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If (a_1=2) and (a_{n+1}=3a_n-1), what will be the value of (a_5)?

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Answer and explanation

Correct answer: 122

Apply the recurrence step by step: \(a_2=3(2)-1=5\), \(a_3=3(5)-1=14\), and \(a_4=3(14)-1=41\). Therefore, \(a_5=3(41)-1=122\). The value 116 can result from an error in multiplication or subtraction in the final step. Exam tip: write each intermediate term before finding the required term.

Related tags

SequencesRecurrence RelationsRecursive SequenceClass 9 MathematicsProgressions

Frequently asked questions

What is the correct answer to this question?

122

Why is this the correct answer?

Apply the recurrence step by step: \(a_2=3(2)-1=5\), \(a_3=3(5)-1=14\), and \(a_4=3(14)-1=41\). Therefore, \(a_5=3(41)-1=122\). The value 116 can result from an error in multiplication or subtraction in the final step. Exam tip: write each intermediate term before finding the required term.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Sequences and Progressions. Topic: Sequences.

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