What is the zero of the linear polynomial (9x-27)?
Answer and explanation
Correct answer: 3
To find the zero, equate the polynomial to 0: \(9x-27=0\). Thus, \(9x=27\), so \(x=3\). Hence, substituting 3 makes the polynomial equal to 0. Substituting \(-3\) gives \(9(-3)-27=-54\), so it is not a zero. Exam tip: the zero of a linear polynomial \(ax+b\) is \(-\frac{b}{a}\), where \(a\ne0\).
Frequently asked questions
What is the correct answer to this question?
3
Why is this the correct answer?
To find the zero, equate the polynomial to 0: \(9x-27=0\). Thus, \(9x=27\), so \(x=3\). Hence, substituting 3 makes the polynomial equal to 0. Substituting \(-3\) gives \(9(-3)-27=-54\), so it is not a zero. Exam tip: the zero of a linear polynomial \(ax+b\) is \(-\frac{b}{a}\), where \(a\ne0\).
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Introduction to Polynomials. Topic: Linear polynomials.
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