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For which value will ((h-1)x+10) be a linear polynomial?किस मान पर ((h-1)x+10) रेखीय बहुपद होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \(h \ne 1\)\(h \ne 1\)
For \((h-1)x+10\) to be linear, the coefficient of \(x\) must be non-zero. Thus, \(h-1\ne0\), so \(h\ne1\). If \(h=1\), the expression becomes \(10\), which is a constant polynomial, not a linear polynomial. Exam tip: In a linear polynomial, the highest power of the variable is 1 and its coefficient must be non-zero.बहुपद \((h-1)x+10\) रेखीय होने के लिए \(x\) का गुणांक शून्य नहीं होना चाहिए। अतः \(h-1\ne0\), यानी \(h\ne1\)। \(h=1\) पर व्यंजक केवल \(10\) रह जाता है, जो एक स्थिर बहुपद है, रेखीय नहीं। परीक्षा टिप: रेखीय बहुपद में चर की उच्चतम घात 1 और उसका गुणांक अशून्य होता है।
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