Class 9 Mathematics - Sequences and Progressions - Geometric Progression Expert Quiz

Mathematics Sequences and Progressions Geometric Progression Expert Class 9 Level 42

Level 42 • 3/50 questions • 25 seconds per question.

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This level needs 47 more active questions. Admin panel me same class, subject, difficulty aur level_no 42 par question add karein.
Question 1 / 3 0 score
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Question 1/3 Expert Mathematics Sequences and Progressions Sequences Class 9 Level 42

अनुक्रम \(3,-6,12,-24,\ldots\) में (9)वाँ पद क्या होगा?

What will be the (9)th term in the sequence \(3,-6,12,-24,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (768)

Step 1

Concept

The general term is (3(-2)^{n-1}), so (a_9=3(-2)8=768). Exam tip: an even power gives a positive sign.

Step 2

Why this answer is correct

The correct answer is C. (768). The general term is (3(-2)^{n-1}), so (a_9=3(-2)8=768). Exam tip: an even power gives a positive sign.

Step 3

Exam Tip

सामान्य पद (3(-2)^{n-1}) है इसलिए (a_9=3(-2)8=768) है। सम घात पर चिह्न धनात्मक होता है।

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Question 2/3 Expert Mathematics Sequences and Progressions Sequences Class 9 Level 42

अनुक्रम \(3,9,27,81,\ldots\) के पहले (4) पदों का योग क्या है?

What is the sum of the first (4) terms of the sequence \(3,9,27,81,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (120)

Step 1

Concept

The sum is (3+9+27+81=120). Exam tip: direct addition is safest for a small number of terms.

Step 2

Why this answer is correct

The correct answer is C. (120). The sum is (3+9+27+81=120). Exam tip: direct addition is safest for a small number of terms.

Step 3

Exam Tip

योग (3+9+27+81=120) है। छोटे पदों वाले योग में सीधे जोड़ना सबसे सुरक्षित है।

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Question 3/3 Expert Mathematics Sequences and Progressions Sequences Class 9 Level 42

अनुक्रम \(2,4,8,16,32,64,\ldots\) के पहले (6) पदों का औसत क्या है?

What is the average of the first (6) terms of the sequence \(2,4,8,16,32,64,\ldots\)?

Explanation opens after your attempt
Correct Answer

C. (21)

Step 1

Concept

The sum of the first (6) terms is (126), and the average is \(\frac{126}{6}=21\). Exam tip: divide the sum by the number of terms.

Step 2

Why this answer is correct

The correct answer is C. (21). The sum of the first (6) terms is (126), and the average is \(\frac{126}{6}=21\). Exam tip: divide the sum by the number of terms.

Step 3

Exam Tip

पहले (6) पदों का योग (126) है और औसत \(\frac{126}{6}=21\) है। औसत में योग को पदों की संख्या से भाग दें।

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