Practice focused topic-wise MCQs with answers and explanations for quick revision and exam preparation.
Difficulty select karke sirf is topic ke focused MCQs practice karein. Score, timer aur explanations student-friendly flow me milenge.
Showing 201-210 of 600 questions.
What is the vertex of the graph of (f(x)=|x-5|-2)?
A. ((5,-2))
(|x-5|) शून्य (x=5) पर होता है और बाहर (-2) जुड़ता है। इसलिए शीर्ष ((5,-2)) है। / (|x-5|) becomes zero at (x=5), and (-2) is added outside. So the vertex is ((5,-2)).
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What is the minimum value of (f(x)=|2x+4|+1)?
A. (1)
मापांक का न्यूनतम मान (0) होता है। इसलिए (|2x+4|+1) का न्यूनतम मान (1) है। / The minimum value of a modulus is (0). Therefore the minimum value of (|2x+4|+1) is (1).
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At which (x)-value is the vertex of (f(x)=|3x-9|)?
A. (x=3)
शीर्ष तब मिलता है जब (3x-9=0)। इससे (x=3) मिलता है। / The vertex occurs when (3x-9=0). This gives (x=3).
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What are the (x)-intercepts of (f(x)=2|x+2|-6)?
A. (x=1) और (x=-5)(x=1) and (x=-5)
(2|x+2|-6=0) से (|x+2|=3) मिलता है। इसलिए (x=1) और (x=-5) हैं। / From (2|x+2|-6=0), we get (|x+2|=3). So (x=1) and (x=-5).
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What is the maximum value of (f(x)=-|x-1|+4)?
A. (4)
क्योंकि \(|x-1|\ge 0\), इसलिए \(-|x-1|+4\le 4\)। अधिकतम मान (4) (x=1) पर मिलता है। / Since \(|x-1|\ge 0\), \(-|x-1|+4\le 4\). The maximum value (4) occurs at (x=1).
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What is the value of (f(x)=|x-2|+|x-6|) at (x=4)?
A. (4)
(f(4)=|2|+|-2|=2+2=4)। मापांक के दोनों भाग अलग से निकालें। / (f(4)=|2|+|-2|=2+2=4). Evaluate both modulus parts separately.
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What is the value of (f(x)=|x+4|-|x-2|) at (x=-1)?
A. (0)
(f(-1)=|3|-|-3|=3-3=0)। चिन्ह बदलने से पहले मापांक का मान लें। / (f(-1)=|3|-|-3|=3-3=0). Take the modulus values before subtracting.
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What are the (x)-intercepts of (f(x)=3(x-1)2-12)?
A. (x=-1) और (x=3)(x=-1) and (x=3)
(3(x-1)2-12=0) से ((x-1)2=4) मिलता है। इसलिए (x=-1) और (x=3) हैं। / From (3(x-1)2-12=0), we get ((x-1)2=4). So (x=-1) and (x=3).
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What are the zeros of (f(x)=x-2+8x+15)?
A. (x=-3) और (x=-5)(x=-3) and (x=-5)
(x-2+8x+15=(x+3)(x+5))। इसलिए शून्यक (x=-3) और (x=-5) हैं। / (x-2+8x+15=(x+3)(x+5)). Therefore the zeros are (x=-3) and (x=-5).
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What is the axis of symmetry of (f(x)=x-2-10x+21)?
A. (x=5)
सममिति अक्ष \(x=-\frac{b}{2a}\) होता है। यहां (a=1) और (b=-10), इसलिए (x=5)। / The axis of symmetry is \(x=-\frac{b}{2a}\). Here (a=1) and (b=-10), so (x=5).
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