x) और (-3-7=-10) मिलता है। इसलिए (q(x)-p(x)=3x-10) है।
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किस मान पर ((h-1)x+10) रेखीय बहुपद होगा?
For which value will ((h-1)x+10) be a linear polynomial?
#polynomial
#parameter
#linear
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A (h=1)
B (h=0)
C (h) कोई भी हो / Any (h)
D कोई मान नहीं / No value
Explanation opens after your attempt
Step 1
Concept
At (h=0), the coefficient of (x) is (-1), which is non-zero. Therefore the polynomial is linear.
Step 2
Why this answer is correct
The correct answer is B. (h=0). At (h=0), the coefficient of (x) is (-1), which is non-zero. Therefore the polynomial is linear.
Step 3
Exam Tip
(h=0) पर (x) का गुणांक (-1) है जो शून्य नहीं है। इसलिए बहुपद रेखीय है।
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यदि (p(x)=0\cdot x+14), तो (p(x)) की डिग्री क्या है?
If (p(x)=0\cdot x+14), what is the degree of (p(x))?
#polynomial
#constant_degree
#not_linear
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A (1)
B (14)
C (0)
D परिभाषित नहीं / Not defined
Explanation opens after your attempt
Step 1
Concept
\(0\cdot x+14\) simplifies to (14). A non-zero constant polynomial has degree (0).
Step 2
Why this answer is correct
The correct answer is C. (0). \(0\cdot x+14\) simplifies to (14). A non-zero constant polynomial has degree (0).
Step 3
Exam Tip
\(0\cdot x+14\) सरल होकर (14) बनता है। अशून्य नियतांक बहुपद की डिग्री (0) होती है।
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रेखीय बहुपद (2x+10) का शून्यक क्या है?
What is the zero of the linear polynomial (2x+10)?
#polynomial
#zero
#linear
50 50-50 2 wrong hide
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A (5)
B (-5)
C (2)
D (-10)
Explanation opens after your attempt
Step 1
Concept
From (2x+10=0), we get (x=-5). Pay attention to the sign while finding the zero.
Step 2
Why this answer is correct
The correct answer is B. (-5). From (2x+10=0), we get (x=-5). Pay attention to the sign while finding the zero.
Step 3
Exam Tip
(2x+10=0) से (x=-5) मिलता है। शून्यक निकालते समय चिन्ह का ध्यान रखें।
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